I like these $159.99 500 W Chinese grid-tie inverters
http://www.amazon.com/Small-Inverter-Converter-24-52v-90v-130v/dp/B005N2B0C2/ref=sr_1_1?ie=UTF8&qid=1331847121&sr=8-1
The least expensive PVs I've found so far are AUO panels which make
240 watts at 44 C in 1kW/m^2 sun with a 14.4% efficiency and a -0.44%
power tempco and an 80 C max operating temp, for $1.28/Wp, including
shipping. I'd like to raise their output to at least 250 watts so 2
panels can drive a 500 watt inverter. I could lay them flat on the
north edge of a deck and lay a piece of greenhouse poly film on top to
make a shallow water trough. At my 40 N lat, 6/21 beam sun at noon has
a 90-40+23.7 = 73.5 degree elevation.
In July, Phila has an average 0.0133 outdoor humidity ratio, with Pa =
29.921/(0.62198/0.0133-1) = 0.654 "Hg. At the wet bulb temp, Bowen's
1926 equation says 100(Pw-Pa)/(Twb-Td) = -1, ie Twb = 9621/(22.47-
ln(Td-Twb+100Pa) = 9621/(22.47-ln(606.8-Twb), with Td = 460+81.4 R and
Twb (R). Plugging in Twb = 70 F (530 R) on the right makes Twb = 530.7
on the left. Repeating makes Twb = 530.4, then 530.5 R, ie 70.5 F or
19.2 C, so the panel output would increase by 100(46-19.2)0.0044 =
11.8% if cooled at the wet bulb temp, eg 240x1.118 = 268 watts under 1
kW/m^2 sun.
How tall should the reflector be to make 250 watts per panel at noon
on 6/21? If P = (800+1.9h800)268/1000 = 214(1+0.9h) with h in meters,
h = 0.0052P-0.9 meters, eg 0.39 meters for 250 watts or 0.826 for 333
watts. A 4' (1.22 m) reflector would make 450 watts peak, or 2.7 real
kW for 6 panels, enough for 4 or 5 $159.99 500 W grid tie inverters.
They have overcurrent protection, so they probably don't mind
overdriving.
With 5 inverters, this system would cost about $2638.60/2.5kW = $1.06
per real peak watt.
I see 240 watt panels at 80 cents/watt at
http://www.soldist.com/clearance/
Nick