How to get the Path of an InputFile in a Sensor? version 6.7

[xti...@gmail.com]

Hello fellows,

I am migrating a existing plugin that works for Sonarqube 5.6 to 6.7.1.

in order to handle the files  in a Sensor I used:

for (InputFile file : context.fileSystem()

                .inputFiles(context.fileSystem().predicates().hasLanguage("cs"))) {            

            Path fileInSonar = Paths.get(file.file().getPath());

            // code that process the file....where the magic happens

        }

I just found that the method file(), as well as the absolutePath() and relativePath() methods has been deprecated.

what is the option to have the path of the file?

[Julien HENRY]

Hi,

Those methods were deprecated in an attempt to encourage Sensors to not rely on local filesystem to read file content, but instead use provided content() or inputStream() methods.

Can you share why you need to get the Path of the file?

++

Julien

[xti...@gmail.com]

Hi Julien,

As you pointed the methods content() or the inputStream() will fit if you need to read file content, but that is not my intention.

I need the path (relative or absolute) because I am using an external tool to generate some metrics, that tool creates an XML report, where all the files analyzed are included and distinguished by its path; As I have several files with the same name but in different folders I need to filter by its path, take the information regarding that file, parse it and save it into Sonarqube.

thanks.

Xtian

[Julien HENRY]

Hi Xtian,

The correct way would be to use InputFile::uri() to build a Path: Paths.get(inputFile.uri()). On scanner side you are guaranteed this uri will always be a file:// (which is not true on SonarLint for example).

++

Julien Henry | SonarSource

Developer

https://sonarsource.com

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[xti...@gmail.com]

Thanks a lot!!!