Hi,
This is regarding a question in DI.
The weights of each of the five members is a, b, c,d, e is a distinct integer.
The sum of the weights of the group of 3 individuals are
106,116,122,126,132,146,120,126,136 and 142.
It is known that weight of a is the average of b and e.
And e is heavier than c but lighter than d.
Find their individual weights.
In the solution they found the sum of the weights to be sum of the above mentioned 10 groups divided by 6.
Why?
Thanks and Regards
Sahil Mehta
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