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Add to AP's 25th published book of science:: Riemann Hypothesis proof about Puzzles and Riddles especially the Hotel Riddle, and now the Alice in Wonderland meeting Lion and Unicorn on what day of the week
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Archimedes Plutonium
Nov 6, 2023, 1:34:59 AM11/6/23
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Archimedes Plutonium
Nov 5, 2023, 8:49:09 PM (4 hours ago)
to
On Sunday, November 5, 2023 at 6:44:50 PM UTC-6, Mild Shock wrote:
> Please solve this with logic:
>
> When Alice entered the forest of forgetfulness, she did not
> forget everything, only certain things. She often forgot her
> name, and the most likely thing for her to forget was the day
> of the week. Now, the lion and the unicorn were frequent
> visitors to this forest. These two are strange creatures. The
> lion lies on Mondays, Tuesdays, and Wednesdays and tells
> the truth on the other days of the week. The unicorn, on the
> other hand, lies on Thursdays, Fridays, and Saturdays, but tells
> the truth on the other days of the week.
>
> One day Alice met the lion and the unicorn resting under a tree.
> They made the following statements:
>
> Lion: Yesterday was one of my lying days.
> Unicorn: Yesterday was one of my lying days.
>
> From these statements, Alice, who was a bright girl, was able to
> deduce the day of the week. What was it?
>
Alright, well, let us see if Jan Burse with 3 strikeouts in a row makes a 4th:
1) fails at conics-- slant cut of cone is Oval, not ellipse
2) never a geometry proof of Fundamental Theorem of Calculus
3) his mindless acceptance of error filled Boole logic such as 2 OR 1 = 3 with AND as subtraction.
Let us see if Jan Burse, logic failure can even cut and paste a old riddle properly and correctly.
More important than the answer in this riddle is a Method of Logic to solve it.
So we say the Day is __truly Sunday__. Is there a contradiction? The lion says yesterday was one of my lying days-- meaning Saturday, contradiction. So here we have a Contradiction inside the puzzle for Sunday is indeterminate and making the maker-of-the-puzzle slipshod in logic. The unicorn says yesterday-- saturday was a lying day which is true. So, yes, Sunday is indeterminate with its contradiction, and where the puzzle maker was slip shod in formulation. But let us see if the other days of the week can be eliminated.
Now we say the Day is __truly Monday__, but it cannot be monday for the unicorn says he lies on Thur,F,S but tells the truth on monday.
Now we say the Day is __truly Tuesday__, but it cannot be tuesday for the unicorn says he lies on Thurs, F, S
Now we say the Day is __truly Wedn__, but it cannot be Wedn for the unicorn says he lies on Thur,F,S.
Now we say the Day is __truly Thurs__, but it can it be Thurs for the unicorn says he lies on Thurs, while the lion tells the truth on thursday. No contradiction in either lion or unicorn so Thursday is the only Well Formed Answer with Sunday Indeterminate.
Now we say the Day is __truly Fri__, but it cannot be Fri for the lion lies on M,T,W.
Now we say the Day is __truly Sat__, but it cannot be Sat for the lion lies on M,T,W.
So, we end up with Sunday indeterminate or Thursday as the one well determined answer that solves the riddle. And Jan Burse made a mistake in copy pasting from original author of this riddle. Or Jan Burse has not enough logical marbles to be an attendant do this puzzle.
Looks like 4 strikes in a row for Jan Burse-- can someone escort Jan Burse to the exit door of sci.math.
AP
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Archimedes Plutonium
Nov 5, 2023, 9:08:00 PM (3 hours ago)
to
Let me sharpen up the Contradiction made by the puzzle maker of this riddle-puzzle. The maker says that the Lion lies only on Monday, Tues, Wedn and tells the truth for the rest of the week.
But if the day is truly Sunday, then the Lion would not make a statement to Alice that Lion: Yesterday was one of my lying days.
It is acceptable that the unicorn would say Unicorn: Yesterday was one of my lying days. For yesterday to the unicorn was Saturday in which he does lie.
So here is a Puzzle that the puzzlemaker screwed up in formulating.
To correct his/her puzzle would have to say something like Sunday is off the table, some holiday of sorts and the puzzle can only be formulated over the other 6 days.
This is caused by there being the odd number of 7 days in a week. So if we boot out Sunday, then the puzzle is a Logic puzzle without Contradiction.
So the day of Sunday is not even mentioned or reckoned with.
> Now we say the Day is __truly Monday__, but it cannot be monday for the unicorn says he lies on Thur,F,S but tells the truth on monday.
>
> Now we say the Day is __truly Tuesday__, but it cannot be tuesday for the unicorn says he lies on Thurs, F, S
>
> Now we say the Day is __truly Wedn__, but it cannot be Wedn for the unicorn says he lies on Thur,F,S.
>
> Now we say the Day is __truly Thurs__, but it can it be Thurs for the unicorn says he lies on Thurs, while the lion tells the truth on thursday. No contradiction in either lion or unicorn so Thursday is the only Well Formed Answer with Sunday Indeterminate.
>
> Now we say the Day is __truly Fri__, but it cannot be Fri for the lion lies on M,T,W.
>
> Now we say the Day is __truly Sat__, but it cannot be Sat for the lion lies on M,T,W.
>
> So, we end up with Sunday indeterminate or Thursday as the one well determined answer that solves the riddle. And Jan Burse made a mistake in copy pasting from original author of this riddle. Or Jan Burse has not enough logical marbles to be an attendant do this puzzle.
>
> Looks like 4 strikes in a row for Jan Burse-- can someone escort Jan Burse to the exit door of sci.math.
>
You can always count on Jan Burse with his mannequin puppet in Canada Dan Christensen to screw up anything dealing in Logical thought.
