On Saturday, August 1, 2020 at 6:32:18 PM UTC-6,
prokaryotic.c...@gmail.com wrote:
>
> On Saturday, August 1, 2020 at 5:55:46 PM UTC-5, Gary Harnagel wrote:
> >
> > On Saturday, August 1, 2020 at 11:20:12 AM UTC-6,
prokaryotic.c...@gmail.com wrote:
> > >
> > > Let's look at the Minkowski diagrams that I drew for Wikipedia:
> > >
https://en.wikipedia.org/wiki/Special_relativity#Graphical_representation_of_the_Lorentz_transformation
> > >
> > > In the unprimed frame in Figure 3-1a, infinite speed is represented
> > > by lines parallel to the x-axis.
> > >
> > > In the primed frame in Figure 3-1d, infinite speed is represented
> > > by lines parallel to the x'-axis.
> > >
> > > NEITHER FRAME IS PREFERRED OVER THE OTHER. That is one of
> > > the major sources of confusion that you display in your vixra paper.
> >
> > However, an observer in the primed frame sees infinite speed as horizontal
> > also. And no, I;m not confused, but apparently, YOU are.
>
> I'm snipping the rest of your post, because you need to get this
> ABSOLUTELY MOST BASIC POINT CLEARED UP before you can even HOPE to
> discuss more advanced topics.
>
> ================================================================
>
> A) An infinite speed signal is one that can travel from one point to another
> in the spatial dimension without any advancement in the time dimension.
>
> True or false?
Of course. deltat = L/u. As u approaches infinity, deltat approaches zero.
For deltat > 0, u is less than infinity.
Since you asked me a question and I answered it,, it's only fair that you answer
a question of mine. My question for you is, since deltat > 0 applies to a speed
less than infinite, to what speed does deltat < 0 apply?
> ================================================================
>
> B) For the unprimed observer in Figure 3-1a, the spatial dimension is
> horizontal, and the time dimension is vertical.
>
> True or false?
Of course.
> C) For the unprimed observer in Figure 3-1a, the lines of simultaneity
> are horizontal and parallel with the x axis.
>
> True or false?
Of course.
> D) Therefore, for the unprimed observer in Figure 3-1a, an infinite speed
> signal could be represented by a horizontal arrow which is parallel
> with the x axis.
>
> True or false?
Of course/
> ================================================================
>
> E) For the primed observer in Figure 3-1d, the spatial dimension is
> tilted arctan(0.5) from the horizontal (approx 26.6°), and
> the time dimension is tilted approx -26.6° from the vertical.
>
> True or false?
Of course.
> F) For the primed observer in Figure 3-1d, the lines of simultaneity
> are tilted approx 26.6° from the horizontal and are parallel with
> the x' axis.
>
> True or false?
Of course.
> G) Therefore, for the primed observer in Figure 3-1d, an infinite speed
> signal could be represented by an arrow tilted 26.6° from the
> horizontal which is parallel with the x' axis.
>
> True or false?
Of course.
> ================================================================
>
> In which step, A, B, C, D, E, F, G, do you begin to disagree with
> my interpretation of the Minkowski diagram?
None at all. You see, I DO understand the Minkowski diagram.
> Bonus question
> H) Since you assert, in Figure 3d, that an infinite speed signal must be
> represented by a horizontal arrow, please show me how the primed
> observer can POSSIBLY know what "horizontal" is for an unprimed observer?
That question doesn't even make sense. I did NOT assert that infinite speed
in 3d was a horizontal line. I said the moving observer sees his time
axis as vertical and his space axis as horizontal. It appears that you
chose to misinterpret what I said.
> ================================================================
>
> The problem is that since simultaneity is observer-dependent, "infinite
> speed" also be observer dependent.
> If, as you assert, "infinite speed" is always horizontal in a Minkowski
> diagram, you are in effect asserting the existence of ABSOLUTE SIMULTANEITY.
I did not assert that. I only stated that infinite speed was along the
horizontal axis for the moving observer. That would be the x' axis
in 3d, but the moving observer sees that axis as horizontal.
Now, you are laboring under another misconception which I tried to
point out with MY question. There certainly is something wrong with
downward-sloping velocity vectors. One reason is that deltat < 0
mus apply to a speed GREATER than infinity, which is completely
absurd. So we must not draw them. How do we keep from drawing them?
The relativistic energy equation:
E² = p²c² - (mc²)²
points the way out. Tachyon energy is infinite for u = c and monotonically
falls to zero at u = ∞. As you point out, speed is observer dependent.
The relativistic velocity composition equation must be valid for tachyons
since tachyons are supposed to obey special relativity, and the way that
backward-in-time solutions occur is when the denominator goes negative,
but that means two things: greater than infinite speeds and energies in
some strange region beyond where a tachyon has - no energy at all! But
since to other observers, the tachyon still has positive energy, one can only
conclude that tachyon DETECTION is observer dependent.
And it turns out that observers who would experience causality violations
if they could receive signals, can't. Thus, tachyons don't violate causality.