gravity begins with the proton

[haroldj...@gmail.com]

Where under a cloud when it comes to gravity, the Gravitational Constant and consequently an exact given value for the Planck units. We're forever being told
how the next series of measurements will confirm these phenomena once and for all.

We do have templates to give us some idea but only templates. The most useful are the Gc templates. Many of the values in physics are factorised by Gc or (Gc/2)^0.5
without us realising it.

By using 2/c as substitute for G we get the following:

(1). In the formula for the Planck mass, (ch/4G)^0.5, when substituting 2/c for G
we arrive at 2.72837394x10^-9, quite recognisable as the Planck mass except it is out by a factor of (GC/2)^0.5.

(2). The same principle can be applied to the Planck radius, formula (Gh/c^3)^0.5.
This time we end up with 4.050436x10^-34.

(3). The ratio of Strong force over gravity, 2.660725x10^38, based on
(Mpl/Mpr), where Mpl is Planck mass and Mpr is proton mass. Appying the above criterion the Gm template becomes 2.66079655x10^36.

(4). Mpr/h is equal to (1.009721668x10^7)/4. The quantum adjustor, qa, is equal to 4/{4h(c/2)^4}^0.333r=3.62994678, the quantum adjustor. 4/qa is equal to 1.10194453. 1.10194453xGc. If the radius of the proton was equal to the Planck Radius then the total energy given to a falling Planck sphere would be
1.10194453xGm/4 x Mpl=1.503278583x10^-10 J. The total energy of the proton.
(1.503278583x10^-10)(1.009721668x10^7)=1.51789295x10^-3.
2/1.51789295x10^-3=1.317615975x10^3. The square root of this is 3.629898x10.
Accepting there might be a small drift from the theoretical qa it can still be assumed that Gm/2 is around 1/100.

(5). The analogue to 1.009721668x10^7 is 1.11585396x10^-35. This value multiplied by qa is the Planck radius. It is found by the formula 2Mpr/c
and is removed from GMpr by the familiar differential Gc.

[haroldj...@gmail.com]

On Saturday, 17 May 2014 18:39:09 UTC+1, haroldj...@gmail.com wrote:
> We're under a cloud when it comes to gravity, the Gravitational Constant and consequently an exact given value for the Planck units. We're forever being told

FINDING METRES FROM PLANCK TEMPLATES:

(6). By using the Gc template for Planck mass, 2.72837394x10^-9, see item (1) and dividing by the proton mass then squaring the result, we get 2.66079655x10^36, see item (3).

(7). If we multiply the proton mass by 1.00972168x10^7, see item (4), we get
1.688883686x10^-20. The reciprocal squared equals (5.92107087x10^19)^2 =
3.50590803x10^39, which equals (Mpl/Mpr)^2 multiplied by (qa)^2, or,
2.660725x10^38x(3.62994678)^2, see item (3).

(8). If we multiply 3.505908x10^39 by 1.11585396x10^-35, see item (5), we get
3.912081282x10^4 metres.

3.912081282x10^4 metres will be the Schwarzschild radius for a body of mass equal to 2.660725x10^38 Planck masses and then multiplied by (qa),appx. 3.62994678.

(9). There is a number, around 8.179349, that when divided by c gives us the Planck mass. When divided into the Planck constant gives us the Planck length,
when multiplied by c gives us the Planck energy and when multiplied by (c^2/h)
gives us the surface gravity of the Planck sphere. The (Gc/2) version is
0.817945942. We know this because this quantum number formula must be:

(hc^3)/4G=(number)^2.

If we replace G with 2/c we get a formula: (hc^4)/8=0.817945942)^2.

0.817945942x(qa)=2.96910024.

3.629897995x10, see item (4), has been thoroughly investigated and is proven to be qa/Gc/2)^0.5. And;

2.96910024x3.62989799x10 is equal to 1.077753101x10^2. This is the Schwarzschild radius of the mass equivalence of (GC template) 2.66079655x10^36
Planck masses. 1.0777531x10^2 is universal. Whatever the change from the kilogram/second there is there will be a corresponding change in the actual value of the metric and a nominal change in qa. Each time the differences cancel out and the result stays at, nominally,1.0777531x10^2 m.

10. 3.912081282x10^4, see item (8), divided by 1.0777531x10^2, equals

3.629849247x10^2, which is qa divided by Gc/2. The reciprocal, 2.75493534x10^-3,
is equal to the escape speed from a proton surface where radius is equal to the Planck radius.

[haroldj...@gmail.com]

The magic of 1.08823067x10^9 and what to name it.

It is c(qa) or c times 3.62994678 in SI units.
It emerges from Ch/4, 4.966118653x10^-26, the G(Mpl)^2 product where Mpl is equal to the Planck mass. 1/4.966118653x10^-26=2.013645x10^25. (2.013645x10^25)^0.3333r
is equal to 2.72057667x10^9. Multiply this by 4 and you have 1.08823067x10^9.
If you multiply our SI system's timescale mass GM structure, 6.7360006x10^24, by
(2.72057667x10^9)^3 you arrive at c^2/h or 1.356391399x10^50. This new Gm structure differs from an SI system structure in that its local mass unit is 2.72057667x10^9 lighter than the kilogram and local c is greater by 2.72057667x10^9 but the metre is the same as the SI system. Think of the CGS system. In such a system the the local GMpl^2 GM structure amounts to one.
Therefore local Planck mass approximates to the proton opposite's Gm product, 29.6906036, divided by 4 or 7.4226509. Square this and you get 55.09574638.
Therefore local G must equal the inverse of this. If we double this to 110.1014928 we have a value that is related to 1.10194453. This is how:

There is a number at the heart of physics I call the quantum number. It approximates to 8.17934956. One of its functions is to convert c into the Planck
mass, 8.17934956/c=Mpl. In my past list of Gc templates I substituted 2/c for G
to give an analogue of the Planck mass of 2.72837394x10-9. Multiply this by c and you have 0.81794593. Multiply h by 2(c/2)^4=0.66903556 and the square root of this is 0.8179459. 0.66903556x2=1.3380711 and the cube root of this is 1.10194453. divide this by 2 and you have 0.550972265 and the square root is 0.74227506 an analogue of 29.6906036/4. And 7.4227506 divided by our analogue Planck mass, 2.72837394x10^-9 comes to 1.08823067x10^9. An obvious parallel match.

