Is probability a function of k'th occasion

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ravishankar.cws

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May 19, 2015, 6:16:13 AM5/19/15
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In the help file provided with SPACECAP, detection probability is considered as a function of i, j and k (p(i, j, k)), while the right handside of the equation depends only on
(i and j). From what I have understood, detection probability is independent of k. I would like to know if  k indeed plays a role in the computation of probability.

Arjun Gopalaswamy

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May 19, 2015, 8:44:26 AM5/19/15
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Dear Ravishankar:

The k is actually put to define a restricted sampling period of one unit. If this restriction is not present, then it would imply “all occasions” in which case the detection probability will increase.

But you are right in the sense that for a given sampling occasion detection probability does not depend on k.

Does that help?

Arjun



On 19/05/2015 11:16, "ravishankar.cws" <ravisha...@gmail.com> wrote:

ravishankar.cws

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May 19, 2015, 9:08:36 AM5/19/15
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Dear Arjun

Thanks a lot for the clarification. I got it. I was actually confused with the usage of P(i, j, k) in the equation rather than P(i, j) as
I was trying to see P as a function and found that the variable k was redundant in the expression. I understand that P(i,j) corresponds to the detection probability for any k'th sampling unit.

regards
ravi
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