AP, King of Science, especially Physics
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 9:28:06 PM (3 hours ago)
to
Another way of putting the contradiction, whether the fool Jan Burse made the puzzle or whether the blame goes elsewhere to the original puzzle maker.
So we have stated that both lion --- lies on Monday, Tuesday, Wedn and tells the truth the rest of the week
>Lion: Yesterday was one of my lying days.
And that all falls apart for Sunday. For say the Actual true day that Alice meets the lion and unicorn is Sunday. That would mean the Lion should say "Yesterday was a truthful day". Because it was a Saturday and the author of the puzzle says the lion speaks the truth on Thur, Fri, Sat, Sun.
So, the puzzlemaker of this riddle does not have enough logical marbles to make a contradiction free puzzle.
AP
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 11:38:22 PM (1 hour ago)
to
Now there is a far far better and easier solution to rectify this Puzzle Riddle, by simply saying the Lion lies on Sunday, Monday, Tues, Wedn and tells the truth the rest of the week, while the Unicorn lies on Thurs, Frid, Sat and tells the truth the rest of the week.
Now let me check to see if that makes a Logically Sound Riddle. Under the conditions of.
> Lion: Yesterday was one of my lying days.
> Unicorn: Yesterday was one of my lying days.
If Alice meets on __truly Sunday__ then Sunday is a possible true meeting day for lion is liaring about Saturday while Unicorn is telling the truth about Saturday is a lie.
If ___ truly Monday___ then unicorn proves it was not Monday
If ____truly Tuesday__ then unicorn proves it cannot be Tues.
If ____truly Wedn___ then unicorn proves it cannot be Wedn.
If ____truly Thurs___ then unicorn does satisfy it is a lie and lion does satisfy that wedn is a liaring day.
If ___truly Fri___ then lion proves it cannot be Fri.
If ___truly Sat___ then lion proves it cannot be Sat.
So, question then becomes, did the original author of this riddle make a mistake with Sunday not included as a liaring day for lion, or was the hand me done of this riddle become obfuscated so much that when Jan Burse gets a whiff of the riddle, he blindly and stupidly forgets the lion needs to liar on Sunday, Mon, Tues and Wedn.
AP
This makes a nice riddle in AP's collection of riddles, however, the all time greatest riddle is the Hotel with three guests paying 10 each. The owner gives 5 back to be divided into the three. The bellhop gives 1 to each soldier but pockets 2 as a crooked bellhop. So each of the 3 soldiers payed $9 for their room making a total of $27, with the crooked bellhop pocketing $2. So we have 27+ 2 = 29. Where did the 1 dollar go?
This favorite riddle of mine is the essence of the Disproof of the Riemann Hypothesis in Old Math.
AP
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 11:51:33 PM (1 hour ago)
to
On Sunday, November 5, 2023 at 11:38:22 PM UTC-6, Archimedes Plutonium wrote:
> Now there is a far far better and easier solution to rectify this Puzzle Riddle, by simply saying the Lion lies on Sunday, Monday, Tues, Wedn and tells the truth the rest of the week, while the Unicorn lies on Thurs, Frid, Sat and tells the truth the rest of the week.
>
> Now let me check to see if that makes a Logically Sound Riddle. Under the conditions of.
> > Lion: Yesterday was one of my lying days.
> > Unicorn: Yesterday was one of my lying days.
> If Alice meets on __truly Sunday__ then Sunday is a possible true meeting day for lion is liaring about Saturday while Unicorn is telling the truth about Saturday is a lie.
>
> If ___ truly Monday___ then unicorn proves it was not Monday
> If ____truly Tuesday__ then unicorn proves it cannot be Tues.
> If ____truly Wedn___ then unicorn proves it cannot be Wedn.
> If ____truly Thurs___ then unicorn does satisfy it is a lie and lion does satisfy that wedn is a liaring day.
> If ___truly Fri___ then lion proves it cannot be Fri.
> If ___truly Sat___ then lion proves it cannot be Sat.
>
> So, question then becomes, did the original author of this riddle make a mistake with Sunday not included as a liaring day for lion, or was the hand me down of this riddle become obfuscated so much that when Jan Burse gets a whiff of the riddle, he blindly and stupidly forgets the lion needs to liar on Sunday, Mon, Tues and Wedn.
>
Now it is possible that the original author never had a Logically Sound Riddle for he/she thought the answer is uniquely Thursday, and not both Sunday and thursday.
So in the framing of the riddle we must look to see if the original author thought it was a unique day, and not 2 different days. Then we have the situation that no-one in this puzzle had a Sound Logical Puzzle, but rather a scatterbrained puzzle.
> AP
>
> This makes a nice riddle in AP's collection of riddles, however, the all time greatest riddle is the Hotel with three guests paying 10 each. The owner gives 5 back to be divided into the three. The bellhop gives 1 to each soldier but pockets 2 as a crooked bellhop. So each of the 3 soldiers payed $9 for their room making a total of $27, with the crooked bellhop pocketing $2. So we have 27+ 2 = 29. Where did the 1 dollar go?
>
> This favorite riddle of mine is the essence of the Disproof of the Riemann Hypothesis in Old Math.
>
There is another puzzle down through the years that I like. It goes something like this-- a man and his fox, goat and hay come to a river to cross. The boat can only take two at a time. So how to get all across without the sheep eating the hay, the fox not eating the goat and the goat not eating the hay. Solution. Take the goat first, come back and pick up the fox. Take the fox across and load the boat with the goat going back. Drop off the goat and take the hay across to the fox. Now go back and pick up the Goat and continue the journey. Sadly I have not been able to utilize this riddle in any math or physics problems.
My 25th published book.
Disproof of Riemann Hypothesis // Math proof series, book 11
by Archimedes Plutonium (Author) (Amazon's Kindle)
Last revision was September 2023. This is AP's 25th published book of science.