All of physics seems to be about replicating numerically what we see. We are no closer to understanding what we see than scientific thinkers were in Newton's time. Take the Rydberg energy, somewhat later than Newton but empirically put together, 2.17987417x10^-18 J. Then take the Gm product GMpl^2, hc/4, 4.966118653x10^-26. Multiply by 2c and you have 7.444024589x10^-18. Divide this by the Rydberg energy, 2.17987417x10^-18 and you have 3.41488728. This number just happens to be the local quantum adjustor for another system where the local mass unit is 1.062977 times lighter than the kilogram hence 3.41488728x1.062977=3.62994678 and 4/3.62994678=1.10194453. So why is this? You could say it's the wrong equation. Take a look:

What we have here is what seems to be and what actually is in the nature of being.
We seem to be dealing with the Gm product, GMpl^2, 4.966118653x10^-26. This numerical value when divided by the proton opposite's Gm product, 29.6906036,
comes to 1.672623x10^-27, the proton mass and therein lies the answer to the riddle. It is not directly about GMpl^2 this time but it does involve the Planck mass.

It is about difference between the Planck energy, (Mpl)c^2 and the Rydberg energy, 2.452107x10^9/2.179874x10^-18=5.62442419x10^26. The problem might be better understood if we look at the reciprocal, 1.777959779x10^-27. This value is 1.062977 greater than the proton mass. What the formula was trying to do was
multiply the Planck energy by 1.777959779x10^-27 which of course comes to the Rydberg energy, total energy this time. But what you must know is that the Planck energy has another composition. It is 29.6906036/3.62994678 and then multiplied by c. So it goes through the same procedure but with 1.777959779x10^-27 instead of the proton mass.

If we take another look at this number, 3.4148874, we can still find a relationship with the SI system.
29.6906036/3.62994678=8.17934956 which approximates to the quantum number. Divide this by 3.4148874 and we find 1.19760167. Where does this come from?
We arrive at the Rydberg energy as follows:

The Rydberg constant, 1.0973732x10^7xcxh. But this is the same as writing it down as:

1.0973732x10^7 x GMpl^2 x 4. What this tells us is there is a close numerical bond between the Planck mass and the nominal values of energy.
If we take away G we arrive at 4x1.0973732x10^7 xMpl^2=Planck mass multiplied by 1.19760167. So that's where it came from.

[haroldj...@gmail.com]

In John D Barrow's book, The Constants of Nature, he writes of correspondence
between Einstein and a friend, Ilse Rosenthal-Schneider. They had a running debate about the constants of nature and the need to seek out a pure number
system when constructing constants. John Barrow rounds up the debate by basing
such a system on the Planck/proton ratios.

Such a system can be constructed by using the difference between the proton energy, Mprc^2 and the Rydberg energy, 2x2.179874x10^-18 J, which comes to 3.4480856x10^7, and using the reciprocal in place of the Planck mass,2.90016x10^-8. The next thing we need to do is find the difference between the Planck energy, Mplc^2, and the Rydberg energy, see above, which comes to 1.77795984x10^-27, which differs from the nominal value of the proton mass by 1.062977. Using this new value in place of the proton we can continue.

The following adjustors can be worked out and used to put in place a completed symmetrical pure number system to rival the SI system. All these values and ratios are mentioned above:

(1) 1.0973732x10^7/1.009721668x10^7=1.086807657.
(2) 1.086807657/1.1094453= 1.1976017.
(3) (C/8)/1.0973732x10^7= 3.414887.
(4) C/3.4480856x10^7= 8.69446077.
(5) 8.69446077/3.41488722= 1.273023.
(6) 1.273023/1.1976017= 1.062977.
(7) 8.69446077x1.273023= 11.06824853.
(8) 1.273023x1.1976017x(1.062977)^2=1.72264721.
(9) 11.06824853/2= 5.534124266.
(10) 2(5.534124266)^2= 61.2530628.

From these adjustors can be worked out everything needed in a new symmetrical
pure number system.

The adjustmenst from the SI System are as follows:

Cx1.273023= 3.81642653x10^8= new C.
G= 1.29480892x10^-10.
hx1.7226472= 1.141439047x10^-33.
1.777959779x10^-27= Proton mass in new units.
(1.777959779x10^-27)^2= 3.161140976x10^-54.
3.1611409779x10^-54 is Schwarzschild radius of proton in the new units.
3.75515358x10^-18 is the new value for the Rydberg energy.
5.156367493x10^-35, new value for Planck radius.
61.25306279 is new unit value for GM product 29.6906036, the proton opposite.
1.32141x10^-15mx1.273023=1.6821853x10^-15= new Compton wavelength of proton.
1.6821853x10^-15/3.1611409779x10^-54=2.660725x10^38 which is equal to (M/m)^2
where M is Planck mass and m is proton mass.

