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Einstein's Gravity is Emergent

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Jack Sarfatti

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Jan 27, 2006, 12:33:39 AM1/27/06

I think I have derived at least Einstein's classical GR vacuum equation
as an emergent Goldstone phase modulation.

I assume a Planck-scale emergence where the degenerate vacuum manifold

G/H ~ S2

So there are 2 independent local Goldstone phase coherent fields theta & phi

I define the invariant 1-form

B = (dtheta)/\(phi) - (theta)/\(dphi)

so that

dB = 2(dtheta)/\(dphi) =/= 0

d^2B = 0 locally

The invariant Einstein-Cartan 1-form is

e = 1 + B

where

e = eudx^u

eu = eu^a&a

Einstein's symmetric metric tensor is by the equivalence principle

guv = eu^a(Minkowski)abev^b

Note the nonlinear terms ~ B^2.

The spin connection is the 1-form W^a^b = Wu^a^bdx^u

The exterior covariant derivative is

D = d + W/\

Zero torsion means

De = 0

Therefore

W = -*[dB/\(1 - B)]

* is the Hodge dual

The curvature 2-form is

R = DW = dW + W/\W

i.e.

R^a^b = DW^a^b + Wa^c/\Wc^b

The Bianchi identities are

DR = 0

Define

The vacuum equation is the 1-form equation

*(R/\e) + *(Lambda/\e/\e/\e) = 0

brian a m stuckless

unread,

Jan 27, 2006, 6:31:12 AM1/27/06

$$ [MORE h*fL EMiTTER & RECiEVER equations @ item 2.]; SPEEDO.wpd.
Re: the speed of electron; Mon, 16 Jan 2006 20:14:10
Tom Roberts wrote: > double precision wrote: > big magician wrote:
> >>> does anyone knows the speed of the accelerated deviated
> >>> electrons in a crt?
> >> The accelerating voltage of a typical CRT is about 15 kV, so the
> >> kinetic nergy of an electron when it hits the screen is about 15
> >> keV; it therefore has v/c ~ 0.03. -=- I see I made a mistake.
> >> Sorry. I use units with c=1: keV for energy, keV/c^2 for mass,
> >> and keV/c for momentum (since c=1 these distinctions are
> >> notational only).
>
> KE = 15 keV ; m = 511 keV/c^2 ; E = m + KE = 526 keV

Those equation shows no LaGrangian L; And, no Angular momentum pA:
$$ GR equation corrected.
GUESS iSS GR G_uv = G_absolute / G = 1 / (n - 1) = G_relative = Gr.

ENTHALPY E = m*c^2 + LaGrangian L + Volt*Amp*sec energy eV
= eM + L + eV
= m*c^2 + pL*c + pA*fA
= m*c^2 + pL*c - (me*v^2 / 2)
= m*c^2 + m1*c^2 - (me*v^2 / 2)
= m*c^2 + h*fL + pA*fA
= m*c^2 + h*fL + nA*hbar*fA
= m*c^2 + nL*h*c / wl + nA*hbar*fA
= iNTRiNSiC energy + LaGrangian L + Volt*CHARGE energy eV
= eM + L + eV
= eM + eK ..note, this line very much fits 526 keV, above;
= eF + L + eK
= eG + eK - eV
= eG + eK + (me*v^2 / 2)
= eM + eK + (me*v^2 / 2) + eV.

