Hi all,
I have two results proved in Lean: an upper bound with 1771/3456 in place of 43/80, and lower bounds for n = 8 to 14. Neither uses
native_decide, and the theorems depend on the three standard axioms only.
Upper boundIn Jay's thread I gave 1771/3456 = 0.5124 as a claim to be checked. It is now proved: Jay's bound holds with 1771/3456 in place of 43/80 = 0.5375, and the finite version holds from n = 13 on. The proof is Jay's, applied to the selection with only full and short slices from that post, and the statements use the definitions of his
Challenge.lean. For n >= 14 there are no explicit words, so the bound is new there:
n = 14: 93,907,379,760 -> 93,905,309,790 (-2,069,970)
n = 15: 1,401,355,309,200 -> 1,401,331,300,446 (-24,008,754)The numbers on the left are the best values of Jay's finite bound.
Lower boundsThese are built on Xiaolong Liu's library. The first is
L(n) >= n! + (n-1)! + (n-2)! + n - 3 + ceil( 2((n-2)! - (n-2)) / (n^2 - 4n + 1) ) for n >= 7.
Cole Fritsch proposed this formula here in January 2020. In September Jay announced a Lean proof of a bound that gives the same integers up to n = 14, together with a sharper table. My proof goes through the deficit-one lemma from Marin Kisic's note of August.
The formula rests on an inequality between the number of pieces of a chain and its deficit. For each n from 8 to 14 a finite search shows that a stronger inequality holds, and the Lean kernel runs that search: 827,022 states for n = 8 and fewer than 30,000 for each of the others. The results:
n before (Lean) now change Jay (announced)
8 46,130 46,133 +3 46,130
9 408,418 408,469 +51 408,468
10 4,033,080 4,033,378 +298 4,033,374
11 43,916,235 43,917,903 +1,668 43,917,903
12 522,610,764 522,622,378 +11,614 522,622,378
13 6,746,523,219 6,746,626,957 +103,738 6,746,626,519
14 93,890,256,441 93,891,141,008 +884,567 -The column "before" is William Echols's 46,130 for n = 8 and Xiaolong Liu's bounds for the others. The table starts at n = 8 because for n = 7 the formula gives 5,895 and Justin Lebar's 5,898 is higher.
The last column is Jay's table. He announced it before I had any of these bounds. I haven't seen his proofs, so I don't know how much mine have in common with them. I'd be glad to compare once they are out.
Everything is at
https://github.com/jhalfar/superpermutations in
proofs/lean, and the READMEs there say how each proof goes. The same directory has a command that checks a word in the Lean kernel. My words of 4,034,855, 43,930,578 and 522,737,175 letters are checked that way.
Best,
Jakub