Pregression

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abhishek chakrobrotty

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Feb 14, 2014, 11:02:33 AM2/14/14
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In the series 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ..... Find the 2014th Term.

Deepesh Arora

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Feb 14, 2014, 11:28:22 AM2/14/14
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63



On Fri, Feb 14, 2014 at 9:32 PM, abhishek chakrobrotty <choc...@gmail.com> wrote:

In the series 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ..... Find the 2014th Term.

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With  Regards
Deepesh Arora

abhishek chakrobrotty

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Feb 14, 2014, 11:30:08 AM2/14/14
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ya ..rite ..can u xplain how ??
Thanks in advance :)

Shubham Jain

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Feb 14, 2014, 11:34:00 AM2/14/14
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(n)*(n+1)/2 should be less than or equal to 2014 so that we can get the nearest value...
using this we get n= 62...
so 62 will come upto 1953 term..so 63 will come upto 2016.. hence 63

abhishek chakrobrotty

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Feb 14, 2014, 11:40:49 AM2/14/14
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yeah rite...thansk :)
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