fusion using a tesla coil

[Chris]

As applied to fusion in tesla coil
Calculation of pressure required at various potential gradients
Mean Free Path
Vacuum rangePressure in hPa (mbar)Molecules / cm3Molecules m-3mean free path
Ambient pressure10132.7*10192.7*102568 nm
Low vacuum300-11019-10161025-10220.1-100 ?m
Medium vacuum1-10-31016-10131022-10190.1-100 mm
High vacuum10-3-10-71013-1091019-101510 cm-1 km
Ultra high vacuum10-7-10-12109-1041015-10101 km-105 km
Extremely high vacuum<10-12<104<1010>105 km

>From Wikipedia
The energy required to ionise hydrogen is about 40 electron-volts so for a
potential of ten volts over 4 cm (2500 V/m) a path of 16 cm is needed to
obtain a high enough energy to ionise the gas. That gives a pressure of 1E-4
mbar. At this pressure the free proton would have up to 2500 eV so the
temperature is 2.5 KeV. This is enough to cause a few fusion reactions and
with the exponential tail of the free path distribution energies of 100 KeV
or 3000 KeV (3E10K) would occur making proton-proton and D-D reactions
possible. Since these reactions increase the temperature this is expected to
rapidly rise. These potentials were reached in coil of the 10 volt
oscillator.
For higher pressures such 3 Tor the mean free path is 100E-6m (=1E-4m) so
the potential would be 400 KV/m. With a mean free path of 1 Km a mean energy
of 400 MeV. This would also be the mean energy of the protons making a
temperature of 400 MeV or (at 8.617 343E-5/K) 4E12 K. This would be expected
in a Tesla coil.