HwanI checked on the runtime information using trace =2 and saw that the initially given interval of [0, d] keep shrinking to some extent. Does it mean the bvp_solver has bugs, or that is what is supposed to be in some particular cases. I will appreciate your thoughts on the problem I described above.I supposed that the resulting mesh points must always spread over the closed interval of [0, 500], and therefore the solver will generate a vector of continuous solution functions on [0, 500]. What puzzled me was that the solver gave a vector of solution functions on an interval of [0, x], where x is less than d. With this problem, The functions are not defined in the interval of (x, d].John,How are you?Recently, I worked on a BVP problem using scikits.bvp_solver. For this problem, I set boundary_points = (0, d), where d = 500.0; see below.
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problem = bvp.ProblemDefinition (
num_ODE = 7,
num_parameters = 0,
num_left_boundary_conditions = 3,
boundary_points = (0, d),
function = patent.dudt,
boundary_conditions = patent.bc )
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Thanks.
Maybe you could post the output trace=2?
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