[haroldj...@gmail.com]

The advantage of a pure number system is that there are a number of known unknowns
that coincide with a number of known knowns, to quote Donald Rumsfeld.
For instance, there will be no quantum adjustor because all the quantum adjustor does is correct the asymmetry of a non pure number system. It turns out that in a pure number system several values are nominally identical for what turns out to be obvious reasons.

(1)Take the pure number system G, 1.29480892x10^-11. Now take the proton energy,
mc^2, 1.777959779x10^-27x(3.81642653x10^8)^2=2x1.2948089x10^-11. G is nominally equal to the proton energy.

(2) Take the Gm product of the Planck mass, using pure number system units from above, 3.75515358x10^-18, which is nominally the same as the local Rydberg energy.

(3) Local Planck mass, 2.90016x10^-8, squared comes to 8.410928x10^-16.
Now work out the proton Compton wave length using the above local units:
h/mc=(1.141439047x10^-33)/(1.777959779x10^-27x3.81642653x10^8)=2x8.4109275x10^-16.

Looking at these figures the first thing that becomes apparent is that in these
wave structure energies the 'mass' of the wave structure becomes the Planck radius, locally, 5.156367493x10^-35. Multiplied by c^2 this becomes, in local units, 2x3.755153363x10^-18, either the Rydberg energy or the Planck mass GM product, take your pick.

What is also surprising is that there was no manipulation of the figures to get this result. 1.77795779x10^-27 was originally and still is the ratio between the Rydberg energy and the Planck energy, (Mpl)c^2. 2.90016x10^-8 was the ratio between the proton and Rydberg energies. I never dreamt that this last figure
would morph into the Planck mass. Yet a quick check, x/y, shows their ratio as
1.6311729x10^19, the square root of the ratio between strong and gravitational forces.

In the eyes of nature, when associated with more natural constants,
G is the proton energy;
GMpl is the Rydberg energy;
and the Planck mass squared is the Compton wavelength of the proton. A quick check with SI system constants with a current G will show a constant differential proportional with this pure number model.

[haroldj...@gmail.com]

THE PURE NUMBER SYSTEM

There is only one pure number system and this is it.

There are four main elements in any system, SI or otherwise.
They are:

(1) Mass.
(2) Length -> space.
(3) Time.
(4) Energy.

In the last mailing the second was used as the time unit. Now, it would be a miracle if any of the above elements had their nominal values coincide with the ultimate pure number system's. What is rather intriguing is how closely the SI system does shadow its pure number counterpart particularly when you consider the random historical development of the various measurements concerned.

The following table brings the changing time unit into the fold and gives the differentials between Pure Number and SI.

(1) Mass: Pure Number mass is 1.062977 smaller than the kilogram.
(2) Metre: Pure Number unit of length is 1.273023 smaller than metre.
(3) Time: Pure Number unit of time is 11.068247 times smaller than the second.
(4) Energy: Pure Number unit of energy is nominally 1.7226472 times smaller.

Masses:

Proton: 1.77795779x10^-27 new units.
Proton opposite= 1.77795779x10^-27x2.660725x10^38=4.73065679x10^11.
GM product of Mop is 0.5 relating the reciprocal to G.
Planck mass: 1/3.4480856x10^7=2.90016x10^-8.
Timescale mass: 9.6967476x10^33 units.

Lengths: C: The new C becomes 3.4480856x10^7, reciprocal of the local
Planck mass.
Proton Compton wavelength: 1.6821853x10^-15, Compton radius=
8.410928x10^-16=(2.90016x10^-8)^2=1/(3.4480856x10^7)^2.
Schwarzschild radius of proton=Mpr^2=3.16114x10^-54.
Planck radius=5.156367493x10^-35 which is nominally identical
to the local Planck constant h and the reciprocal is equal to
the timescale mass by a factor of 2.
From the Proton Schwarzschild radius and Compton length of proton we can work out the following: Where M=Planck mass and m=proton mass:

M/m= 1.6311729x10^19
(M/m)^2=2.660725x10^38.

G & Gm products & nominally related energies:

G= 1.05693438x10^-12.
Kinetic Energy of Proton=(Mc^2)/2=1.05693438x10^-12.

Planck GM product: =1/1.6311729x10^19=6.13055795x10^-20/2.
Rydberg Constant: =1/1.6311729x10^19=6.13055795x10^-20.
Gm product of proton: =1/2.660725x10^38=3.75837408x10^-39.
C/G: =2x1.6311729x10^19.

And so on.

All of science owes its entire repertoire of measurements to these few pure numbers.

Even the threshold mass value for a collapsing star requiring enough mass before
it can become a black hole is here, it is 2.660725x10^38/3.4480856x10^7, approximately 3.6 solar masses.

[haroldj...@gmail.com]

THE PURE NUMBER SYSTEM'S BENEFITS:

The main benefit of this system is that it immediately gives you the true nature of the numerical structure of just about everything.

It is pretty obvious, looking at the SI system, that the numerical structures of nature are separated by uniform adjustors. Take h, the Planck length & the timescale mass of the second,

(1) h: =6.6260755x10^-34 J.
(2) Timescale mass: =1.0096739x10^35kg.
(3) Planck length: =2x4.05049049x10^-35m=8.1008098x10^-35m.

They are all separated by a factor of 8.17934956 or there abouts.

(i) {(8.17934956)^2}/h=1.0096739x10^35kg.
(ii) (8.17934956)/Planck length=timescale mass.
(iii) h/8.17934956=Planck length.

And:

(4) The Planck Mass multiplied by C=8.17934956.
(5) The Planck energy=Cx8.17934956.
(6) The Planck surface g = 8.17934956xc^2/h=1.109439939x10^51ms.

