+AP's 151st book TEACHING TRUE PHYSICS, 1st year College, 2021 soon to be published
Archimedes Plutonium<
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Apr 4, 2021, 12:51:22 PM (2 days ago)
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Call it the NEW ERA RUTHERFORD-GEIGER-MARSDEN-EXPERIMENT
Where we take a Galvanometer and attach it to the 1911 Rutherford experiment gold leaf foil.
We measure the electricity produced because of the alpha particles thrusting through the proton toruses of gold atoms.
Looking for the prediction formula of how much electricity is produced.
The Prediction formula must be on the order of Emf = N * B * velocity * Length
B = tesla= magnetic flux density, I have no idea what a alpha particle B field is
N = windings, and here I need to equilibrate how many windings a gold foil represents
velocity, that is easy for the alpha particles are going a 5% speed of light into the gold proton toruses
Length, well that is the length of the gold leaf foil. I think some websites specified Rutherford-Geiger-Marsden actual length. But here I maybe concerned in making the gold leaf itself go all the way around and be a circuit gold leaf, as the electricity produced in Faraday law from inside of protons need to flow. Of course we attach a Galvanometer and what is the best engineering attachement? I suppose alligator clips at worst, maybe something better. Whatever the connectors are, should not be part of the alpha particle target.
We should get a prediction Amperage before doing the experiment. Perhaps 1 amp or more. Keeping in mind alpha particles are going very fast.
You see, it is this kind of Experiment with a prediction beforehand that Physics of the 20th and 21st century need to be doing, and not their dreadful horrible assinine postdiction of the Standard Model, a mindless game that never predicted a single thing.
AP
King of Science, especially Physics
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Archimedes Plutonium<
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Apr 4, 2021, 2:36:31 PM (2 days ago)
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On Sunday, April 4, 2021 at 12:51:22 PM UTC-5 Archimedes Plutonium wrote:
Call it the NEW ERA RUTHERFORD-GEIGER-MARSDEN-EXPERIMENT
Where we take a Galvanometer and attach it to the 1911 Rutherford experiment gold leaf foil.
We measure the electricity produced because of the alpha particles thrusting through the proton toruses of gold atoms.
Looking for the prediction formula of how much electricity is produced.
The Prediction formula must be on the order of Emf = N * B * velocity * Length
I am not in luck, for I see no-one ever measured the magnetic field around a alpha particle.
That means the above formula will have to find out the Magnetic Field once the experiment is completed. And the above formula will be a tool in finding the alpha particle magnetic field, but since we do not know the magnetic field before we do the experiment, means we cannot predict the amperage in the current from the alpha particles thrusting through the gold leaf protons inside of gold.
Here at home in my lab, I just conducted a experiment of the Faraday law where I entered a north magnet at one end of the coil and a south magnet at the other end of the coil and found that the needle on the galvanometer moved off the scale. A far larger reading than just entering one magnet in the coil.
This tells me that when a alpha particle enters a proton torus of gold and is met by the oncoming 79 muons moving in opposite direction, that a bountiful of electric current is produced. So every large angle recoil of alpha particles in Rutherford's gold leaf is also the largest electricity production.
So if the alpha particle magnetic field has never been measured, the AP remake of Rutherford Experiment will measure the alpha particle magnetic field.
B = tesla= magnetic flux density, I have no idea what a alpha particle B field is
N = windings, and here I need to equilibrate how many windings a gold foil represents
velocity, that is easy for the alpha particles are going a 5% speed of light into the gold proton toruses
Length, well that is the length of the gold leaf foil. I think some websites specified Rutherford-Geiger-Marsden actual length. But here I maybe concerned in making the gold leaf itself go all the way around and be a circuit gold leaf, as the electricity produced in Faraday law from inside of protons need to flow. Of course we attach a Galvanometer and what is the best engineering attachement? I suppose alligator clips at worst, maybe something better. Whatever the connectors are, should not be part of the alpha particle target.
We should get a prediction Amperage before doing the experiment. Perhaps 1 amp or more. Keeping in mind alpha particles are going very fast.
