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What is the sum of 2, 4, 16, 256, 65535, ..

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kasu...@gmail.com

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Feb 22, 2008, 7:07:09 AM2/22/08
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I want to find the sum of 2, 4, 16, 256, 65535, ..
Could you tell me how I can solve this problem?

Valeri Astanoff

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Feb 22, 2008, 8:46:16 AM2/22/08
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On 22 fév, 13:07, kasum...@gmail.com wrote:
> I want to find the sum of 2, 4, 16, 256, 65535, ..
> Could you tell me how I can solve this problem?

Good day,

Here is an approximate formula:

s(n) = 38*n^3 - 222*n^2 + 404*n + 2^(2^n) - 218

V.Astanoff

JEMebius

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Feb 22, 2008, 9:08:31 AM2/22/08
to kasu...@gmail.com
kasu...@gmail.com wrote:
> I want to find the sum of 2, 4, 16, 256, 65535, ..
> Could you tell me how I can solve this problem?

Just by elementary-school arithmetic and by securing exponentially increasing quantities
of pencil, paper and eraser as you proceed towards infinity.

Happy studies: Johan E. Mebius

The Qurqirish Dragon

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Feb 22, 2008, 9:46:59 AM2/22/08
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On Feb 22, 7:07 am, kasum...@gmail.com wrote:
> I want to find the sum of 2, 4, 16, 256, 65535, ..
> Could you tell me how I can solve this problem?

The general term is apparently 2^(2^n), n=0,1,2,... so, since each
term is exponentially greater than the previous one, the sequence of
partial sums is asymptotic to the final term in the partial sum.
(asymptotic in the sense that the ratio of the last term to the
partial sum becomes arbitrarily close to 1). Obviously the full series
diverges and has no sum.

Details are left as an exercise to the OP.

Neilist

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Feb 22, 2008, 9:53:52 AM2/22/08
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On Feb 22, 7:07 am, kasum...@gmail.com wrote:
> I want to find the sum of 2, 4, 16, 256, 65535, ..
> Could you tell me how I can solve this problem?

YOUR problem is in typing and proofreading, and you can solve your
problem by reading what you type, and by typing more slowly BEFORE you
press SEND.

Your last term should be 65536 = 2^16, in order for the terms of your
sequence to be 2^(2^i) for i=0 to infinity.

Richard Tobin

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Feb 22, 2008, 10:16:16 AM2/22/08
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In article <c195b541-8182-4b38...@n58g2000hsf.googlegroups.com>,
Neilist <latto...@gmail.com> wrote:

>> I want to find the sum of 2, 4, 16, 256, 65535, ..
>> Could you tell me how I can solve this problem?

>YOUR problem is in typing and proofreading, and you can solve your
>problem by reading what you type, and by typing more slowly BEFORE you
>press SEND.

I think you're the one with the problem here.

-- Richard
--
:wq

Neilist

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Feb 22, 2008, 10:50:47 AM2/22/08
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On Feb 22, 10:16 am, rich...@cogsci.ed.ac.uk (Richard Tobin) wrote:
> In article <c195b541-8182-4b38-9b73-6a0e58136...@n58g2000hsf.googlegroups.com>,

>
> Neilist  <lattora...@gmail.com> wrote:
> >> I want to find the sum of 2, 4, 16, 256, 65535, ..
> >> Could you tell me how I can solve this problem?
> >YOUR problem is in typing and proofreading, and you can solve your
> >problem by reading what you type, and by typing more slowly BEFORE you
> >press SEND.
>
> I think you're the one with the problem here.
>
> -- Richard
> --
> :wq

I think you're the one with the problem here. Right back at you.

[Mr.] Lynn Kurtz

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Feb 22, 2008, 12:47:47 PM2/22/08
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On Fri, 22 Feb 2008 15:08:31 +0100, JEMebius <jeme...@xs4all.nl>
wrote:

I don't think so. First question is whether the OP means 65536 instead
of 65535. And if so, see:

http://www.research.att.com/~njas/sequences/A001146

--Lynn

tommy1729

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Feb 22, 2008, 4:10:43 PM2/22/08
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no its you neilist.

tommy1729

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Feb 22, 2008, 4:13:50 PM2/22/08
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dragon wrote :

> On Feb 22, 7:07 am, kasum...@gmail.com wrote:
> > I want to find the sum of 2, 4, 16, 256, 65535, ..
> > Could you tell me how I can solve this problem?
>
> The general term is apparently 2^(2^n), n=0,1,2,...
> so, since each
> term is exponentially greater than the previous one,
> the sequence of
> partial sums is asymptotic to the final term in the
> partial sum.
> (asymptotic in the sense that the ratio of the last
> term to the
> partial sum becomes arbitrarily close to 1).

trivial.


> Obviously the full series
> diverges and has no sum.

perhaps the OP wonders about a summability method.


>
> Details are left as an exercise to the OP.

what details ?? what exercise ??

regards
tommy1729

Neilist

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Feb 22, 2008, 6:05:29 PM2/22/08
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> no its you neilist.- Hide quoted text -
>
> - Show quoted text -

Tommy1729 still hasn't resolved his mental problems regarding
integrals.

On August 28, 2007, 2:35 PM, Tommy1729 wrote:

"integers ...-2,-1,0,1,2,...

integrals 1,2,3,4,...

natural numbers 0,1,2,3,... "

Hahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahaha!

Hey Tommy, here's an "integral" for you: 69

Hahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahahaha!

191019...@gmail.com

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Dec 16, 2019, 3:03:09 AM12/16/19
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On Friday, February 22, 2008 at 5:37:09 PM UTC+5:30, kasu...@gmail.com wrote:
> I want to find the sum of 2, 4, 16, 256, 65535, ..
> Could you tell me how I can solve this problem?

ans = (-2/3)

Basil Jet

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Dec 16, 2019, 7:12:51 AM12/16/19
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Great, it only took you 11 years.

--
Basil Jet recently enjoyed listening to
The Box - 1983 - The Box

Sergio

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Dec 16, 2019, 3:21:00 PM12/16/19
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put a + where , is
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