More of my philosophy of if i can do math..

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Hello...


More of my philosophy of if i can do math..

Archimedes Plutonium just written:
>In fact we do not know if Amine can do any math


So you are asking if i can do math?

Yes i can do math, and here is my logical proof of it, you can
read my following thoughts of how i can do math:

About Markov chains in mathematics and more..

In mathematics, many Markov chains automatically find their own way to
an equilibrium distribution as the chain wanders through time. This
happens for many Markov chains, but not all. I will talk about the
conditions required for the chain to find its way to an equilibrium
distribution.

If in mathematics we give a Markov chain on a finite state space and
asks if it converges to an equilibrium distribution as t goes to
infinity. An equilibrium distribution will always exist for a finite
state space. But you need to check whether the chain is irreducible and
aperiodic. If so, it will converge to equilibrium. If the chain is
irreducible but periodic, it cannot converge to an equilibrium
distribution that is independent of start state. If the chain is
reducible, it may or may not converge.

So i will give an example:

Suppose that for the course you are currently taking there are two
volumes on the market and represent them by A and B. Suppose further
that the probability that a teacher using volume A keeps the same volume
next year is 0.4 and the probability that it will change for volume B
is 0.6. Furthermore the probability that a professor using B this
year changes to next year for A is 0.2 and the probability that it
again uses volume B is 0.8. We notice that the matrix of transition is:

|0.4 0.6|
| |
|0.2 0.8|

The interesting question for any businessman is whether his
market share will stabilize over time. In other words, does it exist
a probability vector (t1, t2) such that:

(t1, t2) * (transition matrix above) = (t1, t2) [1]

So notice that the transition matrix above is irreducible and aperiodic,
so it will converge to an equilibrum distribution that is (t1, t2) that
i will mathematically find, so the system of equations of [1] above is:

0.4 * t1 + 0.2 * t2 = t1
0.6 * t1 + 0.8 * t2 = t2

this gives:

-0.6 * t1 + 0.2 * t2 = 0
0.6 * t1 - 0.2 * t2 = 0

But we know that (t1, t2) is a vector of probability, so we have:

t1 + t2 = 1

So we have to solve the following system of equations:

t1 + t2 = 1
0.6 * t1 - 0.2 * t2 = 0

So i have just solved it with R, and this gives the vector:

(0.25,0.75)

Which means that in the long term, volume A will grab 25% of the market
while volume B will grab 75% of the market unless the advertising
campaign does change the probabilities of transition.


Thank you,
Amine Moulay Ramdane.