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Thomas Gramstad b...@ifi.uio.no
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More recently, crystals of DNA fragments have been made in which the X-ray
crystal structure shows that the precise conformation is irregular and
depends on the base sequence, although for many purposes the regular
double helix is sufficient.
Bob Langridge Phone: +1 415 476-2630, -1540, -5128
Computer Graphics Laboratory FAX: +1 415 476-0688
University of California E-Mail: r...@cgl.ucsf.edu
San Francisco CA 94143-0446
(quoting from a letter to me:)
A helix is a circle that moves up with time. Hence the equations
x(t) = sin t
y(t) = cos t
z(t) = t
describe a helix. A double helix is two helices that are offset by half
a turn. The equations for the second helix would then be
x(t) = sin t
y(t) = cos t
z(t) = t + \pi
No quite, since the original question referred to a DNA double
helix. First, the double helix is not symetric. This gives rise to a
major and minor groove. The way to represent this, using the parametric
formss you give, is to have for the second helix, z(t) = t + k*pi. I'm not
sure what the exact value for k should be, but something like 0.7 would be
about right. Second, to be really correct, you should incorporate the fact
that the two strands are anti-parallel (i.e. one goes up andd the other
goes down). You need a sign-inversion in there somewhere (but don't just
change the sign of z; that would change the helical sense from right to
left handed).
--
Roy Smith, Public Health Research Institute
455 First Avenue, New York, NY 10016
{att,philabs,cmcl2,rutgers,hombre}!phri!roy -or- r...@alanine.phri.nyu.edu
"The connector is the network"
I've made dozens of these models for my kids: take a sheet of paper
and fold it lengthwise to give 3 parallel creases each bending the
same direction (a flat tube). Fold it up so that you have this flat
tube as one strip 1/4th the width and then fold that into equilateral
triangles by starting at one end and folding in alternate directions
along a 60 degree crease, bringing one side flush with one of the
sides of the strip; when done, the strip should be an accordian of
equilateral triangles. Unfold the paper and overlap the outside
strips (from the first three creases) - the paper will need to be
skewed to do this (one top corner is pulled out further than the
other). This should form a tube-like column of tetrahedrons.
--
Gary Murphy decvax!utzoo!dciem!nrcaer!cognos!garym
(garym%cogno...@uunet.uu.net)
(613) 738-1338 x5537 Cognos Inc. P.O. Box 9707 Ottawa K1G 3N3
"There are many things which do not concern the process" - Joan of Arc