Too much coincidence, there must be an answer.

The nominal values we use to quantify the products of nature, the weights and measures, are simply that, nominal, and it was this that Einstein debated in his letter writing with Ilse Rosenthal-Schneider.
A good example of the unreliability of nominal values lies in the expression
Mpl^2, the Planck mass squared. It crops up often.

The first element represents the fixed value of the Planck mass, but the second
element becomes a multiplier. So Mpl^2 in SI units differs a thousand fold
to Mpl^2 in CGS units. And it is with that numerical principle in mind that we find ourselves with the inherent differences between the SI system and the pure number system.

One of the first things one notices with any attempt at analysis is the relationship between the Rydberg energy and GMpl. The GMpl product approximates
to 1.8201997x10^-18 and differentiates from the Rydberg energy by 1.19760167.
The Rydberg energy is the Rydberg constantxCxh, or:

1.097373x10^7xch. This converts to 4(1.0973732x10^7)GMpl^2.
We know that the Planck mass must differentiate from the Rydberg constant by factors 4 & 1.19760167. We have the 4 so things should go like this:
4(Rydberg Constant)(GMpl^2)=GMplx1.19760167.

In previous posts it was shown how 4Mpr/h=1.009721668x10^7 and that this value was related to the Planck mass by, approximately, 3.62994678, the quantum adjustor. 1/3665236x10^7=Mpl.

The Rydberg constant divided by 1.009721668x10^7=1.086807639. What this means is that 1.19760167 is divided by(4/3.62994678) or 1.10194453. These two values being the differences between the Planck mass with the Rydberg constant on one hand and 1.009721668x10^7 on the other hand. The rest has been already explained.
Mass changes by 1.062977, length by 1.273023, time by 11.068247.
The new Planck mass, 2.90016x10^-8, 1/3.44808x10^7 is the difference between Rydberg and proton energies, C/3.4480856x10^7=8.69446077.
C/(8xRydberg constant)=3.41488722.
And, 8.69446077/3.41488722=1.273023,
and, 8.69446077x1.273023=11.068247, and so on.

The theoretical nature of these figures means that they can only be regarded as good approximations, rather like our current crop of G's, but then it is quite usual for theoretical reckoning to differ from spectroscopic observation. One might add, however, that most of the values used here are based on an assemblage of spectroscopic findings.

[haroldj...@gmail.com]

All attempts to beak down numerical mass structures will lead to aspects and components of planck and proton. The two are inseparable.

(1). Take Gmop, the Gm opposite of the proton, 29.6906036, and divide it into C,
C/Gmop=1.009721668x10^7.

(2). Then take the quantum number that separates C and Mpl, the Planck mass,
qn= CxMpl.

Then, Gmop/qn=qa, the quantum adjustor.

(3). We cannot directly ascertain the Planck number, qn, but we can establish qnx(Gc/2)^0.5. as follows:

If hc/4 = GMpl^2, then :

2(Gmpl^2)(C^3)=0.33451778x2=0.6690355. (0.6690355)^0.5=2x0.40897297=0.81794594.
And, 4(0.40897297)^0.33333r=0.742275x4=2.96910024. This is a numerical value involving Gmop and a factor of Gc.

Then, 29.6906036/4=(7.4226509)^3=408.95649. 408.95649x=817.912983 metres and this value amounts to the proton Sun radius divided by qa. The proton Sun
being (29.6906036xC)/G^2, about 2x10^30Kgs.

(4). (Mpr)C^2=1.503278583x10^-10 J. But the mass of the proton is made up of other components which break down to Gx29.6906036/(qa)^2.
So, MprC^2/29.6906036=G/(qa)^2=5.063145847x10^-12.
If we use this as a substitute G in the formula (Gh/C^3)^-0.5, the Planck radius, we wind up with 1.115853948x10^-35, which is the Planck radius divided by qa. It also amounts to the proton mass divided by c/2.

(5). 817.912983, see (3), divided by 1.115853948x10^-35, (4), is
7.329928657x10^37. Divide this by 1.009721668x10^7 the reciprocal of our
adjusted Planck mass, see (1) and we get 7.25935562x10^30kg, the mass of our
threshold black hole that transitional link between neutron star and Schwarzschild Radius. If we divide this by the proton mass, 1.672623x10^-27kg, we get 4.3401027x10^57. Not only is this Schwarzschild sphere 4.3401027x10^57 proton masses, it is made up of 4.3401027x10^57
Proton Compton spheres each assumed to be spherical with a radius equal to half the Compton wavelength of the proton.
(4.3401027x10^57)^0.666666rec=2.660725x10^38, the number of Compton proton
spherical surfaces on this particular Schwarzschild sphere. Because we know this we can work out the Schwarzschild radius. 2.660725x10^38 Compton surfaces amounts to 1.45957x10^9 m^2, giving a radius of 1.0777241x10^4m.

And, 2.660725x10^38 is the ratio between Strong and gravitational forces.

[haroldj...@gmail.com]

The proton is an essential component in the understanding of numerical structures representing physical values of massive bodies. So is the proton Sun. The Proton Sun is a star about 2x10^30 kg, much like our own Sun. It measures (29.6906036xC)/G^2.

We can apply it to any Sunlike structure, even our own.

The GM product of our Sun is around 1.32712x10^20. Because we are looking for a situation that is configured by the numerical structure, (29.6906036xC)/G^2, we can apply such process on 1.32712x10^30kg, first, by dividing by C.

1.32712x10^20/C=4.42679582x10^11kg. We are free to choose this as a magnitude of mass that when multiplied by G produces a GM product of 29.6906036.