Hamiltonian ANALYSiS confused POTENTiAL energy especially, which
is WHY it only fits with LaGrangian ANALYSiS in PARTiCULAR cases.
You CAN only understand this if REST mass*c^2 = iNTRiNSiC energy.
Note c constant is NOT equal to 1 in GUESS iSS units, but arrives
at the SAME ANSWER ..and also, with the SAME form as noted above.
```Brian.
> P = sqrt(E^2 - m^2) = 125 keV/c ; > beta = v/c = P/E = 0.24
> So this is more relativistic than I originally said, but not
> enormously so. gamma-1 is a typical measure of how large
> relativistic effects are, and that is 0.029 or ~3%. To obtain
> good crisp images across the face of a CRT (especially position
> being linearly related to the signal voltage)
> I suspect they must be taken into account in the design.
>
> As others have pointed out, bigger screens use larger voltages.
> Increasing to 25 kV only increases v/c to 0.30 and gamma-1 to ~5%.
>
> Tom Roberts tjob...@lucent.com
Re: the speed of electron.
########## ########### ########## ##########

$$ [MORE h*fL EMiTTER & RECiEVER equations @ item 2.]; PD wrote:
> Length is not an intrinsic physical property of the spaceship,
> so asking whether it "PHYSICALLY increases or decreases" is a
> nonsequiter. The same is true of its clock rate. > PD

Especially in GR, WHERE the GR TEST-mass is a GR POiNT-mass ..ONLY.!!
But PUT GR aside:
1. h/2*pi*c = me*wls = {mph}*ls = Moo*loo/4*pi = eR*loo/2*pi*c^2.

2. h*fL = pL*c = nL*h*c / wl = m1*c^2 = nA*{mph}*ls*c^2 / rA, ENERGY;
= pi*(h + nA*hbar) / (pi + 1)*sec ..The ENERGY for at a RECiEVER;
= 2*pi*(h + 2*hbar) / (2*pi + nA)*sec ..The ENERGY for an EMiTTER;
= (m1*v1^2/2)*{(m1/M1) + 1), The GUESS STANDARD LaGrangian.
SAME...
LEFT side is a RECiEVER DETECTOR; AND|OR EMiTTER (below) ENERGY, h*fL;
|
pi*(h + nA*hbar) | 2*pi*(h + 2*hbar)
= -- -- --- -- -- = -- -- --- -- --;|= -- -- -- -- -- --; = -- ---
(pi + 1)*sec | (2*pi + nA)*sec
|
2*pi*(h + nA*hbar) | Ra*h 2*pi*Ra*hbar
= -- -- -- -- -- -- = -- -- -- --;|= -- -- -- -- -- = -- -- -- -- --
Ra*sec | (2*pi +nA)*sec (2*pi +nA)*sec
|
LEFT side is the RECiEVER DETECTOR| ; The RiGHT side is the EMiTTER.
|
SAME, but for the AMBiENT media ..or, iN-TRANSiT space ENERGY, h*fL;

nA*{mph}*ls*c^2 nL*h*c | m1*v1^2 m1 |
= -- -- -- -- -- -- = --- -- = |(-- - --)*(-- + 1)| = pL*c = m1*c^2.
rA wl | 2 M1 |
STANDARD LaGrangian.

Sun RADiATEs @ AMBiENT; AMBiENT RADiATEs 1400 Watts/m^2 @ 1*AU radius.

3. RESTmass*c^2 = iNTRiNSiC REST energy eM = EQUiVALENT energy e.

####### ########### #########

$$ iNTRiNSiC energy (Jim Carr), follows..

RePOST 1: iNTRiNSiC energy (Jim Carr).
From: arc...@my-deja.com; To: arc...@my-deja.com
Re: Do Photons Have Mass?; Date: Mon, 15 Jan 2001 20:05:56 GMT
--------------------------------------------------------------
In article <93vike$u0a$1...@nnrp1.deja.com>, s...@microtec.net wrote:
In article <3a631377$1...@pull.gecm.com>, richard...@baesystems.com
wrote: > > In article <3A4646B6...@microtec.net>,
srp (s...@microtec.net) wrote: > > > Jim Carr a Ècrit :
In article <3a362709...@news.uq.edu.au> th...@will.bounce writes:
> > > > > Mass is equivalent to energy and photons of course have
> > > > > energy.
> > > >
> > > > Only partly true. Mass is equivalent to (what I call)
> > > > _intrinsic_ energy, the energy a particle has that is
> > > > unrelated to its motion.
> > > > The relation is that m = sqrt{ E^2 - (pc)^2 }/c^2.
`````snip`````
> > Note the sign. He's *subtracting* the momentum contribution
> > from the total energy. What's left is the intrinsic energy.
>
> I understand that. The point was that pc can only theoretically
> be completely subtracted in that equation because in reality
> no particle can be brought completely to rest with respect to
> all other particles.
>
> This means that when what Jim calls the intrinsic energy is to be
> calculated, the simple original equation E=mc^2 has always been
> and still is the real deal.

[arcsign to srp] YES, exactly, 'iNTRiNSiC energy' is just ANOTHER
simple SYNONYM for (Rest-mass)*c^2=(Rebel GR-invarint REST-mass)*c^2.

