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maxwell's equations in the frequency domain

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alex

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Dec 7, 2009, 2:13:25 PM12/7/09
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Hope someone can help.. I just can't see where I have gone wrong.

Firstly I susbstituted the fourier decomposition of an electric field
into the vector maxwell equation rot E(r,t) = mo part d/dt H (r,t)

E(r,t) = 1/2pi integral E(r,w)e^wt dw

LHS Took the cross product inside the integral
RHS took the time derivative inside the integral

Then consider how to take the time deriv of the H (r,w), which is a
complex vector in the frequency domain.

Use the defintion of fourier transform to then rewrite H in time
domain to perform partial deriv wrt time

Inside the integral is then a partial derivative of a product.

part d/dt (E(r,t)e^iwt) = E(r,t). iwe^iwt + e^iwt. partial d/ dt E
(r,t)

Using that rule I get term cacnelling to zero.

What's wrong

I am sorry its difficult to understand, but don't have acces to a
scanner to post my working out.

Any help greatfully recieved...

Thanks
ALex

Timo Nieminen

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Dec 10, 2009, 6:01:57 PM12/10/09
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On Mon, 7 Dec 2009, alex wrote:

> Hope someone can help.. I just can't see where I have gone wrong.
>
> Firstly I susbstituted the fourier decomposition of an electric field
> into the vector maxwell equation rot E(r,t) = mo part d/dt H (r,t)
>
> E(r,t) = 1/2pi integral E(r,w)e^wt dw
>
> LHS Took the cross product inside the integral
> RHS took the time derivative inside the integral
>
> Then consider how to take the time deriv of the H (r,w), which is a
> complex vector in the frequency domain.
>
> Use the defintion of fourier transform to then rewrite H in time
> domain to perform partial deriv wrt time
>
> Inside the integral is then a partial derivative of a product.
>
> part d/dt (E(r,t)e^iwt) = E(r,t). iwe^iwt + e^iwt. partial d/ dt E
> (r,t)
>
> Using that rule I get term cacnelling to zero.
>
> What's wrong

For a Fourier component E(r)*exp(iwt), the E(r) is not a function of time.
E(r) is the time-independent amplitude (density) of the Fourier component
of angular frequency w.

Presumably, you mean H, since the time derivative is of H, not E, but the
same point holds.

--
Timo

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