Then, 29.6906036/4.42679582x10^11=6.707018983x10^-11, this particular system's
Gravitational constant and I will refer to it as G in this post.
I say this particular system because it will not be the SI kilogram. Each different mass system has its own different proton Sun as well as mass.

In our own SI system hc/4, 4.966118653x10^-26, is equal to the GM product of Gmpl^2, where mpl is equal to the Planck mass. The cube root of the reciprocal
of this is equal to 1.08823067x10^9/4.

Gx1.08823067x10^9=7.298783762x10^-2.
4/7.298783762x10^-2=54.8036512.
(54.8036512)^0.5=7.40294882.
7.40294882x4=29.61179529, a structural drift from 29.6906036.

1.08823067x10^9/29.61179529=1/3.674990521x10^7=Planck mass/error(x).
C/3.67499052x10^7=8.15763898=quantum number, qn, with error(x).
29.61179525/8.15763898=3.639607463, quantum adjustor, with error (x).

Cx3.639607463=1.091126867x10^9.

1.091126867x10^9/29.61179625=3.68477x10^7=1/Planck mass, corrected.
C/3.68477x10^7=8.13598609=quantum number, qn, corrected.
29.6906036/8.13598609=3.6492938, qa, quantum adjustor, corrected.

29.6906036xC/2=4.4505095x10^9, which is the mass of GM product 29.6906036, multiplied by Gc/2. This is a universal truth as long as we are using the metre and the second.

4.4505095x10^9/4=1.112627379x10^9x3.6492938, (corrected quantum adjustor), =4.060304196x10^9.

3.68477x10^7/3.6492938=1.009721668x10^7.
(4x1.009721668x10^7)/Gc/2=4.01736623x10^9.

(4.01736623x10^9)x(4.060304196x10^9)=1.6311729x10^19.

(1.6311729x10^19)^2=2.660729x10^38=Strong/Gravitational force ratio.

(4.060304196x10^9)/(4.01736623x10^9)=(1.00532984)^2=1.010688089.

This differential closes up the nearer you get to the SI system till they eventually match, (4.0387708157x10^9)^2=11.6311729x10^19.
1.112627379x10^9x3.6492938

[haroldj...@gmail.com]

The suggestion that primordial black holes of the same 05size as the Compton wavelength of the proton abound. Such black holes would have a Schwarzschild diameter of 1.3214x10^-15m and a radius of half that, 6.60705x10^-16m, and a mass of 4.45039x10^11kg.
These black holes have a different historical background from conventionally conceived gravitational black holes in that they were formed in the immediate aftermath of the Big Bang caused not by gravitational collapse but by the extreme pressures from the sheer density of matter and energy that would have existed then. Such black holes would not have had the same mass constituent evolution but would have been made up of a whirlpool soup of radiation and particles in the early stages of evolution. But they would have obeyed the same laws of nature that abounds to this day. One such rule would concern the threshold between neutron star and black hole. The threshold mass is 7.25935527x10^30kg. Its Schwarzschild radius is 1.07771x10^4m.
7.25935527x10^30kg/4.45039x10^11kg=1.6311729x10^19.
(1.6311729x10^19)^2=2.660725x10^38=Strong/Gravitational force ratio.
2.660729x10^38xproton mass=4.45039x10^11kg=primordial black hole.
1.6311729x10^19x4.05049049x10^-35m(Planck radius)=6.60705x10^-16m.
The Schwarzschild radius of the proton is 2.48317655x10^-54m.
Planck radius/2.48317655x10^-54m=1.6311729x10^19.
1.07771x10^4m/6.60705x10^-16m=1.6311729x10^19.
1.07771x10^4m/Planck radius=2.660725x10^38.
There is no getting away from the link between proton and Planck.

[robin....@gmail.com]

There's an old saying:-
Gravity begins at home.

[haroldj...@gmail.com]

The Strong/Gravitational Ratio is often translated into the Planck mass squared
divided by the proton mass squared, (Mpl/Mpr)^2. The involvement of pi in the electric equation is quite separate from considerations of the value of the Planck mass. For linear versions of Planck units to have parity and symmetry with changing scales between Planck and Compton units the following rationale and formula should be considered:

The Planck mass is considered to have a particular value where its Compton length is equal to its Schwarzschild diameter, not its radius. The basic principle is to view such a condition in such a way as we would look upon
two spheres, one a Schwarzschild sphere, the other a spherical wave.
The formula required for that condition is based on the two separate formulae,

(4GM/c^2=h/cm) which translates to m^2=hc/4G which means Gm^2=hc/4.
hc/4=4.966118653x10^-26.
Divide this by the proton mass and you get 29.6906036. 29.6906036 is a Gm structure where the Schwarzschild diameter is equal to the Compton wavelength of the proton, 1.32141x10^-15m, and is sometimes described as a possible dimension for the primordial black hole.

I refer to 29.6906036 as Gmop, Mop meaning the proton opposite.
In this case (Mop/Mpl)^2 is equal to (Mpl/Mpr)^2 which, in turn, is equal to (Mop/Mpr).

Using these considerations, I have calculated that the Strong/Gravitational ratio is about 2.660725x!0^38 which is equal to (1.6311729x10^19)^2 and then
(4.038778157x10^9)^4.

The Timescale mass of the light second, that value of mass where its Schwarzschild diameter is one light second across, is about 1.009x10^35kg.
Its Gm product is 6.7360006x10^24. This is equal to 29.6906036 multiplied by the Compton frequency of the proton, 2.2687314x10^23.
the square root of 2.2687314x10^23 is 4.76312x10^11. Mop is equal to about
4.45x10^11kg. 4.76312x10^11/4.45x10^11 comes to about 1.07.. So, in a sense the Timescale mass has three sections, one section being 1.07.. less than the other two. I'll refer to this difference, 1.07.., as (x) in this post.

