another one :)

Rohan

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Jul 31, 2010, 7:58:03 AM7/31/10

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Let n=9999...99 (2009 times). find the sum of digits of n^2

1) 18072
2)18081
3)18082
4)18073
5)18080

saurabh aggarwal

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Jul 31, 2010, 9:40:29 AM7/31/10

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5) 18080

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Regards,
Suvrit Chadha

suv

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Jul 31, 2010, 12:33:30 PM7/31/10

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18081

On Jul 31, 6:40 pm, saurabh aggarwal <coolsaurabh1...@gmail.com>
wrote:
> 5) 18080

>
> On 31 July 2010 17:28, Rohan <jiit.ro...@gmail.com> wrote:
>
> > Let n=9999...99 (2009 times). find the sum of digits of n^2
>
> > 1) 18072
> > 2)18081
> > 3)18082
> > 4)18073
> > 5)18080
>
> > --
> > You received this message because you are subscribed to the Google
> > Groups "Simple fundas" group.
> > To post to this group, send email to simple...@googlegroups.com
> > To unsubscribe from this group, send email to

> > simple-funda...@googlegroups.com<simple-fundas%2Bunsu...@googlegroups.com>

Rohan Aggarwal

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Jul 31, 2010, 12:36:31 PM7/31/10

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18081 is correct :)

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