You see, it is this kind of Experiment with a prediction beforehand that Physics of the 20th and 21st century need to be doing, and not their dreadful horrible assinine postdiction of the Standard Model, a mindless game that never predicted a single thing.
AP
King of Science, especially Physics
This experiment is of top priority in all of physics, for it not only proves what the real structure of interior of atoms is. But it also teaches us the axiom that All is Atom, and atoms are nothing but electricity and magnetism.
AP
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Archimedes Plutonium<
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Apr 5, 2021, 11:55:29 AM (yesterday)
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Today I call into question the idea that Beta decay is merely Faraday Law of atoms with excess neutrons. Neutrons are capacitors and thus atomic-batteries, that leak out electricity. So in the gold leaf Rutherford experiment, as we attach a Galvanometer, we are reading in one sense beta decay and in another sense the Faraday law of alpha particles thrusting through the proton coils of the 79protons in each gold atom.
In this sense, there should be a radioactive Beta emitter that you cannot tell the difference on whether it is a well kept battery of ordinary material, or whether it comes from a lump of radioactive material.
Here we blurr the lines between what we call a battery making electricity and what we call an element that is emitting electricity by particles inside its atoms thrusting through proton coils.
AP
King of Science, especially Physics
AP
King of Science, especially physics
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Archimedes Plutonium<
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Apr 5, 2021, 1:05:15 PM (yesterday)
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I do not know how many of these beta emitters rivals the very best batteries ever made. If I recall correctly, beta emitters were used in the robots sent to Mars and outer space. They must be more reliable and far more efficient than any other type of battery. Of course, in AP theory, beta emitters are just Faraday law on the scale of the protons inside of atoms. So we need to take Beta decay out of radioactivity and place it into the section of physics teaching into the Maxwell Equations section of physics textbooks.
--- quoting Wikipedia ---
Strontium-90 is a commonly used beta emitter used in industrial sources. It decays to yttrium-90, which is itself a beta emitter. It is also used as a thermal power source in radioisotope thermoelectric generator (RTG) power packs. These use heat produced by radioactive decay of strontium-90 to generate heat, which can be converted to electricity using a thermocouple. Strontium-90 has a shorter half-life, produces less power, and requires more shielding than plutonium-238, but is cheaper as it is a fission product and is present in a high concentration in nuclear waste and can be relatively easily chemically extracted. Strontium-90 based RTGs have been used to power remote lighthouses.
--- end quoting ---
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Archimedes Plutonium<
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Apr 5, 2021, 1:39:16 PM (yesterday)
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Now, also as we place Beta decay out of radioactivity, leaving radioactivity only as a neutron emmission or a alpha particle or larger emission. For beta decay is not really radioactivity, but is part of electricity and magnetism of the Faraday law.
But also, I need to know if we attach a galvanometer to a element like Pu238, whether we get a electricity reading. Sort of think of 238Pu as a electric generator in and of itself. You need nothing to add to the slab of Pu238 to generate electricity, it is all self contained generator.
AP
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Archimedes Plutonium<
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Apr 5, 2021, 4:53:10 PM (yesterday)
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Probably not that lucky to be able to connect a Galvanometer directly to a metal or ore and immediately get a current reading. Metals that are radioactive have surprisingly high conductivity of strontium of 7.7*10^6 S/m or thorium at 6.7*10^6 S/m or uranium at 3.6*10^6 S/m or radium at 1*10^6 S/m. And it is this fact that I want to exploit, by showing that radioactive beta decay is in essence, electricity production inside of those elements proton toruses.
Considering copper has 5.9*10^7 S/m and the highest of silver at 6.2*10^7 S/m with iron being 1*10^7 S/m. Happy to see lithium is 1.1*10^7 S/m and Beryllium is 2.5*10^7 S/m. But carbon is a mere 1*10^5 S/m. Sodium is surprisingly large at 2.1*10^7 S/m. Silicon is so small and obviously a semiconductor at 1*10^3 S/m. But phosphorus, a heavy element for life right up there at 1*10^7 S/m. Whereas sulfur is incredibly small at 1*10^-15 S/m. Radioactive plutonium is 6.7*10^5 S/m, and neptunium at 8.3*10^5 S/m.
