Teasemaster
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to Sunday Times Teaser Solutions
Cubes which divide by 9 up to (9870-0789 = 9081) are 27, 216, 729,
1728, 3375, 5832
These must be expressible as 999(a-d)+90(b-c) which gives:
cube = 729, (a-d) = 1, (b-c) =+/-3
or 1728, (a-d) = 2, (b-c) =+/-3
The number so generated must divide by 4 (to produce an integer
average)
This gives us (1,3 condition):
1520, 1740, 1960, 2631, 2851, 3742, 3962, 4853, 5304, 5964, 6415,
7306, 7526, 8417, 8637, 9308, 9528, 9748
The only one where where the sum and average do not repeat digits is:
(number) 8417, (sum) 20, (ave) 5, (cubert diff) 10.8
BUT if (1,-3)
(number) 8147, (sum) 20, (ave) 5, (cubert diff) 9
I didn't check the (2,+/-3) condition
TM