Hello Everyone!
Let R = Tanh(Integral_{x>=1} ArTanh((1 - T(x)) / (1 + T(x)))dx) = 0.930679...
where T(x) = Zeta(2x) / Zeta(x)^2. The constant R is related to
Whereas S = Integral_{x>=1} PrimeZeta(x)dx = 1.6366...
More generally, for a constant c >= 1,
S_c = Sum_{p prime} 1/(p^c log p) =
= Integral_{x>=c} PrimeZeta(x)dx.
For what c, S_c = R ?
Best,
Tom Ordo
____________