prblm

[Neha Sinha]

Hi everyone, 

plz give me the solution of ques no 1.

With Regards,

Neha Sinha

MBA-International Business (IIIrd Sem)

FMS, BHU

mail to- nhsi...@gmail.com

[harshit gupta]

2 i Think
Is it ryt?

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[Ankit Kanaujiya]

4

[Neha Sinha]

plz give the ans with detail solution

With Regards,

Neha Sinha

MBA-International Business (IIIrd Sem)

FMS, BHU

mail to- nhsi...@gmail.com

[Ujjwal mishra]

For a numbe to be divisible by 99 it should be divisible by both  9 and.

Since it has 1 to 9 all digits hence it is divisible by 9.as its sum is 45 which is divisible by 9.

Now let us suppose digits be abcdefghi

divisible by 11 means is (a+c+e+g+i)-(b+d+f+h) is divisible by 11

(5+2+3+1+6)-(4+7+8+9)= 11 which is divisible by 11

So number is 542738196

But there are more such number exists.

(7+5+6+2+8)-(1+3+4+9) = 28-17 which is divisible by 11

so the number is 715364298
..
Also
541728396
152738596 etc...
So ambiguous to answer.