> We know c, we can measure m, so we can very precisely calculate E.
>
> On its part, p is relative, and varies depending with respect to
> which other particle you consider the motion of the original
> particle. The major point being that it can never equal zero for
> any real particle with respect to all other particles.
>
> --
> André Michaud
> Service de Recherche Pédagogique http://www.microtec.net/srp/
> La nouvelle "Société Royale" http://www.microtec.net/srp/socroyfr.htm
> "Les choses n'arrivent dans ce monde que lorsque quelqu'un les fait
> arriver" - Anonyme.
>
> Sent via Deja.com > http://www.deja.com ; ® © ¿ ; End of rePOST 1.

RePOST 2:
From: alan (dark...@mac.SendMeSpam.not.com); sci.physics;
Date: 2000/06/19; Go-go Google: <
http://groups.google.com/groups?hl=en&lr=lang_en&ie=UTF-8&th=aae4c668cab37523&
seekm=8hm3vk%24j1c%241%40crib.corepower.com#link20 >:
> | James A. Carr <j...@scri.fsu.edu> > ================
> Dear Jim,
> Three times, you have quoted this error.
>
> The speed of light is NOT "the ratio of the electric permittivity
> of free space (vacuum) to the magnetic permeability of free
> space.".
>
> It's the square root of the inverse of their product.
[jiM Carr to Brian (arcsign)]
Sorry for the error. Of course you are right, it is the "square root
of the inverse of their product". Thank you for correcting me. I hate
being wrong, but now that you have corrected me I am no longer wrong.

> You numbskulls are pathetic.
>
> Sincerely, > brian a. m. stuckless
Re: Three questions from a layman. ..end of rePOST 2.
$$ [MORE h*fL EMiTTER & RECiEVER equations @ item 2.]; End.

[POSTscript]: Jack Sarfatti wrote: >
> I think I have derived at least Einstein's classical GR vacuum

> equation as an emergent Goldstone phase modulation. -=- -=-

> I assume a Planck-scale emergence where the degenerate vacuum

> manifold -=- -=-

> Einstein's symmetric metric tensor is by the equivalence principle

> guv = eu^a(Minkowski)abev^b.

The GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr.

$$ ^.
["No WORLD-line" since GR DECLARED, "NO prior GEOMETRY".]
[Any SPACE where STUFF is "falling" CLEARLY isN'T empty.]
There's QUiTE simply, "NO GRAViTY in GEOMETRY". ```Brian.

Re: Einstein's Gravity is Emergent. End of POSTscript.

brian a m stuckless

unread,

Jan 27, 2006, 1:34:03 PM1/27/06

$$ EMiTTER & DETECTOR equations & ENTHALPY E typo +eV & added line.
[SPEEDO.wpd] ; Re: the speed of electron; Mon 16 Jan 2006 20:14.

Tom Roberts wrote: double precision wrote: big magician wrote:
> >>> does anyone knows the speed of the accelerated deviated
> >>> electrons in a crt?
> >> The accelerating voltage of a typical CRT is about 15 kV, so the
> >> kinetic nergy of an electron when it hits the screen is about 15
> >> keV; it therefore has v/c ~ 0.03. -=- I see I made a mistake.
> >> Sorry. I use units with c=1: keV for energy, keV/c^2 for mass,
> >> and keV/c for momentum (since c=1 these distinctions are
> >> notational only).
>
> KE = 15 keV ; m = 511 keV/c^2 ; E = m + KE = 526 keV

Those EQUATiONs show no LaGrangian L; And, no ANGULAR momentum pA:
$$ GR equation corrected:

GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr.

ENTHALPY E = m*c^2 + LaGrangian L + Volt*Amp*sec energy eV

= eM + L + eV
= m*c^2 + pL*c + pA*fA
= m*c^2 + pL*c - (me*v^2 / 2)
= m*c^2 + m1*c^2 - (me*v^2 / 2)
= m*c^2 + h*fL + pA*fA
= m*c^2 + h*fL + nA*hbar*fA
= m*c^2 + nL*h*c / wl + nA*hbar*fA
= iNTRiNSiC energy + LaGrangian L + Volt*CHARGE energy eV
= eM + L + eV

= eM + L - (me*v^2 / 2) ; ..Added line;
= eM + eK ; ..This line, VERY much, fits 526 keV, ABOVE;

= eF + L + eK

= eG + eK - eV ; ..THiS LiNE and NEXT *are-MUTUALLY-exclusive*;
= eG + eK + (me*v^2 / 2); Typo +eV WAS on (missing) BOTTOM LiNE.

at the SAME ANSWER ..and also, with the SAME FORM as noted ABOVE.

