Q2) 5 aug

[suv]

Q2)
The number of zeros at the end of (5^200 – 1) ! is

Ans:(5^200 - 801)/4

plz explain..

[JATIN GUPTA]

I think the answer gives us the hint here that the power of 5 should be the same..

for eg:

To find number of zeros in:

(5^2-1)! can be written as {5^2 - (5+(4*1))}/4(i.e 4)

(5^3-1)! can be written as {5^3 - (5+(4*2))}/4(i.e 24)

...........

..........

general solution is (5^x -1)! will have {5^x - (5 + (4*(x-1))}/4 zeros..

 

so rather than starting from the question we should go by the option for this question..   

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Regards,
Suvrit Chadha

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Regards,
Jatin Gupta

[suv]

k..

On Aug 6, 8:24 am, JATIN GUPTA <jatin....@gmail.com> wrote:
> I think the answer gives us the hint here that the power of 5 should be the
> same..
> for eg:
> To find number of zeros in:
> (5^2-1)! can be written as {5^2 - (5+(4*1))}/4(i.e 4)
> (5^3-1)! can be written as {5^3 - (5+(4*2))}/4(i.e 24)
> ...........
> ..........
> general solution is (5^x -1)! will have {5^x - (5 + (4*(x-1))}/4 zeros..
>
> so rather than starting from the question we should go by the option for
> this question..
>
> On 5 August 2010 17:01, suv <suv...@gmail.com> wrote:
>
>
>
>
>
> > Q2)
> > The number of zeros at the end of (5^200 – 1) ! is
>
> > Ans:(5^200 - 801)/4
>
> > plz explain..
>
> > --
> > You received this message because you are subscribed to the Google
> > Groups "Simple fundas" group.
> > To post to this group, send email to simple...@googlegroups.com
> > To unsubscribe from this group, send email to

> > simple-funda...@googlegroups.com<simple-fundas%2Bunsubscribe@goog­legroups.com>

> > For more options, visit this group at
> >http://groups.google.co.in/group/simple-fundas?hl=en-GB
>
> > Regards,
> > Suvrit Chadha
>
> --
> Regards,

> Jatin Gupta- Hide quoted text -
>
> - Show quoted text -

[Rohan Aggarwal]

yeah thats the way to do it :) good one jatin :)

[JATIN GUPTA]

thx..:)

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Regards,
Jatin Gupta