Redefining the model

[Roy Jacobs]

Hi,

this topic has come up a few times in the archives, but I never saw an
actual answer:

Let's say I have a strongly-typed view. I like this, because stuff
like MvcContrib Html Helpers use the model so that I can do stuff
like: this.Input(x => x.Name); and so on.

In this view, I am using a number of partials. The partial is also
strongly typed, so that I can continue using the HtmlHelpers etc.

However, Spark doesn't allow me to redefine the model in a partial,
and therefore I need to render this partial through the controller
somehow. Currently I am using an ajax request for this, but that is
clearly not ideal.

So my question is:
Is there some way to render a strongly-typed partial from a strongly-
typed view?

And, if I still need to go through the controller somehow:
Can I call a controller action from Spark without needing an ajax
request?

Thanks,
Roy

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[Adam Schroder]

It will if u call #RenderPartial()

[Roy Jacobs]

Ah, naturally! I don't know why I was ignoring the regularly available
rendering methods.

On May 20, 10:14 am, Adam Schroder <adamschro...@gmail.com> wrote:
> It will if u call #RenderPartial()