> P = sqrt(E^2 - m^2) = 125 keV/c ; > beta = v/c = P/E = 0.24
> So this is more relativistic than I originally said, but not
> enormously so. gamma-1 is a typical measure of how large
> relativistic effects are, and that is 0.029 or ~3%. To obtain
> good crisp images across the face of a CRT (especially position
> being linearly related to the signal voltage)
> I suspect they must be taken into account in the design.
>
> As others have pointed out, bigger screens use larger voltages.
> Increasing to 25 kV only increases v/c to 0.30 and gamma-1 to ~5%.
>
> Tom Roberts tjob...@lucent.com
Re: the speed of electron.
########## ########### ########## ##########

$$ EMiTTER & DETECTOR equations & NOTEs, etc.

> Length is not an intrinsic physical property of the spaceship,
> so asking whether it "PHYSICALLY increases or decreases" is a
> nonsequiter. The same is true of its clock rate. > PD

ESPECiALLY in GR, WHERE the GR TEST-mass is a GR POiNT-mass ..ONLY.!!

But PUT GR aside:
1. h/2*pi*c = me*wls = {mph}*ls = Moo*loo/4*pi = eR*loo/2*pi*c^2.

LEFT side is a RECiEVER DETECTOR ;| AND/OR EMiTTER (below) ENERGY h*fL;

|
pi*(h + nA*hbar) | 2*pi*(h + 2*hbar)

= -- -- --- -- -- = -- -- --- --;|= -- -- -- -- -- --; = -- --- -- --

(pi + 1)*sec | (2*pi + nA)*sec
|
2*pi*(h + nA*hbar) | Ra*h 2*pi*Ra*hbar

SAME, but for the AMBiENT media ..or, iN-TRANSiT space ENERGY, h*fL;

nA*{mph}*ls*c^2 nL*h*c | m1*v1^2 m1 |

= -- -- -- -- -- -- = --- -- = |(-- - --)*(-- + 1)| = pL*c = m1*c^2;
rA wl | 2 M1 |
$$ STANDARD LaGrangian.

####### ########### #########

> Sent via Deja.com > http://www.deja.com ® © ¿ End of rePOST.
[SPEEDo.wpd]; $$ $$ $$ $$ $$ $$ $$ $$ $$ End of POST.
Re: EMiTTER & DETECTOR equations & ENTHALPY E typo & added line.

brian a m stuckless

unread,

Jan 28, 2006, 5:09:40 AM1/28/06

$$ Emit detect Dirac ambient h*fL.
$$ Note EMiTTER side 4*(pi)^2*Rx typo-CORRECTiON @ item 2 ..below.

> Length is not an intrinsic physical property of the spaceship,

> so asking whether it "PHYSICALLY increases or decreases" -=-

[ESPECiALLY in GR, WHERE the GR TEST-mass is a GR POiNT-mass ONLY.!!]

PUT GR aside:..

1. h/2*pi*c = me*wls = {mph}*ls = Moo*loo/4*pi = eR*loo/2*pi*c^2.

Reciever DETECTOR (on LEFT side) || Planck EMiTTER energy h*fL (below);

||
pi*(h + nA*hbar) || 2*pi*(h + 2*hbar)
= -- -- --- -- -- = -- -- --- --||= -- -- -- -- -- --; = -- --- -- --
(pi + 1)*sec || (2*pi + nA)*sec
||
2*pi*(h + nA*hbar) || Ra*h 2*pi*Ra*hbar
= -- -- -- -- -- -- = -- -- -- --||= -- -- --- -- -- = -- -- --- -- --
Ra*sec || (2*pi + nA)*sec (2*pi + nA)*sec
||
2*pi*(h + nA*hbar)*Ni || (PLANCK Temp Tp)*h
= -- -- -- --- -- -- -- = --- ---||= -- -- --- -- -- -- = -- --- -- --
(PLANCK Temp Tp)*sec || (2*pi + nA)*Ni*sec
||

(h + nA*hbar)*hbar || 4*(pi)^2*Rx <- Typo-CORRECTED;

= -- -- --- -- -- -- = -- - -- --||= -- -- --- -- -- = -- -- --- -- --
Rx*sec || (2*pi + nA)*sec
||
LEFT side is a RECiEVER, DETECTOR|| The RiGHT side is an h*fL EMiTTER.