Preface: The Riemann Hypothesis was a conjecture never able to be proven and for good reason, for it was the last symptom of a rampant disease inside of mathematics. Old Math did not have the true numbers that compose mathematics. Old Math had a rag-tag ugly collection of fake numbers with their Reals, their Negative numbers compounded with Rationals compounded with Irrationals and then adding on the Imaginary. These are fake numbers, when the true numbers of mathematics are the Decimal Grid Numbers. Because Old Math uses fake numbers, is the reason that Riemann Hypothesis just languished, languished and languished. You cannot prove something riddled in fakery. Below I demonstrate why having fake numbers in math, creates fake proofs, fake theorems, and creates a conjecture that can never be proven.
Cover picture: Riemann Hypothesis deals with fake numbers of mathematics. When what is needed is the true numbers-- Decimal Grid Numbers. We learn Decimal Grid Numbers when very young, when just toddlers, wood counting blocks. All the true numbers of mathematics come from Mathematical Induction-- counting. Mathematical Induction is utterly absent in the Riemann Hypothesis, when it should be central to the hypothesis.
Product details
ASIN : B07PVDS1RC
Publication date : March 20, 2019
Language : English
File size : 1489 KB
Text-to-Speech : Enabled
Screen Reader : Supported
Enhanced typesetting : Enabled
X-Ray : Not Enabled
Word Wise : Not Enabled
Print length : 77 pages
Lending : Enabled
Best Sellers Rank: #5,118,638 in Kindle Store (See Top 100 in Kindle Store)
◦ #643 in Number Theory (Kindle Store)
◦ #1,398 in One-Hour Science & Math Short Reads
◦ #3,559 in Number Theory (Books)
AP
Add to AP's 25th published book of science:: Riemann Hypothesis proof about Puzzles and Riddles especially the Hotel Riddle, and now the Alice in Wonderland meeting Lion and Unicorn on what day of the week
Nov 5, 2023, 8:49:09 PM (4 hours ago)
to
On Sunday, November 5, 2023 at 6:44:50 PM UTC-6, Mild Shock wrote:
> Please solve this with logic:
>
> When Alice entered the forest of forgetfulness, she did not
> forget everything, only certain things. She often forgot her
> name, and the most likely thing for her to forget was the day
> of the week. Now, the lion and the unicorn were frequent
> visitors to this forest. These two are strange creatures. The
> lion lies on Mondays, Tuesdays, and Wednesdays and tells
> the truth on the other days of the week. The unicorn, on the
> other hand, lies on Thursdays, Fridays, and Saturdays, but tells
> the truth on the other days of the week.
>
> One day Alice met the lion and the unicorn resting under a tree.
> They made the following statements:
>
> Lion: Yesterday was one of my lying days.
> Unicorn: Yesterday was one of my lying days.
>
> From these statements, Alice, who was a bright girl, was able to
> deduce the day of the week. What was it?
>
Alright, well, let us see if Jan Burse with 3 strikeouts in a row makes a 4th:
1) fails at conics-- slant cut of cone is Oval, not ellipse
2) never a geometry proof of Fundamental Theorem of Calculus
3) his mindless acceptance of error filled Boole logic such as 2 OR 1 = 3 with AND as subtraction.
Let us see if Jan Burse, logic failure can even cut and paste a old riddle properly and correctly.
More important than the answer in this riddle is a Method of Logic to solve it.
So we say the Day is __truly Sunday__. Is there a contradiction? The lion says yesterday was one of my lying days-- meaning Saturday, contradiction. So here we have a Contradiction inside the puzzle for Sunday is indeterminate and making the maker-of-the-puzzle slipshod in logic. The unicorn says yesterday-- saturday was a lying day which is true. So, yes, Sunday is indeterminate with its contradiction, and where the puzzle maker was slip shod in formulation. But let us see if the other days of the week can be eliminated.
Now we say the Day is __truly Monday__, but it cannot be monday for the unicorn says he lies on Thur,F,S but tells the truth on monday.
Now we say the Day is __truly Tuesday__, but it cannot be tuesday for the unicorn says he lies on Thurs, F, S
Now we say the Day is __truly Wedn__, but it cannot be Wedn for the unicorn says he lies on Thur,F,S.
Now we say the Day is __truly Thurs__, but it can it be Thurs for the unicorn says he lies on Thurs, while the lion tells the truth on thursday. No contradiction in either lion or unicorn so Thursday is the only Well Formed Answer with Sunday Indeterminate.
Now we say the Day is __truly Fri__, but it cannot be Fri for the lion lies on M,T,W.
Now we say the Day is __truly Sat__, but it cannot be Sat for the lion lies on M,T,W.
So, we end up with Sunday indeterminate or Thursday as the one well determined answer that solves the riddle. And Jan Burse made a mistake in copy pasting from original author of this riddle. Or Jan Burse has not enough logical marbles to be an attendant do this puzzle.
Looks like 4 strikes in a row for Jan Burse-- can someone escort Jan Burse to the exit door of sci.math.
AP
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 9:08:00 PM (3 hours ago)
to
Let me sharpen up the Contradiction made by the puzzle maker of this riddle-puzzle. The maker says that the Lion lies only on Monday, Tues, Wedn and tells the truth for the rest of the week.
But if the day is truly Sunday, then the Lion would not make a statement to Alice that Lion: Yesterday was one of my lying days.
It is acceptable that the unicorn would say Unicorn: Yesterday was one of my lying days. For yesterday to the unicorn was Saturday in which he does lie.
So here is a Puzzle that the puzzlemaker screwed up in formulating.
To correct his/her puzzle would have to say something like Sunday is off the table, some holiday of sorts and the puzzle can only be formulated over the other 6 days.
This is caused by there being the odd number of 7 days in a week. So if we boot out Sunday, then the puzzle is a Logic puzzle without Contradiction.
So the day of Sunday is not even mentioned or reckoned with.
