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Dean Hickerson recently reported a formula whose cubes contain no zeros in base 10, provided n>=5 and n==2 mod 3. Here is a slightly simpler variation true for all n>=0.
(2.10^5n - 10^4n + 2.10^3n + 10^2n + 10^n + 1)/3.
E.g. for n=3 this is 666334000333667.
Ed Pegg Jr.
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Apr 22, 1999, 3:00:00 AM4/22/99
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I solemnly concede that my conjecture "Only a finite number of cubes lack the digit zero" is false. Nice discovery!
Lew Baxter <lba...@interlog.com> wrote in message news:7fnakj$han$1...@news.interlog.com...