So, if we wound strontium or thorium into a wire and thrust a bar magnet we should see a reading on the Galvanometer.
But should we thrust the same bar magnet through beta radioactive emitter strontium, should the Galvanometer reading be far higher due to the fact that the radioactivity is thrusting through the strontium proton toruses causing additional electricity.
What I am going to argue here, is to remove Beta decay from radioactivity in physics, and place beta decay as not radioactivity but the mere production of electricity due to the fact that atom's protons are coils for which the thrusting muon and other particles create electricity and the 0.5MeV Dirac magnetic monopole.
In other words radioactivity is a science of neutron emission, of alpha particle emission and of large particle emission, even SF, spontaneous fission. But beta emission is part of physics of the electromagnetism chapter, the Maxwell Equations chapter should deal with beta emission, not the radioactivity department of physics.
AP
King of Science
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Archimedes Plutonium<
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Apr 5, 2021, 5:35:11 PM (yesterday)
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EXPERIMENT
So, what I need to prove is that radioactivity of Beta decay is not really radioactivity at all but is the natural process of creating Dirac magnetic monopoles in proton toruses inside of atoms and then storaging those monopoles in neutrons acting as capacitors.
So, we get strontium-90, the beta emitter and we form it into a coil wire for a Faraday law experiment thrusting through the strontium 90 with bar magnet. It should give a current reading.
Now we do the identical same thing with stable strontium, build a wire coil, thrust a bar magnet and get a electrical reading from Galvanometer. All things being equal except one uses radioactive strontium while the other uses stable strontium.
What should the end result be? I am guessing the current in stable strontium is far less than the current in beta emitter strontium.
AP
King of Science
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Archimedes Plutonium<
plutonium....@gmail.com>
Apr 5, 2021, 9:37:52 PM (yesterday)
to Plutonium Atom Universe
Call it the NEW ERA RUTHERFORD-GEIGER-MARSDEN-EXPERIMENT
Where we take a Galvanometer and attach it to the 1911 Rutherford experiment gold leaf foil.
We measure the electricity produced because of the alpha particles thrusting through the proton toruses of gold atoms.
Looking for the prediction formula of how much electricity is produced.
The Prediction formula must be on the order of Emf = N * B * velocity * Length
I cannot find a known measure of the B field for alpha particle. I thought of using the B field of hydrogen proton and neutron and multiply by 2. But that is only a speculation and makes a horrible prediction.
So for the Experiment, if it has a current, it would be able to determine the B field of alpha particle for we would have the EMF the N the velocity and the length. Thus determine the B-field.
So if it works, then AP has created a new physics tool for measuring the B field of particles.
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Archimedes Plutonium<
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Apr 5, 2021, 11:26:11 PM (yesterday)
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On Monday, April 5, 2021 at 4:53:10 PM UTC-5 Archimedes Plutonium wrote:
Probably not that lucky to be able to connect a Galvanometer directly to a metal or ore and immediately get a current reading. Metals that are radioactive have surprisingly high conductivity of strontium of 7.7*10^6 S/m or thorium at 6.7*10^6 S/m or uranium at 3.6*10^6 S/m or radium at 1*10^6 S/m. And it is this fact that I want to exploit, by showing that radioactive beta decay is in essence, electricity production inside of those elements proton toruses.
Has anyone found that when you dope silicon with thorium or radium or uranium that you increase silicon's conductivity?
Considering copper has 5.9*10^7 S/m and the highest of silver at 6.2*10^7 S/m with iron being 1*10^7 S/m. Happy to see lithium is 1.1*10^7 S/m and Beryllium is 2.5*10^7 S/m. But carbon is a mere 1*10^5 S/m. Sodium is surprisingly large at 2.1*10^7 S/m. Silicon is so small and obviously a semiconductor at 1*10^3 S/m. But phosphorus, a heavy element for life right up there at 1*10^7 S/m. Whereas sulfur is incredibly small at 1*10^-15 S/m. Radioactive plutonium is 6.7*10^5 S/m, and neptunium at 8.3*10^5 S/m.