What I'll do is use a Timescale mass of three equal sections(4,76312x10^11)^3
which is equal to 1.080624035x10^35 mass units. Dividing this into the Gm product of 6.7360006x10^24 gives us a local G of 6.23343585x10^11. This, of course, differs from SI G by a factor of(x).

Using this G as a substitute in the formula (ch/4G)^0.5, we get a value of 2.822570503x10^-8 mass units. We will also require a substitute Gc/2 which, using the same substitute G, gives us 9.343685276x10^-3.

In the above Timescale mass of 1.080624035x10^35 all sectors are 4.763120196x10^11 so this will be in this particular model the local Mop.
(4.763120196x10^11)x9.343685276x10^-3(the local Gc/2)=4.4505095x10^9.
4.4505095x10^9/1.009721668x10^7=4x1.101914928x110^2.
This means that Mop, whatever it is, will have the following properties:
4(1.009721668x10^7/Gc/2)x1.101914928x10^10^2.
Now, Mop/Mpl is the square root of Strong/Gravitational force. So if we consider the following:
Using the above Gc/2,
4(1.009721668x10^7/9.343685276x10^-3)=4.32258424x10^9.(factor one)

Using substitute Planck mass 2.822570503x10^-8 and borrowing the removed 1.101914928x10^2 from Mop we have:
(1.101914928x10^2)/(2.822570503x10^-8)=3.9039412x10^9.(factor two)

If we multiply both factors, (4.32258424x10^9)x(3.9039412x10^9)=1.68751147x10^19. The square of this,2.847694965x10^38, is the Strong/Gravitational ratio multiplied by (x).

However, (4.32258424x10^9)/(3.9039412x!0^9)=1.107236=(x)^1.5.

Therefore (x)=1.07027035 and (1.07027035)^1.5=1.107236.

In all cases the substitute templates are factors of (x) or its square root so any cross factorisation will result in (x) or an exponent of (x).

Interestingly, 8(1.101914928x10^2)= (29.6906036)^2.

[haroldj...@gmail.com]

Using the above parameters and numerical considerations the following can be reckoned.
(1) Mpl^2=hc/4=4.966118653x10^-26:reciprocal=2.013645x10^25=2.72057667x10^8.

(2) C/2.72057667x10^8=1.10194453.

(3) 2(29.6906036/4)^2=1.101914928x10^2 and is an analogue to (2) being separated by a sum equal to or around a value Gc/2.

(4) In the Strong/Gravitational force difference, 2.660725x10^38, we find the
components can be altered to (Mop/mpl)^2. Mop is estimated as a likely mass value for the primordial black hole at some 4.45039x10^11Kgs. Its Schwarzschild diameter being the same as the proton Compton wavelength, 1.3214x10^-15m. mpl is the Planck mass worked out from the simple linear natural unit formula, (hc/4G)^0.5. Worked out from the question, what mass has a Schwarzschild diameter equal to its own Compton wavelength? The question assumes two equally sized spheres, one a spherical Compton wavelength and the other a gravitating Schwarzschild sphere.

Several things become apparent when scrutinising the above values.

(5) If Mop (mass opposite to the proton) is unknown although clearly around, 4.45039x10^11kg, then its analogue, 4.4505095x10^9 is very much known.
The Gm product of Mop is 29.6906036 so multiplying this by c/2, giving the above, which is MopxGc/2.

As I have written before, the Strong/Gravity ratio, appx 2.660725x10^38, can be broken down into four equal components. This is how:


The quantum adjustor, qa, about 3.629946, multiplied by the value, 1.009721668x10^7 gives us the reciprocal of the Planck mass, about 3.665236x10^7. 1.009721668x10^7 can be found elsewhere, c/29.6906036 or
4 times the mass of the proton, mpr, divided by h.

(6) If you divide Mop(Gc/2), 4.4505095x10^9, see (5), by 1.009721668x10^7 you get 4(1.101914928x10^2), see (3). That means, numerically, there can exist a value that is equal to 4(1.009721668x10^7)/Gc/2, having borrowed (Gc/2) from Mop proper.

We can get a very good approximation with:

4.4505095x10^9/1.10194453, {see (2)}=4.03877816x10^9=4(1.009694539x10^9).

That leaves us with the reciprocal of the Planck mass, 3.665236x10^7.
We multiply this with our spare 1.101914928x10^2, from above and we find
the same value, roughly, 4(1.009694539x10^9), and, of course, if you multiply them together, we get 2.660725x10^38, the S/G ratio.

(7) For amusement you can reverse the situation and tie Mpl with Gc/2 and
4(1.009721668x10^7) with 1.101914928x10^2. You get 3.665137x10^9 and 4.4505095x10^9 which is, of course a known, Mop(Gc/2), see (5). So they are interchangeable.

Which brings us back to Gmpl^2 and the cube root of its reciprocal, 2.72057667x10^8, see (1).

(8) In the previous posts I have used a template timescale mass called the protonic system. It is based on the Compton frequency of the proton, 2.2687314x10^23. Its square root is 4.763120196x10^11 and the cube of this is 1.080624x10^35 protonic mass units which would weigh some 1.07 times less than the kg. The purpose of constructing this model was to highlight what one might call the tripartite numerical construct nature of the SI system.

In this the protonic system can be measured as a cube of 4.763120196x10^11,each cube root sector having a Gm product of 29.6906036 or Gmop. Its local G is easy to work out, 6.23343585x10^-11.

