It means "turns times winding current" if 40 mA is flowing in a 20000T winding then the current sheet is 800 A so the plasma curent is 800 A. The plasma is generated by the ionisation wire which is excited by 20KV 60KHz power supply.
The ion pressure is 800.800.mu/D/length of winding. But since the current is actually a standing wave them there is a maximum current in the middle and zero at the ends making the pressure a bit quite a bit bigger near the middle. The pressure I calculated as about 10^8Pa and the plasma heats by ohmic heating with the maximun near the middle and near the axis. When the temperature reaches 6KeV (that is about 10^11 K the power reaches its maximum. This is only near the middle and near the axis the insulation is because the ionised gas does not diffuse outward because of the ion pressuree and is kept near the maximum because it is the maximum current. The fusion reactions futher heat the gas and the ions exert pressure on the containment current this inducing more current in the winding. The current density near the centre is very high because the area over which it flowes is about 1mmx6mm so the current density is 800/6E-6 or 8E8A/meter^2.
The copper loss is the resisance of the winding (2000Ohm) and the current (40mA) which is 80 Watt.
The power generated is 0.5 Watt/cc/kPa^2 and with a reaction volume of 18E-2 so the power is 18E-2x0.5x(10E8/1000)^2 or 9E10Watt (90GW). It cannot be run at that power because the current generated is too high for the windings and since this extra current increasss the pressure the power simply rises exponentially until the unit explodes.
THe power is controlled by the shunt regulator by shunting the windings when the potential rises to the preset level.
To make a high power unit the reaction chamber remains the same but the resonance winding is made of insulated copper tube of the same inductance. This will have a smaller number of turns because the winding has a bigger diameter. I do not know how to work the inductance out from the number of turns and dimensions of the winding. You can estimate from the gaussian formula for a single turn coil and after winding, measure the inductance. Then calculate the capacitance for resonance at 50 Hz. Calculate the potential reached at maximum power to estimate the voltage rating of the capacitor and similarly the current rating. To get 50KW at 400 V the current output will be 125A. So the tank circuit must run at about 1250A so only 10% is taken to load. The output winding will have about 400T of 125A wire with the output voltage of 400 volt. To calculate the potential across the tank circuit the turns of the resonance winding need be known. So build the resonace cicuit first and then find the potential it develops at low power (the exciter across the resonance coil) and then measure work out the turns for the output winding.
To reduce the copper loss and cool the winding the copper tube winding needs liquid nitrogen flowing in the tube.
Dr Chris.
Dr Chris
http://www.cs003o327.webspace.virginmedia.com/
I think I made an error in the winding current. If you take the turns ratio and work out the current taken by the output coil (125A) and divide by the turns in the resonance winding and multiply by the output winding turns and then multiply by ten you get the winding current in the resonance coil. With a big number of turns like 20,000 then the winding current will be 25A. So we need a 30 A wire for the winding. AHH that’s better!
I make the resonance winding potential 20,000 volt. I am told a 20KV 30 A 50 Hz capacitor of a few microfarads could be made.
From: Christopher Strevens [mailto:christophe...@hotmail.co.uk]
Posted At: 20 April 2013 21:57
Posted To: sci.physics.fusion
Conversation: 50 KW reactor suggestion
Subject: Re: 50 KW reactor suggestion
I think I made an error in the winding current. If you take the turns ratio and work out the current taken by the output coil (125A) and divide by the turns in the resonance winding and multiply by the output winding turns and then multiply by ten you get the winding current in the resonance coil. With a big number of turns like 20,000 then the winding current will be 25A. So we need a 30 A wire for the winding. AHH that’s better!
From: Christopher Strevens [mailto:christophe...@hotmail.co_1.uk_1]
Posted At: 20 April 2013 15:05
Posted To: sci.physics.fusion
Conversation: 50 KW reactor suggestion
Subject: 50 KW reactor suggestion
It means "turns times winding current" if 40 mA is flowing in a 20000T winding then the current sheet is 800 A so the plasma curent is 800 A. The plasma is generated by the ionisation wire which is excited by 20KV 60KHz power supply.
The current sheet is 600,000A so the plasma current is 600,000A.
From: Christopher Strevens [mailto:christophe...@hotmail.co.uk]
Posted At: 20 April 2013 22:19
Posted To: sci.physics.fusion
Conversation: 50 KW reactor suggestion
Subject: Re: 50 KW reactor suggestion
I make the resonance winding potential 20,000 volt. I am told a 20KV 30 A 50 Hz capacitor of a few microfarads could be made.
From: Christopher Strevens [mailto:christophe...@hotmail.co.uk]
Posted At: 20 April 2013 21:57
Posted To: sci.physics.fusion
Conversation: 50 KW reactor suggestion
Subject: Re: 50 KW reactor suggestion
I think I made an error in the winding current. If you take the turns ratio and work out the current taken by the output coil (125A) and divide by the turns in the resonance winding and multiply by the output winding turns and then multiply by ten you get the winding current in the resonance coil. With a big number of turns like 20,000 then the winding current will be 25A. So we need a 30 A wire for the winding. AHH that’s better!
From: Christopher Strevens [mailto:christophe...@hotmail.co_1.uk_1]
Posted At: 20 April 2013 15:05
Posted To: sci.physics.fusion
Conversation: 50 KW reactor suggestion
Subject: 50 KW reactor suggestion
It means "turns times winding current" if 40 mA is flowing in a 20000T winding then the current sheet is 800 A so the plasma curent is 800 A. The plasma is generated by the ionisation wire which is excited by 20KV 60KHz power supply.