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algebra but not sigma-algebra

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Legendre

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Jan 25, 2010, 6:42:31 PM1/25/10
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I want to find a set which is algebra but not sigma-algebra.

Thanks

Tim Little

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Jan 26, 2010, 12:05:00 AM1/26/10
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On 2010-01-25, Legendre <sinan...@yahoo.com> wrote:
> I want to find a set which is algebra but not sigma-algebra.

So, you want an algebra where all finite unions are in the set, but at
least some countably infinite unions are not. Hint: every finite
union of finite sets is finite.


- Tim

Dan Cass

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Jan 26, 2010, 7:57:52 AM1/26/10
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I think an algebra is closed under both finite
unions and complements.

For example the collection of finite subsets of
the integers is not an algebra... so this isn't
the example Tim has in mind.

Off hand I can't come up with an algebra that isn't
a sigma algebra...

Jussi Piitulainen

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Jan 26, 2010, 8:45:20 AM1/26/10
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Dan Cass writes:
> > On 2010-01-25, Legendre <sinan...@yahoo.com>
> > wrote:
> > > I want to find a set which is algebra but not sigma-algebra.
> >
> > So, you want an algebra where all finite unions are in the set,
> > but at least some countably infinite unions are not. Hint: every
> > finite union of finite sets is finite.
>
> I think an algebra is closed under both finite unions and
> complements.
>
> For example the collection of finite subsets of the integers is not
> an algebra... so this isn't the example Tim has in mind.
>
> Off hand I can't come up with an algebra that isn't a sigma
> algebra...

I think I've seen sets called co-finite, possibly without the hyphen,
when their complements are finite. Perhaps the finite and co-finite
subsets of some infinite set might work.

Arturo Magidin

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Jan 26, 2010, 10:50:57 AM1/26/10
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On Jan 26, 6:57 am, Dan Cass <dc...@sjfc.edu> wrote:
> > On 2010-01-25, Legendre <sinankap...@yahoo.com>

> > wrote:
> > > I want to find a set which is algebra but not
> > sigma-algebra.
>
> > So, you want an algebra where all finite unions are
> > in the set, but at
> > least some countably infinite unions are not.  Hint:
> > every finite
> > union of finite sets is finite.
>
> > - Tim
>
> I think an algebra is closed under both finite
> unions and complements.
>
> For example the collection of finite subsets of
> the integers is not an algebra... so this isn't
> the example Tim has in mind.

That's not the only thing they have of course; but if you consider the
smallest algebra that contains finite sets...

What happens if you take the finite sets, and their complements, and
nothing else?

--
Arturo Magidin

Dan Cass

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Jan 26, 2010, 11:11:41 AM1/26/10
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> On Jan 26, 6:57 am, Dan Cass <dc...@sjfc.edu> wrote:
> > > On 2010-01-25, Legendre <sinankap...@yahoo.com>
> > > wrote:
> > > > I want to find a set which is algebra but not
> > > sigma-algebra.
> >
> > > So, you want an algebra where all finite unions
> are
> > > in the set, but at
> > > least some countably infinite unions are not.
>  Hint:
> > > every finite
> > > union of finite sets is finite.
> >
> > > - Tim
> >
> > I think an algebra is closed under both finite
> > unions and complements.
> >
> > For example the collection of finite subsets of
> > the integers is not an algebra... so this isn't
> > the example Tim has in mind.
>
> That's not the only thing they have of course; but if
> you consider the
> smallest algebra that contains finite sets...
***If the collection is closed under union and
***under complement, then it's an algebra.
***DeMorgan then implies closed under intersection also.

> What happens if you take the finite sets, and their
> complements, and
> nothing else?
>
> --
> Arturo Magidin

The collection "FC" of finite or cofinite subsets
of the integers is an algebra.
[closed under union and under complement]

But it doesn't contain the set O of all odd integers.
Since for each odd integer z the set {z} is in FC,
we can say that if FC were a sigma algebra,
it should contain the (countable) union of the {z}'s
which is the set O of all odd integers.

This shows that FC is an algebra and not a sigma algebra.

That's probably what Arturo was getting at...

TCL

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Jan 26, 2010, 11:24:20 AM1/26/10
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On Jan 25, 6:42 pm, Legendre <sinankap...@yahoo.com> wrote:
> I want to find a set which is algebra but not sigma-algebra.
>
> Thanks

Sets that are a finite disjoint union of sets of the form

(-infty,infty), (-infty, a), [a,b), [a,infty), emptyset

where a<b are real numbers.
-TCL

Arturo Magidin

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Jan 26, 2010, 11:32:15 AM1/26/10
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It's almost certainly what Tim was getting at too...

--
Arturo Magidin

David C. Ullrich

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Jan 26, 2010, 11:51:22 AM1/26/10
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In article
<1491419083.50072.12644...@gallium.mathforum.org>,
Legendre <sinan...@yahoo.com> wrote:

> I want to find a set which is algebra but not sigma-algebra.

People have given two simple examples. In case you want
infinitely many more: If S is any countably infinite collection
of subsets of any set X then the algebra generated by S is
countable, and hence cannot be a sigma-algebra since any infinite
sigma-algebra has cardinality at least c.

> Thanks

--
David C. Ullrich

Tim Little

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Jan 26, 2010, 6:06:40 PM1/26/10
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On 2010-01-26, Dan Cass <dc...@sjfc.edu> wrote:
> For example the collection of finite subsets of the integers is not
> an algebra... so this isn't the example Tim has in mind.

Correct. That's why it was a hint, and not a solution on a silver platter.


- Tim

Zdislav V. Kovarik

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Jan 27, 2010, 3:20:27 PM1/27/10
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On Mon, 25 Jan 2010, Legendre wrote:

> I want to find a set which is algebra but not sigma-algebra.
>
> Thanks

On the real line, try the algebra A generated by all intervals
of the type [a,b). Can you find the interval (0,1) in it?
(It is in the sigma-algebra generated by A.)
(And you can do the proving yourself.)

(Or: in the positive integers, the algebra generated by finite subsets...)

Cheers,
ZVK(Slavek).

Legendre

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Jan 28, 2010, 6:32:29 PM1/28/10
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Thank you very much. I got the idea.
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