(9) In this tripartite analysis we can quickly establish that in the SI system our kilogram figures like this:
(a) 29.6906036(2.2687314x10^23)=6.7360006x10^24, which is the Gm product of the Kilogram/second time scale mass, appx 1.0096739x10^35kg.
(b) Where the protonic system measures three equal sectors the SI system is as follows:

Mop or 4.45039x10^11kg(4.763120196x10^11)^2. What is also relevant is that each 4.763120196x10^11kg GM product must be greater than 29.6906036 by a factor of 1.07 plus.

(10). What we can see from above is that (4.763120196x10^11)^2 is a multiplier of Gmop. Intriguingly, the square root of the multiplier plays an important role in deduction physics from here on.

We can find a template Planck mass using protonic local G, 6.2334358x10^-11 and SI h, 6.6260755x10^-34. It comes out as 2.822570503x10^-8. What we can be assured of is that whatever the difference between the kilogram and the protonic unit, the difference between SI Planck mass and this version will be the square root of this; ie. the square root of 1.07+.

(11). Taking the cube root of the reciprocal of Gm^2, 2.72057667x10^8, (see(1), multiplying by 4, 1.08823067x10^9, and, multiplying this by protonic Planck mass, 2.822570503x10^-11, we get 30.71607939. This value is an analogue of Gmop, 29.6906036. The explanation why this is quite tedious and will need another post to explain. For now, take my word for it.

So what does 30.71607939 do for us? Well.it does the following:

(12) When we use the known constants in the SI system, h & c, we rely on a variation of G's and consequently Planck mass & Planck length. Get G wrong and your Planck length is wrong along with your Planck frequency which means that particular Planck frequency does not measure one light second. C will only be nominal but not the same as our second in terms of the Planck frequency.

So, in our tripartite construct, we start with 30.71607939 and multiply by 2.2687324x10^23 which comes to 6.96865338x10^24. Divide this by 6.7360006x10^24 and you get 1.0345387. Multiply this by c and you get 3.101469x10^8. So if our protonic system insists on using our nominal C it must own up to being out by 1.0345387. The Planck length, here, registers in at 2(3.915262273x10^-35), the Planck frequency being 3.82851x10^42.

(13) Look at another G, 6.6726x10^-11. Using the same procedure we find that its analogue for Gmop is 2.9688 which results in a shortfall from the second of around 1.000087.

[haroldj...@gmail.com]

THE DISENTANGLEMENT OF THE INTERCONNECTEDNESS OF EVERYTHING.

In the numerical structures of physics, the nominal values tend to conform to a routine proportionality no matter how much we juggle them about. The three main constants of nature, C,h & the proton mass, pretty well convert to all other constants and values. There is one exception to this phenomenon and it goes like this.

In the above post I wrote of the protonic system where the mass unit is 1.0702704 times lighter than the kilogram. G = 6.23343565x10^-11 and therefore Gc/2 = 1/1.0724163x10^2. Quite an innocuous little number you might think and yet:

2(4x1.0724163x10^2)^2 = 3.66533488x10^5. Recognise it? It is the reciprocal of the Planck mass multiplied by Gc/2, SI units of course.

It took a while to fathom out and here it is.

(c^2/h)=1.356391399x10^50 and configures with most parameters. One it does not configure with is the following:

The Strong/Gravitational ratio, 2.660725x10^38 multiplied by Mop, 4.45039x10^11kg, equals 1.1841264x10^50.

(c^2/h)/1.1841264x10^50=(1.0702704)^2. Of course these are theoretical values, how about some proof?

The Strong/Gravitational ratio is equal to (Mop/Mpl)^2 and also Mop/proton mass. In the protonic system Mop is 4.763120196x10^11. I've called the difference (x), theoretically 1.0702704.

If we divide 4.763120196x10^11 by the proton mass we get 2.847695x10^38 which will be Strong/Gravitational times (x). Multiply by 4.763120196x10^11 and you get 1.356391399x10^50, (c^2/h).

So, {(4.763120196x10^11)^3/(local Planck mass)^2} is greater than {(Mop^3)/(Mpl)^2} by (x)^2.

Remember, that the theoretical Oppenheimer-Volkoff value I gave is:

(Strong/Gravitional Ratio) Planck masses, some 7.259355x10^30kg.
(7.259355x!0^30)/Proton mass=4.34010264x10^57 which is the same as
(Mop/Mpl)^3.

So, (c^2/h) divided into (Mop/Mpl)^3 is 1/{(Mpl)(x)^2}=3.19974165x10^7.
We know this because of the following.

Gmop=29.6906036. We would find Mop if we divided this by G. If we cannot confirm G we can at least find a template with c/2. This gives us 4.4505095x10^9 which differs from Mop by Gc/2.

4.4505095x10^9 divided by proton mass is 2.660796545x10^36.
(2.660796545x10^36)^1.5 is 4.340277545x10^54.

4.340277545x10^54 divided by (c^2/h) comes to 3.199871x10^4.

I mentioned before that (4.4505095x10^9)/(1.009721668x10^7) is equal to
4x1.101914928x10^2. 8(1.101914928x10^2) is (29.6906036)^2. You will find this value all over the place in this branch of physics. Look here.

(4x1.009721668x10^7)/(Gc/2) = qa(1.009721668x10^7)(1.101914928x10^2) and (1.009721668x10^7)qa is the reciprocal of the Planck mass. So.

1/proton mass is Mop/(Mpl)^2 therefore {(1.101914928x10^2)/Mpl}^2 comes to
Mop/Mpl. Therefore, the following is true:

2.66079655x10^36 is {(Mop/Mpl)^2}(Gc/2). If we divide 2.6679655x10^36 by
4(1.009721668x10^7) we get 6.58794555x10^28. Multiply this by proton mass and we get 1.101914928x10^2.

