Re: Riedt?s Trinity of c
eric gisse
> Riedt?s Trinity of c
>
> A light source moves through space in direction LR. The speed of light
> is c, when emitted from the light source perpendicular to the
> direction. It is c' when emitted from the front of the source and c''
> when emitted from the back of the source. This can be proven by a
> three mirror interferometer experiment:
Which would show up just fine in two mirror interferometer experiments. Read
the literature.
[snip rest, unread]
BURT
> Peter Riedt wrote:
> > Riedt?s Trinity of c
>
> > A light source moves through space in direction LR. The speed of light
> > is c,
The speed of light is C in the space frame. You can move behind it in
space.
Mitch Raemsch
Peter Riedt
A light source moves through space in direction LR. The speed of light
is c, when emitted from the light source perpendicular to the
direction. It is c' when emitted from the front of the source and c''
when emitted from the back of the source. This can be proven by a
three mirror interferometer experiment (the dots are placeholders):
...................N>N'
....................^
L>>L'=============B==B'=============R>>R'
direction LR >
..................^
................SOURCE
Mirrors at L, N and R, beam splitter at B. Light from the source is
split at B and travels left to mirror L' and back to B', north to
mirror N' and back to B' (at angles) and right to mirror R' and back
to B'. The three beams merge at B'.
Prediction: The speed of light is c (perpendicular arm), c’ (right
parallel arm) and c'' (left parallel arm), producing a null result (no
fringe shift at B').
Solution
..v = 29805m/sec
..c = 299792458m/sec
.c' = c*1/sqrt(1-vv/cc) = 299792459.4816m/sec = c+1.4816m/sec
c'' = c*1/sqrt(1+vv/cc) = 299792456.5184m/sec = c-1.4816m/sec
..D = BN = BR = BL = 11m
Time tn for light path distance BN'B' = 2D(1+vv/2cc)/c =
22.0000001087250m/299792458.0000m/sec = 0.000000073384101sec
Time tr for light path distance BR'B' = 2D(1+vv/cc)/c' =
22.0000002174501m/299792459.4816m/sec = 0.000000073384101sec
Time tl for light path distance BL'B' = 2D(1-vv/cc)/c'' =
21.9999997825499m/299792456.5184m/sec = 0.000000073384101sec
tn = tr = tl
The formulas for the light path distances BR'B' and BN'B' were given
by Michelson and Morley in the American Journal of Science 203/1887
with the provisos “neglecting terms of the fourth order” and the
formulas having “the same degree of accuracy”. They applied the
formulas in the logic of their 1887 two mirror interferometer
experiment which also produced a null result.
Peter Riedt
Dono.
>
>
> Prediction: The speed of light is c (perpendicular arm), c’ (right
> parallel arm) and c'' (left parallel arm), producing a null result (no
> fringe shift at B').
>
No persistent imbecile, it was already shown to you that that's false
It is equivalent to claiming that :
sqrt(1-(v/c)^2)+sqrt(1+(v/c)^2)=2
You are a cretin.
eric gisse
> Riedt?s Trinity of c
>
> A light source moves through space in direction LR. The speed of light
> is c, when emitted from the light source perpendicular to the
> direction. It is c' when emitted from the front of the source and c''
> when emitted from the back of the source.
c = c' = c'', by observation.
Have you looked at any experiment past 1887?
[snip rest, unread]
BURT
The creation of motion is detectable as acceleration or deceleration.
Mitch Raemsch
BURT
There are factors that throw off our estimation of exact light speed.
One factor is motion that slows the clock of the measuring device
causing light to move faster.
Mitch Raemsch
Peter Riedt
Dono, I am claiming that tn=tr=tl=0.000000073384101sec.
Peter Riedt
Dono.
Peter,
You are an imbecile, according to you :
tr=L/c*sqrt(1-(v/c)^2)
tl=L/c*sqrt(1+(v/c)^2)
tn=L/c
Now, elementary algebra says that your claim is full of shit.
eric gisse
> On Mar 11, 10:27 pm, "Dono." <sa...@comcast.net> wrote:
>> On Mar 11, 6:15 am, Peter Riedt <rie...@yahoo.co.uk> wrote:
>>
>>
>>
>> > Prediction: The speed of light is c (perpendicular arm), c? (right
>> > parallel arm) and c'' (left parallel arm), producing a null result (no
>> > fringe shift at B').
>>
>> No persistent imbecile, it was already shown to you that that's false
>> It is equivalent to claiming that :
>>
>> sqrt(1-(v/c)^2)+sqrt(1+(v/c)^2)=2
>>
>> You are a cretin.
>
> Dono, I am claiming that tn=tr=tl=0.000000073384101sec.
>
> Peter Riedt
No wonder it has taken you fifty years for you to _think_ you figured out
the Michelson-Morley experiment. Basic algebra is hard for you!
BURT
>
> - Show quoted text -
Light is weightless and has the fastest clock.
Mitch Raemsch
GogoJF
This is so true.
Peter Riedt
Dono,
tr = 2D(1+vv/cc)/c' = 0.000000073384101sec
tl = 2D(1-vv/cc)/c'' = 0.000000073384101sec
tn = 2D(1+vv/2cc)/c = 0.000000073384101sec
tn = tr = tl
The calculations are easy and irrefutatable. If you think there is an
incompatibilty
between your algebra and my numbers, maybe you are able to explain it.
Peter Riedt
eric gisse
> On Mar 12, 8:56 am, "Dono." <sa...@comcast.net> wrote:
>> On Mar 11, 4:37 pm, Peter Riedt <rie...@yahoo.co.uk> wrote:
>>
>>
>>
>>
>>
>> > On Mar 11, 10:27 pm, "Dono." <sa...@comcast.net> wrote:
>>
>> > > On Mar 11, 6:15 am, Peter Riedt <rie...@yahoo.co.uk> wrote:
>>
>> > > > Prediction: The speed of light is c (perpendicular arm), c? (right
>> > > > parallel arm) and c'' (left parallel arm), producing a null result
>> > > > (no fringe shift at B').
>>
>> > > No persistent imbecile, it was already shown to you that that's false
>> > > It is equivalent to claiming that :
>>
>> > > sqrt(1-(v/c)^2)+sqrt(1+(v/c)^2)=2
>>
>> > > You are a cretin.
>>
>> > Dono, I am claiming that tn=tr=tl=0.000000073384101sec.
>>
>> > Peter Riedt
>>
>> Peter,
>>
>> You are an imbecile, according to you :
>>
>> tr=L/c*sqrt(1-(v/c)^2)
>> tl=L/c*sqrt(1+(v/c)^2)
>> tn=L/c
>>
>
> Dono,
>
> tr = 2D(1+vv/cc)/c' = 0.000000073384101sec
> tl = 2D(1-vv/cc)/c'' = 0.000000073384101sec
> tn = 2D(1+vv/2cc)/c = 0.000000073384101sec
> tn = tr = tl
>
> The calculations are easy and irrefutatable. If you think there is an
> incompatibilty
> between your algebra and my numbers, maybe you are able to explain it.
>
> Peter Riedt
Holy crap nobody cares. Go away.