Fw: QA

[vik...@gmail.com]

Options

A 3*10^6
B 4*10^6
C 6*10^6
D 2*10^6
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-----Original Message-----
From: vik...@gmail.com
Date: Thu, 12 Aug 2010 10:36:32
To: <simple...@googlegroups.com>
Reply-To: vik...@gmail.com
Subject: QA


Can some 1 provide soln to dis ??

Find the remainder when 25! is divided by 10^7 .

A 3*10^6
B 3*10^6
C
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[suvrit chadha]

4*10^6

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Regards,
Suvrit Chadha

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Kind Regards,
Suvrit Chadha

[JATIN GUPTA]

6*10^6....

Regards,
Jatin Gupta

[Rohan Aggarwal]

4*10^6

[Rohan Aggarwal]

4*10^6

soln :  25! has 6 zeroes so remainder wil be remainder from 10 of  (25! / 10^6) that is the last digit.. last digit comes out to be 4 as

(1*3*4*6*7*8*9) * (1*3*4*6*7*8*9)*(1*2*3*4)

[last digits of terms in 25!/10^6]  by solving the last digit is 4, and since 10^6 was canceld.. it wil be re multiplied

On Thu, Aug 12, 2010 at 5:38 PM, JATIN GUPTA <jati...@gmail.com> wrote: