@rohan
I tried to solve the problem,but I got a contradiction
Let the dierect routes from A to B, B to C,C to D be x,y,z resp.
Total num of routes from B to C= dierect routes(B to C)+indierect
routes(B-C-A).
therefore,
indierect routes= 33-x----------------->>>>>>>eq1
now, No of a-c-b=>>dierct routes A to C+ dierct routes C to B;
hence
33-x=y+z
33=x+y+z;
Similarly,
Total num of routes from B to C= dierect routes(B to C)+indierect
routes(b-a-c).
therefore,
indierect routes= 23-x----------------->>>>>>>eq2
now, No of b-a-c=>>dierct routes B to A+ dierct routes A to C;
hence
23-x=y+z
23=x+y+z;
The contradiction
where am i going wrong???