> Now we say the Day is __truly Monday__, but it cannot be monday for the unicorn says he lies on Thur,F,S but tells the truth on monday.
>
> Now we say the Day is __truly Tuesday__, but it cannot be tuesday for the unicorn says he lies on Thurs, F, S
>
> Now we say the Day is __truly Wedn__, but it cannot be Wedn for the unicorn says he lies on Thur,F,S.
>
> Now we say the Day is __truly Thurs__, but it can it be Thurs for the unicorn says he lies on Thurs, while the lion tells the truth on thursday. No contradiction in either lion or unicorn so Thursday is the only Well Formed Answer with Sunday Indeterminate.
>
> Now we say the Day is __truly Fri__, but it cannot be Fri for the lion lies on M,T,W.
>
> Now we say the Day is __truly Sat__, but it cannot be Sat for the lion lies on M,T,W.
>
> So, we end up with Sunday indeterminate or Thursday as the one well determined answer that solves the riddle. And Jan Burse made a mistake in copy pasting from original author of this riddle. Or Jan Burse has not enough logical marbles to be an attendant do this puzzle.
>
> Looks like 4 strikes in a row for Jan Burse-- can someone escort Jan Burse to the exit door of sci.math.
>
You can always count on Jan Burse with his mannequin puppet in Canada Dan Christensen to screw up anything dealing in Logical thought.
AP, King of Science, especially Physics
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 9:28:06 PM (3 hours ago)
to
Another way of putting the contradiction, whether the fool Jan Burse made the puzzle or whether the blame goes elsewhere to the original puzzle maker.
So we have stated that both lion --- lies on Monday, Tuesday, Wedn and tells the truth the rest of the week
>Lion: Yesterday was one of my lying days.
And that all falls apart for Sunday. For say the Actual true day that Alice meets the lion and unicorn is Sunday. That would mean the Lion should say "Yesterday was a truthful day". Because it was a Saturday and the author of the puzzle says the lion speaks the truth on Thur, Fri, Sat, Sun.
So, the puzzlemaker of this riddle does not have enough logical marbles to make a contradiction free puzzle.
AP
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 11:38:22 PM (1 hour ago)
to
Now there is a far far better and easier solution to rectify this Puzzle Riddle, by simply saying the Lion lies on Sunday, Monday, Tues, Wedn and tells the truth the rest of the week, while the Unicorn lies on Thurs, Frid, Sat and tells the truth the rest of the week.
Now let me check to see if that makes a Logically Sound Riddle. Under the conditions of.
> Lion: Yesterday was one of my lying days.
> Unicorn: Yesterday was one of my lying days.
If Alice meets on __truly Sunday__ then Sunday is a possible true meeting day for lion is liaring about Saturday while Unicorn is telling the truth about Saturday is a lie.
If ___ truly Monday___ then unicorn proves it was not Monday
If ____truly Tuesday__ then unicorn proves it cannot be Tues.
If ____truly Wedn___ then unicorn proves it cannot be Wedn.
If ____truly Thurs___ then unicorn does satisfy it is a lie and lion does satisfy that wedn is a liaring day.
If ___truly Fri___ then lion proves it cannot be Fri.
If ___truly Sat___ then lion proves it cannot be Sat.
So, question then becomes, did the original author of this riddle make a mistake with Sunday not included as a liaring day for lion, or was the hand me done of this riddle become obfuscated so much that when Jan Burse gets a whiff of the riddle, he blindly and stupidly forgets the lion needs to liar on Sunday, Mon, Tues and Wedn.
AP
This makes a nice riddle in AP's collection of riddles, however, the all time greatest riddle is the Hotel with three guests paying 10 each. The owner gives 5 back to be divided into the three. The bellhop gives 1 to each soldier but pockets 2 as a crooked bellhop. So each of the 3 soldiers payed $9 for their room making a total of $27, with the crooked bellhop pocketing $2. So we have 27+ 2 = 29. Where did the 1 dollar go?
This favorite riddle of mine is the essence of the Disproof of the Riemann Hypothesis in Old Math.
AP
Archimedes Plutonium's profile photo
Archimedes Plutonium
Nov 5, 2023, 11:51:33 PM (1 hour ago)
to
On Sunday, November 5, 2023 at 11:38:22 PM UTC-6, Archimedes Plutonium wrote:
> Now there is a far far better and easier solution to rectify this Puzzle Riddle, by simply saying the Lion lies on Sunday, Monday, Tues, Wedn and tells the truth the rest of the week, while the Unicorn lies on Thurs, Frid, Sat and tells the truth the rest of the week.
>
> Now let me check to see if that makes a Logically Sound Riddle. Under the conditions of.
> > Lion: Yesterday was one of my lying days.
> > Unicorn: Yesterday was one of my lying days.
> If Alice meets on __truly Sunday__ then Sunday is a possible true meeting day for lion is liaring about Saturday while Unicorn is telling the truth about Saturday is a lie.
>
> If ___ truly Monday___ then unicorn proves it was not Monday
> If ____truly Tuesday__ then unicorn proves it cannot be Tues.
> If ____truly Wedn___ then unicorn proves it cannot be Wedn.
> If ____truly Thurs___ then unicorn does satisfy it is a lie and lion does satisfy that wedn is a liaring day.
> If ___truly Fri___ then lion proves it cannot be Fri.
> If ___truly Sat___ then lion proves it cannot be Sat.
>
> So, question then becomes, did the original author of this riddle make a mistake with Sunday not included as a liaring day for lion, or was the hand me down of this riddle become obfuscated so much that when Jan Burse gets a whiff of the riddle, he blindly and stupidly forgets the lion needs to liar on Sunday, Mon, Tues and Wedn.
>
Now it is possible that the original author never had a Logically Sound Riddle for he/she thought the answer is uniquely Thursday, and not both Sunday and thursday.
