mandag 21. mai 2018 00.44.31 UTC+2 skrev Archimedes Plutonium følgende:
> Proof that KON is a worthless idiot of Math alongside Wiles on FLT
>
> On Sunday, May 20, 2018 at 4:16:11 PM UTC-5, konyberg wrote:
> > søndag 20. mai 2018 22.53.07 UTC+2 skrev Archimedes Plutonium følgende:
>
> > > > Do you really think that two of A, B, C can be even and the third odd?
> > >
> > > Alright, my typo mistake-- only two odds with 1 even, never two evens with one odd.
>
> A rushed typo mistake on my part.
>
> > >
> > > > If all are even, can we not reduce it?
> > > > KON
>
> Now Euler had no Formal Logic way back in his day, so we can excuse Euler for his mistake. And his mistake was to think, --- we need only the case where two of A,B,C are odd and the third being even, for we all know arithmetic that two odds make an even. And this is why we cannot have two evens make a odd.
>
> Even KON and Wiles know that much.
>
> But, where all three fail, and Euler can be excused because there really was no LOGIC, formal logic at his time. For it was in Euler's mind that Suppose three evens exist that fulfill A^3 + B^3 = C^3, and all three are even, then we can say we can reduce to A,B,C where two are odd and one even. But--- you see the logical SUPPOSE that were true of a A^3 + B^3 = C^3, was true then you can extract out the two odds and one even.
>
> But, that is a DOUBLE Supposition.
>
> The FLT that needs proving is look at this sequence
>
>
> exp3 {1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, . .}
>
>
> And prove that any three A, B, C add up to where A+B= C
>
> So, we can have Euler's two odd and one even
>
> But, we can have three evens of A,B,C which is independent of the two odds and one even. Totally independent and has to be proven separately.
>
> You cannot do what Euler did--- Suppose A,B,C solve A^3 +B^3= C^3 with two odds and one even, and then add a second dependent Supposition if A^3 +B^3 = C^3 with all three even reverts to two odds and one even.
>
> All of this is far over the head of KON who is an insane Norwegian stalker and never a mathematician
>
> But, none of that above is over the head of Wiles, who upon reading the above, can see that you cannot SUPPOSE true A^3 +B^3 = C^3 as A,B,C all three even and then say-- it reverts back to 2 odd and 1 even.
>
> The proof of FLT is show no three A,B,C of the sequence
>
> exp3 {1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, . .} has a solution
>
> And each case of two odds,one even is proven separate of the case of three evens.
>
> I do not expect KON to have, ever, one gram of Logical thinking, that he could ever realize the proof of FLT is not suppose true, then go back and say two odds and one even. For KON is logically insane.
>
> I do not expect Euler to have realized his mistake, for formal logic did not exist in his time and place.
>
> However, I do expect Andrew Wiles to have at least a gram of a logical mind to realize this sequence
>
>
> exp3 {1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, . .}
>
> has to be proven independently of two odds with one even and independent of three evens.
>
>
> > >
> > > No, cannot be reduced as the below Generalized FLT shows a plethora of solutions when A,B,C, all three are even. So what Euler proved was only the case of A,B,C two odds and one even has no solutions in exponent 3 but, Euler failed to prove all exponent 3 has no solutions. Only by proving FLT itself--the entirety of FLT in all exponents, do we prove A,B,C evens have no solution in exponent 3.
> > >
> > >
> > > The number Space that governs FLT is this:
> > >
> > > exp3 {1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, 1331, 1728, . .}
> > >
> > > exp4 {1, 16, 81, 256, 625, 1296, 2401, 4096, 6561, 10000, . .}
> > >
> > > exp5 {1, 32, 243, 1024, 3125, 7776, 16807, 32,768, 59,049, 100,000, 161,051, 248,832, 371,293, . .}
> > >
> > > exp6 .....
> > > .
> > > .
> > > .
> > > .
> > >
> > > Now in the proof of Generalized FLT, solutions of A + B = C require a common divisor.
> > >
> > > 2^3 + 2^3 = 2^4 with prime divisor 2 A,B,C all evens
> > > 3^3 + 6^3 = 3^5 with prime divisor 3 two odds, one even
> > > 7^3 + 7^4 = 14^3 with prime divisor 7 two odds, one even
> > >
> > > It is mistakes like this, that Wiles should have spotted in Euler, before he made is silly stupid mission to conquer FLT and for which he ends up with a fakery of math.
> > >
> > > AP
> >
> > Can you show me one equation (which we are talking about) where all are even, and cannot be reduced to a fermat equation?
> > That is two of A, B, C odd and the third even.
> > KON
>
> You see the trouble with the insane KON, is he knows little math, and all he wants to do is hassle people, stalk people.
>
> KON belongs in a Norwegian psychiatric home.
>
> But Wiles should have caught Euler's mistake. For Formal Logic is prevalent in the 20th century and no excuse can be made for not realizing a Logical ARGUMENT cannot have two suppositions.
>
> The proof of FLT is to show no three numbers A,B,C can solve A+B=C in that sequence, and 2odds1even case is independent of 3evens case.
>
> AP
I do know how to divide by 2.
Do you?
KON