r^2=(abc)^2/[(a^2+b^2+c^2)^2 - 2(a^4+b^4+c^4)]
Now, you have a circle inscribed within the same triangle such that the
circle just touches each side of the triangle at a single point. That is,
the triangle's sides are tangents to the circle. What equation relates r, a,
b and c?
See e.g. <http://en.wikipedia.org/wiki/Incircle>
--
Robert Israel isr...@math.MyUniversitysInitials.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
The radius of the inscribed circle is twice
the triangle's area divided by the triangle's
perimeter.
BTW, the circle that passes through the
vertices of a triangle is usually called
the circumscribed circle (terminology that
carries over to regular polygons, which
also have both circumscribed and inscribed
circles).
regards, chip