So in the framing of the riddle we must look to see if the original author thought it was a unique day, and not 2 different days. Then we have the situation that no-one in this puzzle had a Sound Logical Puzzle, but rather a scatterbrained puzzle.
> AP
>
> This makes a nice riddle in AP's collection of riddles, however, the all time greatest riddle is the Hotel with three guests paying 10 each. The owner gives 5 back to be divided into the three. The bellhop gives 1 to each soldier but pockets 2 as a crooked bellhop. So each of the 3 soldiers payed $9 for their room making a total of $27, with the crooked bellhop pocketing $2. So we have 27+ 2 = 29. Where did the 1 dollar go?
>
> This favorite riddle of mine is the essence of the Disproof of the Riemann Hypothesis in Old Math.
>
There is another puzzle down through the years that I like. It goes something like this-- a man and his fox, goat and hay come to a river to cross. The boat can only take two at a time. So how to get all across without the sheep eating the hay, the fox not eating the goat and the goat not eating the hay. Solution. Take the goat first, come back and pick up the fox. Take the fox across and load the boat with the goat going back. Drop off the goat and take the hay across to the fox. Now go back and pick up the Goat and continue the journey. Sadly I have not been able to utilize this riddle in any math or physics problems.
My 25th published book.
Disproof of Riemann Hypothesis // Math proof series, book 11
by Archimedes Plutonium (Author) (Amazon's Kindle)
Last revision was September 2023. This is AP's 25th published book of science.
Preface: The Riemann Hypothesis was a conjecture never able to be proven and for good reason, for it was the last symptom of a rampant disease inside of mathematics. Old Math did not have the true numbers that compose mathematics. Old Math had a rag-tag ugly collection of fake numbers with their Reals, their Negative numbers compounded with Rationals compounded with Irrationals and then adding on the Imaginary. These are fake numbers, when the true numbers of mathematics are the Decimal Grid Numbers. Because Old Math uses fake numbers, is the reason that Riemann Hypothesis just languished, languished and languished. You cannot prove something riddled in fakery. Below I demonstrate why having fake numbers in math, creates fake proofs, fake theorems, and creates a conjecture that can never be proven.
Cover picture: Riemann Hypothesis deals with fake numbers of mathematics. When what is needed is the true numbers-- Decimal Grid Numbers. We learn Decimal Grid Numbers when very young, when just toddlers, wood counting blocks. All the true numbers of mathematics come from Mathematical Induction-- counting. Mathematical Induction is utterly absent in the Riemann Hypothesis, when it should be central to the hypothesis.
Product details
ASIN : B07PVDS1RC
Publication date : March 20, 2019
Language : English
File size : 1489 KB
Text-to-Speech : Enabled
Screen Reader : Supported
Enhanced typesetting : Enabled
X-Ray : Not Enabled
Word Wise : Not Enabled
Print length : 77 pages
Lending : Enabled
Best Sellers Rank: #5,118,638 in Kindle Store (See Top 100 in Kindle Store)
◦ #643 in Number Theory (Kindle Store)
◦ #1,398 in One-Hour Science & Math Short Reads
◦ #3,559 in Number Theory (Books)
AP
Add to AP's 25th published book of science:: Riemann Hypothesis proof about Puzzles and Riddles especially the Hotel Riddle, and now the Alice in Wonderland meeting Lion and Unicorn on what day of the week
Archimedes Plutonium
Nov 6, 2023, 3:45:59 PM11/6/23
to
Logic failure Jan Burse cannot even a logical consistent puzzle without screwing up the puzzle itself.
For his framing of the puzzle has Sunday as indeterminate for he forgot to give the Lion as another day of Liaring. Then the puzzle has two answers--- Sunday and Thursday.
But, the question is, can we frame the puzzle so that it is Logically Consistent and provides a Unique solution. Otherwise, we have no puzzle at all but a inconsistent pile of worthless garbage.
Looking in this thread, another person also realizes there is "funny matter issues going on", in that Mike Terry earlier concluded it was Thursday or Sunday. But rather than press the horrible failed logic of poising the problem, Terry runs.
AP never runs from a problem.
The question over this puzzle is whether it can be made to be a Unique day. And from the looks of it, so far, I would say No, no no.
But for AP, this problem maybe relevant to physics, in the idea of two points of contact in a closed circuit.
So, let us say a Week has not just 7 days but has 10 days. And let us say the lion liars on day 1,2,3,4,5 and tells the truth on days 6,7,8,9,10.
Let us say the Unicorn liars on 6,7,8,9,10 and tells the truth on 1,2,3,4,5.
Now Alice lands from a spaceship in this weird world of lion and unicorn and tasked to figure out which of these 10 days it is.
And Alice hears from the lion and unicorn this testimony::
Lion: Yesterday was one of my truthful days.
Unicorn: Yesterday was one of my truthful days.
I made this puzzle with a even number of days, and I made the statements be of truth for the human mind is not steady and is vacillating whenever it hears "lying" for human minds are wobbly contraptions that wobble in the slightest of breezes.
The Method of Proof is more important than the final answer, as I said before.
So we say the __true day is 1__ and so, can 1 be the day? Impossible because the lion liars on 1 and tells the truth on 10 for the lion would have had to say "Yesterday was a liar day for me".
So we say the ___true day is 6__ and so can 6 be the unique day for Alice? Impossible for the lion tells the truth on day 6 and that truth should be "Yesterday was a liar day, day 5, for me".
So, I believe in this readaption with an even number of days, there is no solution, no unique day at all.
So, at least AP's puzzle is Logically Consistent, whereas Burse and the other puzzles cannot have a Unique solution day for Alice.
On Monday, November 6, 2023 at 9:44:39 AM UTC-6, Mild Shock wrote:
> I got the puzzle from a discussion here,
> which was about Prolog versus Theorem Proving:
>
> The lion and the unicorn met PROLOG
> Bruce D. Ramsey, 1986 - Free Access
> https: dot address
>
> This gives immediately the following database:
>
> yesterday(monday , sunday ).