SAME, but for the AMBiENT media, or, *iN-TRANSiT-space* ENERGY, h*fL;

|nA*{mph}*ls*c^2| nL*h*c | m1*v1^2 m1 | | |

= |-- -- --- -- --| = --- -- = |(-- - --)*(-- + 1)| = pL*c = |m1*c^2|.
| rA | wl | 2 M1 | | |
$$ STANDARD LaGrangian form.

Sun RADiATEs @ AMBiENT; AMBiENT RADiATEs 1400 Watts/m^2 @ 1*AU radius.

3. RESTmass*c^2 = iNTRiNSiC REST energy eM = EQUiVALENT energy e.

Old GR EQUATiON had no LaGrangian L ..and no ANGULAR momentum pA.

$$ GR equation corrected:
GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr.

$$ ENTHALPY E = m*c^2 + LaGrangian L + Volt*Amp*sec energy eV;

= eM + L + eV ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
= eM + L - (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once;
= eM + eK

= eF + L + eK

= eG + eK - eV ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
= eG + eK + (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once.

$$ Hamiltonian ANALYSiS confused POTENTiAL energy especially, which

is WHY it only fits with LaGrangian ANALYSiS in PARTiCULAR cases.
You CAN only understand this if REST mass*c^2 = iNTRiNSiC energy.
Note c constant is NOT equal to 1 in GUESS iSS units, but arrives

at the SAME ANSWER ..and also, with the SAME FORM as GiVEN above.

RePOST: iNTRiNSiC energy (jiM Carr).

Re: Do Photons Have Mass?; Date: Mon, 15 Jan 2001 20:05:56 GMT
--------------------------------------------------------------

