Fwd: numbers

[pooja talwar]

---------- Forwarded message ----------
From: pooja talwar <poojatalw...@gmail.com>
Date: Thu, 30 Jan 2014 18:41:53 +0530
Subject:
To: suii_generis <suii_g...@googlegroups.com>

Ques: If N=1+2+2+3+3+3+4+4+4+4+4+....................(n+n+n+n+n+...........n
times), then the value of N will be

A) n*n
B) n*n*n*n*n
C) [2{n(n+1)}\2]
D) n\6(n+1)(2n+1)


Ans is D)

[Abhilash Chandra]

N=1*1+2*2+3*3................=sum of n^2 = option D

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[pooja talwar]

---------- Forwarded message ----------
From: pooja talwar <poojatalw...@gmail.com>
Date: Thu, 30 Jan 2014 18:36:56 +0530
Subject:
To: suii_generis <suii_g...@googlegroups.com>

ques: Find the number of numbers less than 2^14 and co-prime to it.

A) 2^12
B) 2^22
C) 2^23
D) 2^13


Ans is D) 2^13

[Abhilash Chandra]

its a formula...2^(n-1)

[pooja talwar]

its n^n not n^2 so how D?

[Abhilash Chandra]

its "+"...so 3+3+3=3*3

4+4+4+4= 4*4

[pooja talwar]

ok i got it.

[abhishek chakrobrotty]

i guess the answer is n\6(n+1)(n+1)..??

Can any1 xplain how is it D?

[pooja talwar]

Its the standard formula of n^2.