Here I am asking to see if Carbon 14, the beta emitter is more conductive than the normal carbon.
The beta emitter sodium 24, is that a higher conductor than the normal sodium.
So, if we wound strontium or thorium into a wire and thrust a bar magnet we should see a reading on the Galvanometer.
But should we thrust the same bar magnet through beta radioactive emitter strontium, should the Galvanometer reading be far higher due to the fact that the radioactivity is thrusting through the strontium proton toruses causing additional electricity.
What I am going to argue here, is to remove Beta decay from radioactivity in physics, and place beta decay as not radioactivity but the mere production of electricity due to the fact that atom's protons are coils for which the thrusting muon and other particles create electricity and the 0.5MeV Dirac magnetic monopole.
In other words radioactivity is a science of neutron emission, of alpha particle emission and of large particle emission, even SF, spontaneous fission. But beta emission is part of physics of the electromagnetism chapter, the Maxwell Equations chapter should deal with beta emission, not the radioactivity department of physics.
The fact that beta emission is every element up until you get to the real heavy radioactive elements, is strong indication that Beta emission is not a subject of radioactivity. But that Beta emission is about the Faraday law of protons in atoms. And a simple proof of this would be to find where instead of a helium alpha particle of +2 is found, instead a helium -2 is found, the exact opposite, because the beta particle is a magnetic monopole attached to a helium atom. This would include also a alpha particle of +0, neither +2 or -2. Beta particles are magnetic monopoles that jump aboard a alpha particle and take a free ride out of the atom. And I would not be surprised at all if there were an alpha particle of +1 or -1, mind you still 2 protons and 2 neutrons but with just one magnetic monopole free rider.
AP
King of Science
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Archimedes Plutonium<
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1:49 AM (yesterday)
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--- Quoting from the web a anomaly on beta decay ---
But what the GSI guys found was stranger still. They discovered that the normal exponential decay rate of praseodymium and promethium oscillated with a period of about 7 seconds. It was as if an oscillation had been superimposed on the normal exponential decay curve.
Their experiment is interesting because it is unique. These guys produce a handful of ions in a synchrotron and the measure each one decaying by the change it produces in the resonance of the ion beam as it circulates.
--- end quote ---
And this is a perfect anomaly to explain by AP with his theory that Beta decay is not even radioactivity, but belongs in the department of physics called Maxwell Equations and the Faraday law. For you see, beta particles are not electrons nor positrons but are Dirac magnetic monopoles, created by the muons thrusting through proton toruses and then these monopoles are usually ushered into a nearby capacitor of a neutron for storage and reformation.
A perfect anomaly, and I love the explanation because it shows how awful and horrible is a mind in physics that has no logical brains.
The quote from the above is from
technologyreview.com at MIT titled Radioactive Decay Anomaly Finally Explained (Maybe)
Well, AP has a logical mind, a rare commodity in science, and so, reading this article I come upon this passage.
"These guys were measuring the radioactive decay rates of praseodymium and promethium nuclei that had been stripped of all but one or two of their electrons, leaving them with a charge in excess of +50."
Alright, well to a kook physicist, all that sounds reasonable, good and well. To a logical minded physicist, how can you even have a atom if you strip away most of its electrons. So in the above, we can see that stupid people in physics imagine that a atom can be stripped almost clean of electrons and still be say praseodymium and promethium.
Whereas AP would say, you stripped away not the electrons, for the muons inside of protons, the muons are the real electrons of atoms doing the Faraday law inside of protons and doing the Faraday law in order to create the Dirac magnetic monopoles, for which these kook physicists thought were electrons.
So, here is an experiment from Germany where they remove almost the entire lot of Dirac magnetic monopoles from atoms of Pr and Pm and still retain being atoms of Pr and Pm.
So, how painful is it, to think physicists can believe they removed electrons and still be a Pr and Pm.
