Initialize WebElement for dynamic XPath

[Karthik]

XPATH's are defined by the end user. I just enabling the automation to them. Even I don't know which XPATH type will come (like name,id,xpath, css). 

Is this right way to initialize web element for dynamic XPATH like below?

public WebElement initWebElement(String xpath) {

WebElement webElement = null;

try {

if (xpath.startsWith("//") || xpath.startsWith("(//")) {

webElement = webDriver.findElement(By.xpath(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.id(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.name(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.cssSelector(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.linkText(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.partialLinkText(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.className(xpath));
}

if (webElement == null) {

webElement = webDriver.findElement(By.tagName(xpath));
}

} catch (Exception e) {
e.printStackTrace();
}

return webElement;
}

[Chetan Baraskar]

Hi Karthik,

 

Anyhow the end user will define only xpath, so there is no point in searching By (classname, id, linktext)

Rather you can check the xpath is valid by using below logic

 

Functions below will returns webelement, by verifying user define xpath is valid.

public Webelement getobject( String userxpath)

{

          List<Webelement> e= driver.findelements(By.xpath(“userxpath”)

          if(e.size()>0)

{

                    return e;

          }

else

{

          System.out.println(“Object not present in web page”);

          }

}

 

Regards,

Chetan

 

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[Karthik]

Thank you for the response. They will not give only xpath. It contains css/xpath/id/classname or either other. That means unknown selector type. So that, I created that method. Is it good way to do that? 

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[Joseph Conlin]

Instead of having them pass in a String object and have you try to figure out which kind of By locator they are trying to use, you could have them pass in a By variable that already includes what kind of locator it is.

They would do something like this:
By myVariableName = By.xpath("//*[@id='test']);

By anotherVariableName = By.id("test1");

WebElement myFirstElement = initWebElement(myVariableName);

WebElement anotherWebElement = initWebElement(anotherVariableName);

Your code would look something like this:

public WebElement initWebElement(By locator) {

WebElement webElement = null;

try { 

webElement = webDriver.findElement(locator);