> yesterday(tuesday , monday ).
> yesterday(wednesday, tuesday ).
> yesterday(thursday , wednesday).
> yesterday(friday , thursday ).
> yesterday(saturday , friday ).
> yesterday(sunday , saturday ).
>
> lies(lion, monday ).
> lies(lion, tuesday ).
> lies(lion, wednesday).
>
> lies(unicorn, thursday).
> lies(unicorn, friday ).
> lies(unicorn, saturday).
>
> Now what?
You have no puzzle that is Logically Consistent.
AP
For his framing of the puzzle has Sunday as indeterminate for he forgot to give the Lion as another day of Liaring. Then the puzzle has two answers--- Sunday and Thursday.
But, the question is, can we frame the puzzle so that it is Logically Consistent and provides a Unique solution. Otherwise, we have no puzzle at all but a inconsistent pile of worthless garbage.
Looking in this thread, another person also realizes there is "funny matter issues going on", in that Mike Terry earlier concluded it was Thursday or Sunday. But rather than press the horrible failed logic of poising the problem, Terry runs.
AP never runs from a problem.
The question over this puzzle is whether it can be made to be a Unique day. And from the looks of it, so far, I would say No, no no.
But for AP, this problem maybe relevant to physics, in the idea of two points of contact in a closed circuit.
So, let us say a Week has not just 7 days but has 10 days. And let us say the lion liars on day 1,2,3,4,5 and tells the truth on days 6,7,8,9,10.
Let us say the Unicorn liars on 6,7,8,9,10 and tells the truth on 1,2,3,4,5.
Now Alice lands from a spaceship in this weird world of lion and unicorn and tasked to figure out which of these 10 days it is.
And Alice hears from the lion and unicorn this testimony::
Lion: Yesterday was one of my truthful days.
Unicorn: Yesterday was one of my truthful days.
I made this puzzle with a even number of days, and I made the statements be of truth for the human mind is not steady and is vacillating whenever it hears "lying" for human minds are wobbly contraptions that wobble in the slightest of breezes.
The Method of Proof is more important than the final answer, as I said before.
So we say the __true day is 1__ and so, can 1 be the day? Impossible because the lion liars on 1 and tells the truth on 10 for the lion would have had to say "Yesterday was a liar day for me".
So we say the ___true day is 6__ and so can 6 be the unique day for Alice? Impossible for the lion tells the truth on day 6 and that truth should be "Yesterday was a liar day, day 5, for me".
So, I believe in this readaption with an even number of days, there is no solution, no unique day at all.
So, at least AP's puzzle is Logically Consistent, whereas Burse and the other puzzles cannot have a Unique solution day for Alice.
On Monday, November 6, 2023 at 9:44:39 AM UTC-6, Mild Shock wrote:
> I got the puzzle from a discussion here,
> which was about Prolog versus Theorem Proving:
>
> The lion and the unicorn met PROLOG
> Bruce D. Ramsey, 1986 - Free Access
> https: dot address
>
> This gives immediately the following database:
>
> yesterday(monday , sunday ).
> yesterday(tuesday , monday ).
> yesterday(wednesday, tuesday ).
> yesterday(thursday , wednesday).
> yesterday(friday , thursday ).
> yesterday(saturday , friday ).
> yesterday(sunday , saturday ).
>
> lies(lion, monday ).
> lies(lion, tuesday ).
> lies(lion, wednesday).
>
> lies(unicorn, thursday).
> lies(unicorn, friday ).
> lies(unicorn, saturday).
>
> Now what?
You have no puzzle that is Logically Consistent.
AP
Archimedes Plutonium
Nov 6, 2023, 4:16:46 PM11/6/23
to
Now, let me get back to Alice with lion and unicorn and 7 days in a week.
Let the statements be
Unicorn tells truth on Sun,Mon,Tues,Wedn, and liars on Thurs,Fri,Sat
Is there a unique day for Alice??? And is the puzzle logically consistent??? Those two questions are intertwined.
METHOD OF PROOF
Stepwise we see if each day is possible or impossible.
Suppose the __actual true day is Monday__, is that possible? Okay for lion and okay for unicorn.
Suppose the __actual true day is Tues___, is that possible? checks out okay for both lion and unicorn.
Suppose the __actual true day is Wedn___, here again checks out okay for both.
Suppose the __actual true day is Thurs___, is that possible? No, for lion is off
Suppose the __actual true day is Fri___, is that possible? Checks out okay.
Suppose the ___ actual true day is Sat___, is that possible? Yes checks out on both.
Suppose the ___ actual true day is Sun___, is that possible? No, for the unicorn should have said "yesterday is a liar day for me"
So, here again, there is no Unique day. And Alice can only conclude it is either Sunday or Thursday.
So far in my analysis, either the puzzle has no solutions and when it does have a solution, it has a pair and no unique solution.
AP
Let the statements be
Lion: Yesterday was one of my truthful days.
Unicorn: Yesterday was one of my truthful days.
Lion tells truth on Thurs, Fri, Sat and liars on Sun,Mon,Tues,Wedn
Unicorn: Yesterday was one of my truthful days.
Unicorn tells truth on Sun,Mon,Tues,Wedn, and liars on Thurs,Fri,Sat
Is there a unique day for Alice??? And is the puzzle logically consistent??? Those two questions are intertwined.
METHOD OF PROOF
Stepwise we see if each day is possible or impossible.
Suppose the __actual true day is Monday__, is that possible? Okay for lion and okay for unicorn.
Suppose the __actual true day is Tues___, is that possible? checks out okay for both lion and unicorn.
Suppose the __actual true day is Wedn___, here again checks out okay for both.
Suppose the __actual true day is Thurs___, is that possible? No, for lion is off
Suppose the __actual true day is Fri___, is that possible? Checks out okay.