The cube root of 6.5879655x10^28 is 4.03877817x1^9 and (4.03877817x10^9)^4 is 2.660725x10^38 or Strong/Gravitational ratio.

Now divide (c^2/h) by 6.58794555x10^28 and you get 2.0588989x10^21. This is
2(1.009721668x10^7)^3. This means that a value of 32 resides out side of the limit that is (c^2/h).

So, (2.660796545x10^36)^1.5 = 4.340277545x10^54 and this divided by (c^2/h)
is 3.199871x10^4. If we remove the 32 by dividing it into 3.199871x10^4 we get 1/1.000040304x10^-3. This value represents (Gc/2)^1.5.
(1.000040304x10^-3)^0.6666666 =1.00002688x10^-2=Gc/2.

[haroldj...@gmail.com]

THE DISENTANGLEMENT OF THE INTERCONNECTEDNESS OF EVERYTHING.

Once you recognise a number of the interconnecting multipliers and adjustors
there is no end ways to link the seemingly unlinkable to the linkable.
Take the formula (1.101914928x10^2)^2 divided by Gmpl^2, (hc/4), and you get
2.445x10^29. This in effect is (Mop/Mpl)/G.
Then take cube root of 1/(Gmpl^2)=(1.08823067x10^9)/4. From this we can deduce these cognates,
1.08821605x10^10 & 1.088201423x10^11 in several ways; here's one of them.

(1) (2.445x10^29)/1.08823067x10^9= (4.4935344x10^20)/2=(1/G)^2.
(2) ditto /1.08821605x10^10=(4.4935948x10^19)=c/6.67155073x10^-12.
(3) ditto /1.088201423x10^11=(4.493655x10^18)=c/G.

(4) (1/proton mass)/1.08823067x10^9= 1.09878055x10^18=2/(GMpl).
(5) ditto /1.08821605x10^10=1.0987953x10^17=3.6651866x10^8xc.
(6) ditto /1.088201423x10^11=109881x10^16=c/Mpl.

(7) (1.09878056x10^18)/1.009721668x10^7=1.088201433x10^11.
(8) (1.0987959x10^17)/ ditto =1.088216x10^10.
(9) (1.09881x10^10^16)/ ditto =1.08823067x10^9.

(10) (1.0882014x10^11)/1.009721668x10^7=1.07772412x10^4.
(11) (1.088216x10^10)/ ditto =1.07773863x10^3.
(12) (1.08823067x10^9/ ditto =1.077753x10^2.
(13) 32/29.6906036= =1.07778207.
(14) and by deduction: =1.0777676x10^1
therefore the Oppenheimer-Volkoff mass limit, 7.2959355x10^35kg must have a Schwarzschild radius of 1.07772412x10^4 metres. Divide 1.07772412x10^4 by half the Compton wavelength of the proton, (1.3214x10^-15)/2 and we get 1.6311729x10^19, the square root of the Strong/gravitational ratio. This is so because the surface of this particular Schwarzschild sphere is made up of
2.660725x10^38 areas measuring (4pix1.3214x10^-15m/2)^2.

[haroldj...@gmail.com]

The 1.08823x10^9 series above gives way to the 1.101914928x10^2 series.
1.1011914928x10^2 is Gmop squared and then divided by 8. {(29.6906036)^2}/8.

The series itself started life way back in the Big Bang with the first proton on proton gravitational interaction. G(mpr) divided by Planck Radius comes out at (1.101974155x10^-2)/4. This value crops up time and time again in various interactions.

Of course, we do not have a reliable definition of G but we can use c as a temporary template, 2/c=6.6712819x10^-9. By doing this we get a value of (1.10195933x10^-1)/4 as a temporary stand in for the true value, 1.10197415x10^-2.

Next we need a template for Mop, Mass opposite proton, 29.6906036/G.
Using c template we arrive at 4.4505095x10^9kg instead of 4.45039x10^11kg.

We need a template for the Planck mass; using c template again in the formula for Planck mass (ch/4G)^0.5 we get 2.72837397x10&-9, or, 1/3.6651867x10^8.
(4.4505095x10^9)/(3.661867x10^8) = 1.214265429x10.

(1) (12.14265429)/(1.10195933x10^-1)= 1.101914928x10^2.
(2) (12.14265429)x(1.10195933x10^-1)= (1.338071)= (1.10194453)^3.
(3) (12.14265429)/(1.10194453)= 1.10192972x10^1.
(4) {(1.10195933)^2}/(1.10194453)= 1.1017415x10^-2. See Above.

If the Gmpr/Rpl comes to 1.10197415x10^-2 then dividing again by Planck Radius gives a surface gravity of 6.801485629x10^31 and dividing this into (1.10197415x10^-2)/4 gives us a Planck radius of 4.05049049x10^-35m.

The value 1.10197415x10^-2 can give interesting results in all sorts of places.

First take the Planck units at the Planck limit. Considering the Planck radius to be in a Schwarzschild condition then the following is true:

2GMpl/Rpl=c^2.

The total energy of the proton, mc^2, is 1.503278583x10^-10J.

Looking at the above we can also see it as being mprx2Gmpl/Rpl.

This can be seen as: 2Gmpr(mpl)/Rpl.

As we know that Gmpr/Rpl is along the lines of being (1.10197415x10^-2)/4

then Proton energy 1.503278583x10^-10J divided by 1.10197415x10^-2 and rectified by 2 and we get 2.72833729x10^-8kg, the Planck mass.