And as for the anomaly problem, Dirac magnetic monopoles are dipoles and are light waves so that you can influence them in their closed loop circuit of light waves.
What I like about this anomaly, is that I not only answer the problem, but show the physics community, that the 0.5MeV particle was never the true electron of atoms. If you strip an atom of protons you destroy that atom. Likewise, if you strip the true electron = muons of an atom you again destroy the atom.
So sad, so sad that thousands enter physics, but few have a logical brain to stand upon.
AP
King of Science, especially Physics
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Archimedes Plutonium<
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3:10 PM (3 minutes ago)
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Let us start with the first element in the Periodic Table that is visible and not a gas. Start with lithium and then beryllium.
Now, why are almost all physicists mindless fools of physics, to ever think that if you remove 3 electrons of lithium, you still have lithium? They sure were fooled on helium, for all of them from 1900 to 2020 thought you could remove 2 electrons of what they called 0.5MeV particles as electrons, they thought you could have helium atoms with two missing electrons.
Of course if we were to ask these fools, ask them, if you remove just one proton from helium, would you have helium? And they all chimed in saying, no, removal of just one proton and you have a different atom.
But if you asked them remove just one electron of 0.5MeV or even two electrons of 0.5MeV, again the bozos would chime in-- you still have helium.
Against this backdrop of fools of physics steps in AP. AP says that the real electron of atoms is a muon of 105MeV stuck and trapped inside a proton torus of 840MeV doing the Faraday law. So, now, remove one single muon from helium, you would have to remove a proton also, because you cannot remove the muon stuck inside the proton torus. Not even stars are able to remove the muon out of a proton torus.
So, where does all of this leave Physics? It leaves physics with the idea, that the 0.5MeV was never the electron of atoms but the product of what the muon and proton torus created the 0.5MeV particle.
So, can the bozo physicists ever admit or realize that you can remove not only 3 of those 0.5MeV so called electrons from lithium, but remove 4 or even 5 of those 0.5MeV particles from lithium and you still have remaining in your laboratory, still have remaining lithium atoms. You can call them ionized lithium, meaning only, that you drained or removed Dirac Magnetic Monopoles, but you cannot call them lithium atoms with removed electrons for the 3 muons inside every lithium atom is still there.
Same goes for beryllium, you can remove 4 of those 0.5MeV particles, even 5 or 6 of those particles and still it is beryllium because you never removed a single muon of beryllium.
This is why the website on the GSI experiment calls to question all the anomalies, the very very strange behavior of praseodymium and promethium, the strange behavior when you remove 50 particles of 0.5MeV from those atoms. Strange behavior, but still the same atoms, because not a single muon was removed. GSI was playing around with Dirac Magnetic Monopoles of 0.5MeV, not with electrons of atoms.
Can the physicists of this generation ever grow up about physics? I doubt it. Once they are brainwashed in their beliefs that the 0.5MeV particle is a atom's electron, they, in my estimation will forever be worthless nattering nutter fools of physics. Almost impossible to get their brainwashed minds to think-- "real electron is the muon trapped inside a proton torus".
AP
King of Science, especially Physics
More people reading and viewing AP's newsgroup than viewing sci.math, sci.physics. So AP has decided to put all NEW WORK, postings only to his newsgroup. And there is little wonder because in AP's newsgroups, there is only solid pure science going on, not a gang of hate spewing misfits blighting the skies.
In sci.math, sci.physics there is only stalking hate spew of no value and other than hate spew there is Police drag net spam day and night.
I re-opened the old newsgroup PAU of 1990s and there one can read my recent posts without the hassle of stalkers and spammers, book and solution manual spammers, off-topic-misfits, front-page-hogs, churning imbeciles, stalking mockers, suppression-bullies, and demonizers. And the taxpayer funded hate spew stalkers who ad hominem you day and night on every one of your posts.
There is no discussion of science in sci.math or sci.physics, just one long line of hate spewing stalkers.
Read my recent posts in peace and quiet.
https://groups.google.com/forum/?hl=en#!forum/plutonium-atom-universe
Archimedes Plutonium