Suppose the ___ actual true day is Sat___, is that possible? Yes checks out on both.
Suppose the ___ actual true day is Sun___, is that possible? No, for the unicorn should have said "yesterday is a liar day for me"
So, here again, there is no Unique day. And Alice can only conclude it is either Sunday or Thursday.
So far in my analysis, either the puzzle has no solutions and when it does have a solution, it has a pair and no unique solution.
AP
Archimedes Plutonium
Nov 6, 2023, 8:19:50 PM11/6/23
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Archimedes Plutonium<plutonium....@gmail.com>
4:27 PM (3 hours ago)
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In sci.math I wrote:
On Monday, November 6, 2023 at 4:13:37 PM UTC-6, Archimedes Plutonium wrote:
> Alright, here I am building a Puzzle that is logically consistent, and that provides a unique solution.
>
> Given the lion and unicorn make the statement::
>
> Lion liars on Monday; tells truth on Tues; liars on Wedn; truth on Thurs; liars Fri; truth Sat; liars Sun.
>
> Unicorn truth on Monday; liars Tues; truth Wedn; liars Thurs; truth Fri; liars Sat; truth Sun.
>
> Suppose Alice meets the lion and unicorn and it is ___truly Monday___ is that possible? Yes it is possible in that the lion liars on Sunday and liars on Monday.
>
> Yes, I suspect this formulation gives a unique day --- Monday, eliminating all the other days as not possible, although I have to go through each day, by day to be assured. And finally I have to do it with a even number of days in the week-- 6 or 8 or 10, to see if even-odd favors a unique solution.
>
> AP
Yes, I see now that it has to be a odd number for a week so as to make Sunday and Monday be truth for unicorn but both days as liaring for lion. If the week had even number of days, you do not get that sameness.
So yes, AP finds a Logical Consistent Puzzle with a Unique Solution answer-- the day is Monday.
AP
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Archimedes Plutonium<plutonium....@gmail.com>
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7:17 PM (now)
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So let me try an even number for the puzzle, try 4.
So we have 4 days in a week 1,2,3,4
And the same set-up
Lion: yesterday was a truthful day
Unicorn: yesterday was a truthful day
Lion liars on 1; truth on 2; liars on 3; truth on 4.
Unicorn tells truth on 1; liars on 2; truth on 3; liars on 4.
We have Alice meeting the lion and unicorn and wanting to figure out the day.
Suppose it is __actually and truly day 1___ is that possible? No, for the unicorn tells the truth on 1 and the truth is not that 4 is a truth day.
Are any of the other days possible? No, for the truth spoken by either lion or unicorn contradicts the puzzle of a unique solution. In this case of even 4 days in a week there is no solution.
Now if we throw in there a 5 day week
Lion liars on 1; truth on 2; liars on 3; truth on 4; liar on 5.
Unicorn tells truth on 1; liars on 2; truth on 3; liars on 4; truth on 5.
In this case, again, just like a 7 day week, there is a unique solution of day 1 where the unicorn tells the truth that day 5 is a truthful day. And where the lion liars about day 5.
Now the riddle or puzzle is useless other than a puzzle to play with, except for science and math. We begin to see in this puzzle the idea of a circuit and linked up circuit.
Notice in the Cosmic Abundance of Elements, the odd numbered elements are less abundant than even once we ignore hydrogen.
And better yet in math geometry, the Fibonacci Sequence in a Rectangle of Whirling Squares::
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144,....
For I never noticed before that that vital sequence always has two odds then a even punctuated between two odds.
So what happens to our Alice, Lion, and Unicorn if they liared 2 days, then told the truth the next day, then two more days of liaring. Do we end up with a Unique Solution in a Consistent game?
So what we see as games and puzzles and riddles, are always turned into something of math or science.
AP
4:27 PM (3 hours ago)
to Plutonium Atom Universe
In sci.math I wrote:
On Monday, November 6, 2023 at 4:13:37 PM UTC-6, Archimedes Plutonium wrote:
> Alright, here I am building a Puzzle that is logically consistent, and that provides a unique solution.
>
> Given the lion and unicorn make the statement::
> Lion: Yesterday was one of my truthful days.
> Unicorn: Yesterday was one of my truthful days.
> I am going to evenly scatter the days of truth telling and liaring.
> Unicorn: Yesterday was one of my truthful days.
>
> Lion liars on Monday; tells truth on Tues; liars on Wedn; truth on Thurs; liars Fri; truth Sat; liars Sun.
>
> Unicorn truth on Monday; liars Tues; truth Wedn; liars Thurs; truth Fri; liars Sat; truth Sun.
>
> Suppose Alice meets the lion and unicorn and it is ___truly Monday___ is that possible? Yes it is possible in that the lion liars on Sunday and liars on Monday.
>
> Yes, I suspect this formulation gives a unique day --- Monday, eliminating all the other days as not possible, although I have to go through each day, by day to be assured. And finally I have to do it with a even number of days in the week-- 6 or 8 or 10, to see if even-odd favors a unique solution.
>
> AP
Yes, I see now that it has to be a odd number for a week so as to make Sunday and Monday be truth for unicorn but both days as liaring for lion. If the week had even number of days, you do not get that sameness.
So yes, AP finds a Logical Consistent Puzzle with a Unique Solution answer-- the day is Monday.
AP
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7:17 PM (now)
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So let me try an even number for the puzzle, try 4.
So we have 4 days in a week 1,2,3,4
And the same set-up
Lion: yesterday was a truthful day
Unicorn: yesterday was a truthful day
Lion liars on 1; truth on 2; liars on 3; truth on 4.
Unicorn tells truth on 1; liars on 2; truth on 3; liars on 4.
We have Alice meeting the lion and unicorn and wanting to figure out the day.
