Re: How to handle random Xpath

[Arran]

What is "random" about it?

On Wednesday, 29 May 2013 12:41:30 UTC+1, Rashmi Singh wrote:

Hi All


The problem is that I want to click the Add button of supplied in PrependedInput.


   driver.FindElement(By.Id("prependedInput")).SendKeys("Chetan8");
   driver.FindElement(By.XPath("//li[3]/a/button")).Click();

[Avikash Gorka]

what i understood is that you are searching any user by entering initial few letters of the user in the search textbox. Then some users, would pop put in this form

<UI>

        <Li>

        <Li>

        <Li>

</Ul>

In this case us must know the exact user name which you want to search or atleast that upto that part where you can uniquely identify the user. Depending the name of the user, you would be able to  li using xpath and subsequently add button of that li.

Thanks & Regards,

Avikash Gorka

Sr Test Engineer

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[sridhar ..]

Hi ,

Take common xpath and put it in list.

My situtaion:

Q)xpath will change dynamically so,followed below process

id=automation-1234

id=automation-5634

id=automation-8254

id=automation-6789

id=automation-7543

id=automation-2478

List<webelemtnt> list=driver.findelements(By.xpath(.//div[@starts-with(@id,"automation")])

if you want to second automation 

list.get(1)

Hop it would help you

Regards

Siddu