DI-set

[suv]

Four people P, Q, R and S share forty coins of 25 paise, 50 paise, Re.
1 and Rs.2 denomination. The value of the total coins is 37 rupees.

The money (in Rupees) each person got is an integer and each person
got a different amount. The value of the two rupees coins is 24
rupees. There are equal number of one rupee and 50 paise coins. Each
person gets at least one coin of each denomination. The total amount R
got is Rs.10. P got six 25 paise coins and three one rupee coins. Q
got two 50 paise coins.

The number of coins with S is equal to the amount (in rupees) with
him. For each denomination, at least two members got equal number of
coins. S got equal number of 25 paise and 2 rupee coins. R got four 2
rupee coins.

Q)The total number of coins with S is
9,10,11,12

Q)

If the amount with Q is more than that with P, then the amount with Q
is (in rupees)
6,7,8,9

Q)The maximum possible number of coins that P can have is
11,12,13,14

happy solving :P

[Ankur Rustagi]

Answers are:

 

11

9

13

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Regards,
Suvrit Chadha

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Regards
Ankur Rustagi
+91-9899 210 851

[siddhant gupta]

11,9,13

[Rohan Aggarwal]

yo 11,9,13 is correct