Suppose it is __actually and truly day 1___ is that possible? No, for the unicorn tells the truth on 1 and the truth is not that 4 is a truth day.
Are any of the other days possible? No, for the truth spoken by either lion or unicorn contradicts the puzzle of a unique solution. In this case of even 4 days in a week there is no solution.
Now if we throw in there a 5 day week
Lion liars on 1; truth on 2; liars on 3; truth on 4; liar on 5.
Unicorn tells truth on 1; liars on 2; truth on 3; liars on 4; truth on 5.
In this case, again, just like a 7 day week, there is a unique solution of day 1 where the unicorn tells the truth that day 5 is a truthful day. And where the lion liars about day 5.
Now the riddle or puzzle is useless other than a puzzle to play with, except for science and math. We begin to see in this puzzle the idea of a circuit and linked up circuit.
Notice in the Cosmic Abundance of Elements, the odd numbered elements are less abundant than even once we ignore hydrogen.
And better yet in math geometry, the Fibonacci Sequence in a Rectangle of Whirling Squares::
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144,....
For I never noticed before that that vital sequence always has two odds then a even punctuated between two odds.
So what happens to our Alice, Lion, and Unicorn if they liared 2 days, then told the truth the next day, then two more days of liaring. Do we end up with a Unique Solution in a Consistent game?
So what we see as games and puzzles and riddles, are always turned into something of math or science.
AP
Archimedes Plutonium
Nov 6, 2023, 10:53:26 PM11/6/23
to
Alright, I see beautiful application of the Alice-Lion-Unicorn Puzzle Riddle for Information theory, or some would call it the theory of communication. It involves a circular sequence as it starts on Monday and returns to next Monday.
But before I discuss that, I need to see if a 3 day week would also solve the puzzle with a unique solution.
So we have 3 days in a week 1,2,3, then the next week repeats 1,2,3 and on and on.
And the same set-up
Lion: yesterday was a truthful day
Unicorn: yesterday was a truthful day
Lion liars on 1; truth on 2; liars on 3.
Unicorn tells truth on 1; liars on 2; truth on 3.
We have Alice meeting the lion and unicorn and wanting to figure out the day.
Suppose it is __actually and truly day 1___ is that possible? Yes, both lion and unicorn obey the conditions for a solution.
But when we try __actually and truly day 2__ is that possible? No because on day 2 the lion tells the truth and day 1 is not a liaring day. The same goes for day 3, but instead of lion defeating the cause, it is the unicorn who defeats the cause for the unicorn tells truth on that day but day 2 was a liaring day for the unicorn.
So here we see that for the odd number 3 we can have a consistent logic puzzle with a unique solution.
And what I want to glean from this is that we can picture the Light Wave or Photon as carrying information. The information is 1 day of the week we can figure out what day it is from Logical Conditions. Much like one of the magnetic fields or one of the electric field cusps carries the information while all the rest of the cusps are there to just get the Light Wave to its destination.
The number 3 is the first number in physics for which Information or Communication can take place.
If the world of Light Waves and Photons was based on the number 2, nothing in that wave can be recognized as Unique and thus carry no information nor carry communication.
In physics we seem to have 3 essential particles-- muon and proton and neutron. The muon and proton to conduct Faraday law and the neutron to storage the electricity.
The number 3 for the start of uniqueness and thus the start of information or communication theory.
Now one might wonder where are there 3 in a light wave? One cusp is a magnetic field another a electric field, but we seem to forget that what makes the cusps is a particle rolling over a line as in a cycloid wave. So in a Light Wave of bare minimum has this structure:
1) magnetic field space
2) electric field particle in shape of circle
3) electric field particle rolling on magnetic field plane
4) cusp of cycloid wave as a magnetic field cusp
5) cusp of cycloid wave as a electric field cusp
So a Light Wave at bare minimum has 5 entities for its existence. It need only 3 to carry information.
AP
But before I discuss that, I need to see if a 3 day week would also solve the puzzle with a unique solution.
So we have 3 days in a week 1,2,3, then the next week repeats 1,2,3 and on and on.
And the same set-up
Lion: yesterday was a truthful day
Unicorn: yesterday was a truthful day
Unicorn tells truth on 1; liars on 2; truth on 3.
We have Alice meeting the lion and unicorn and wanting to figure out the day.
But when we try __actually and truly day 2__ is that possible? No because on day 2 the lion tells the truth and day 1 is not a liaring day. The same goes for day 3, but instead of lion defeating the cause, it is the unicorn who defeats the cause for the unicorn tells truth on that day but day 2 was a liaring day for the unicorn.
So here we see that for the odd number 3 we can have a consistent logic puzzle with a unique solution.
And what I want to glean from this is that we can picture the Light Wave or Photon as carrying information. The information is 1 day of the week we can figure out what day it is from Logical Conditions. Much like one of the magnetic fields or one of the electric field cusps carries the information while all the rest of the cusps are there to just get the Light Wave to its destination.
The number 3 is the first number in physics for which Information or Communication can take place.
If the world of Light Waves and Photons was based on the number 2, nothing in that wave can be recognized as Unique and thus carry no information nor carry communication.
In physics we seem to have 3 essential particles-- muon and proton and neutron. The muon and proton to conduct Faraday law and the neutron to storage the electricity.
The number 3 for the start of uniqueness and thus the start of information or communication theory.
Now one might wonder where are there 3 in a light wave? One cusp is a magnetic field another a electric field, but we seem to forget that what makes the cusps is a particle rolling over a line as in a cycloid wave. So in a Light Wave of bare minimum has this structure:
1) magnetic field space
2) electric field particle in shape of circle
3) electric field particle rolling on magnetic field plane
4) cusp of cycloid wave as a magnetic field cusp
5) cusp of cycloid wave as a electric field cusp
So a Light Wave at bare minimum has 5 entities for its existence. It need only 3 to carry information.
AP
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