srp (s...@microtec.net) wrote: > > > Jim Carr a Ècrit :
In article <3a362709...@news.uq.edu.au> th...@will.bounce writes:
> > > > > Mass is equivalent to energy and photons of course have
> > > > > energy.
> > > >
> > > > Only partly true. Mass is equivalent to (what I call)
> > > > _intrinsic_ energy, the energy a particle has that is
> > > > unrelated to its motion.
> > > > The relation is that m = sqrt{ E^2 - (pc)^2 }/c^2.
`````snip`````
> > Note the sign. He's *subtracting* the momentum contribution
> > from the total energy. What's left is the intrinsic energy.

[arcsign to srp]; YES, exactly, 'iNTRiNSiC energy' is just ANOTHER
simple SYNONYM for (REST-mass)*c^2=(Rebel-GR-invarint REST-mass)*c^2.

> -- > André Michaud
> Service de Recherche Pédagogique http://www.microtec.net/srp/
> La nouvelle "Société Royale" http://www.microtec.net/srp/socroyfr.htm
> "Les choses n'arrivent dans ce monde que lorsque quelqu'un les fait
> arriver" - Anonyme.
>
> Sent via Deja.com > http://www.deja.com ® © ¿ End of rePOST.
[SPEEDo.wpd]; $$ $$ $$ $$ $$ $$ $$ $$ $$ End of POST.

Re: EMiTTER side 4*(pi)^2*Rx typo-CORRECTiON @ item 2 on Page 1.
Re: Emit detect Dirac ambient h*fL.

[POSTscript]: Jack Sarfatti wrote: >
> I think I have derived at least Einstein's classical GR vacuum
> equation as an emergent Goldstone phase modulation. -=- -=-
> I assume a Planck-scale emergence where the degenerate vacuum
> manifold -=- -=-
> Einstein's symmetric metric tensor is by the equivalence principle
> guv = eu^a(Minkowski)abev^b.

The GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr.

$$ ^.
["No WORLD-line" since GR DECLARED, "NO prior GEOMETRY".]
[Any SPACE where STUFF is "falling" CLEARLY isN'T empty.]
There's QUiTE simply, "NO GRAViTY in GEOMETRY". ```Brian.

Re: Einstein's Gravity is Emergent. ..End of POSTscript.
Re: Emit detect Dirac ambient h*fL.

brian a m stuckless

unread,

Jan 28, 2006, 5:09:44 AM1/28/06

$$ Emit detect Dirac ambient h*fL.
$$ Note EMiTTER side 4*(pi)^2*Rx typo-CORRECTiON @ item 2 ..below.

> Length is not an intrinsic physical property of the spaceship,

> so asking whether it "PHYSICALLY increases or decreases" -=-

[ESPECiALLY in GR, WHERE the GR TEST-mass is a GR POiNT-mass ONLY.!!]

PUT GR aside:..

1. h/2*pi*c = me*wls = {mph}*ls = Moo*loo/4*pi = eR*loo/2*pi*c^2.

Reciever DETECTOR (on LEFT side) || Planck EMiTTER energy h*fL (below);
||

pi*(h + nA*hbar) || 2*pi*(h + 2*hbar)
= -- -- --- -- -- = -- -- --- --||= -- -- -- -- -- --; = -- --- -- --
(pi + 1)*sec || (2*pi + nA)*sec
||
2*pi*(h + nA*hbar) || Ra*h 2*pi*Ra*hbar
= -- -- -- -- -- -- = -- -- -- --||= -- -- --- -- -- = -- -- --- -- --
Ra*sec || (2*pi + nA)*sec (2*pi + nA)*sec
||
2*pi*(h + nA*hbar)*Ni || (PLANCK Temp Tp)*h
= -- -- -- --- -- -- -- = --- ---||= -- -- --- -- -- -- = -- --- -- --
(PLANCK Temp Tp)*sec || (2*pi + nA)*Ni*sec
||

(h + nA*hbar)*hbar || 4*(pi)^2*Rx <- Typo-CORRECTED;

= -- -- --- -- -- -- = -- - -- --||= -- -- --- -- -- = -- -- --- -- --
Rx*sec || (2*pi + nA)*sec
||
LEFT side is a RECiEVER, DETECTOR|| The RiGHT side is an h*fL EMiTTER.

SAME, but for the AMBiENT media, or, *iN-TRANSiT-space* ENERGY, h*fL;

|nA*{mph}*ls*c^2| nL*h*c | m1*v1^2 m1 | | |

= |-- -- --- -- --| = --- -- = |(-- - --)*(-- + 1)| = pL*c = |m1*c^2|.
| rA | wl | 2 M1 | | |
$$ STANDARD LaGrangian form.

Sun RADiATEs @ AMBiENT; AMBiENT RADiATEs 1400 Watts/m^2 @ 1*AU radius.

3. RESTmass*c^2 = iNTRiNSiC REST energy eM = EQUiVALENT energy e.

Old GR EQUATiON had no LaGrangian L ..and no ANGULAR momentum pA.

$$ GR equation corrected:
GUESS iSS GR G_uv = G_absolute/G = 1/(n - 1) = G_relative = Gr.

$$ ENTHALPY E = m*c^2 + LaGrangian L + Volt*Amp*sec energy eV;

= eM + L + eV ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
= eM + L - (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once;
= eM + eK

= eF + L + eK

= eG + eK - eV ..THiS LiNE and NEXT are *MUTUALLY-exclusive*;
= eG + eK + (me*v^2 / 2) ..a NET energy caN'T be BOTH, at once.

$$ Hamiltonian ANALYSiS confused POTENTiAL energy especially, which

is WHY it only fits with LaGrangian ANALYSiS in PARTiCULAR cases.
You CAN only understand this if REST mass*c^2 = iNTRiNSiC energy.
Note c constant is NOT equal to 1 in GUESS iSS units, but arrives

at the SAME ANSWER ..and also, with the SAME FORM as GiVEN above.

RePOST: iNTRiNSiC energy (jiM Carr).

Re: Do Photons Have Mass?; Date: Mon, 15 Jan 2001 20:05:56 GMT
--------------------------------------------------------------

[arcsign to srp]; YES, exactly, 'iNTRiNSiC energy' is just ANOTHER
simple SYNONYM for (REST-mass)*c^2=(Rebel-GR-invarint REST-mass)*c^2.

brian a m stuckless

unread,

Jan 28, 2006, 5:12:31 AM1/28/06

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