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sinx = ax

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Zack Subin

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Mar 28, 1998, 3:00:00 AM3/28/98
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Is there any algebraic way to solve this equation?

Zack

Joern Holm

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Mar 29, 1998, 3:00:00 AM3/29/98
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Zack Subin wrote:

> Is there any algebraic way to solve this equation?
>

No! I dont think so! Why do you ask?

> Zack


Katiah

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Mar 31, 1998, 3:00:00 AM3/31/98
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>Subject: Re: sinx = ax
>From: Joern Holm <ge...@obel.auc.dk>
>Date: Sat, Mar 28, 1998 18:27 EST
>Message-id: <351D876D...@obel.auc.dk>

I guess 0 is the only solution.

-kate

Enrico Talinucci

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Mar 31, 1998, 3:00:00 AM3/31/98
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Katiah wrote:
>
> >
> >Zack Subin wrote:
> >
> >> Is there any algebraic way to solve this equation?
> >>
> >
> >No! I dont think so! Why do you ask?
> >
> >> Zack
> >
>
> I guess 0 is the only solution.
>
> -kate

0 is the only solution for a >= 1 and a <= -1.

Enrico Talinucci

Norm Dresner

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Apr 1, 1998, 3:00:00 AM4/1/98
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Enrico Talinucci <tali...@cclix1.polito.it> wrote in article
<3520B4...@cclix1.polito.it>...
If you construct graphs of the two functions:
1. y = sin(x)
2. y = ax (you pick a couple of reasonable values of a)
you will see that there is definitely a range of the value of a for which
the curve intersects the straight line. In particular, a < 1.0. I don' t
have the time to compute the lower limit, but a few minutes with a piece of
graph paper and ruler should give you a reasonable approximation.

Norm D.


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