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Re: cardinality of 2^[] = ?
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I.N.R.I. Logic
Jul 8, 2009, 9:21:40 PM7/8/09
to
On Jul 8, 6:16 pm, MeAmI.org <Me...@vzw.blackberry.net> wrote:
On Jul 8, 4:00 pm, MoeBlee <jazzm...@hotmail.com> wrote:
> On Jul 8, 3:57 pm, MoeBlee <jazzm...@hotmail.com> wrote:
>
> > On Jul 8, 3:34 pm, cartman18 <cartmaneri...@hotmail.com> wrote:
>
> > > Let [] be the empty set.
>
> > > What is the cardinality of 2^[] ?
>
> > > 2^[] = P[] ?
>
> > Let 0 = the empty set = the cardinal number zero = the natural number
> > zero.
>
> > 2^0 equals the CARDINALITY of P0.
>
> > 2^0 = 1.
>
> P.S In general, for any cardinal numbers j and k, we have the theorem:
> j^k = the cardinality of the set of functions from k into j.
> http://www.meami.org/?cx=000961116824240632825%3A5n3yth9xwbo&cof=FORID%3A9%3B+NB%3A1&ie=UTF-8&q=cardinality+of+2%5E%5B%5D+%3D+%3F++P%3D%3DNP+Musatov#1056
> MoeBlee (proof link^) (Ever see on an airplane "Do Not Step Here."?
(this is not a joke)
... the cardinality of N > cardinality of > 2^N. > I must be
mistaking, could someone point out my error? (C)2009 Martin Musatov |
P=NP| ... (this space intentionally overwritten)
(Proof Link) (this is
binary insulation for a proof)
http://www.meami.org/?cx=000961116824240632825%3A5n3yth9xwbo&cof=FORID%3A9%3B+NB%3A1&ie=UTF-8&q=cardinality+of+2%5E%5B%5D+%3D+%3F++P%3D%3DNP+Musatov#1056
On Jul 8, 4:00 pm, MoeBlee <jazzm...@hotmail.com> wrote:
> On Jul 8, 3:57 pm, MoeBlee <jazzm...@hotmail.com> wrote:
>
> > On Jul 8, 3:34 pm, cartman18 <cartmaneri...@hotmail.com> wrote:
>
> > > Let [] be the empty set.
>
> > > What is the cardinality of 2^[] ?
>
> > > 2^[] = P[] ?
>
> > Let 0 = the empty set = the cardinal number zero = the natural number
> > zero.
>
> > 2^0 equals the CARDINALITY of P0.
>
> > 2^0 = 1.
>
> P.S In general, for any cardinal numbers j and k, we have the theorem:
> j^k = the cardinality of the set of functions from k into j.
> http://www.meami.org/?cx=000961116824240632825%3A5n3yth9xwbo&cof=FORID%3A9%3B+NB%3A1&ie=UTF-8&q=cardinality+of+2%5E%5B%5D+%3D+%3F++P%3D%3DNP+Musatov#1056
> MoeBlee (proof link^) (Ever see on an airplane "Do Not Step Here."?
(this is not a joke)
... the cardinality of N > cardinality of > 2^N. > I must be
mistaking, could someone point out my error? (C)2009 Martin Musatov |
P=NP| ... (this space intentionally overwritten)
(Proof Link) (this is
binary insulation for a proof)
http://www.meami.org/?cx=000961116824240632825%3A5n3yth9xwbo&cof=FORID%3A9%3B+NB%3A1&ie=UTF-8&q=cardinality+of+2%5E%5B%5D+%3D+%3F++P%3D%3DNP+Musatov#1056
MoeBlee
Jul 8, 2009, 9:29:20 PM7/8/09
to
On Jul 8, 6:21 pm, "I.N.R.I. Logic" <scribe...@aol.com> wrote:
> On Jul 8, 6:16 pm, MeAmI.org <Me...@vzw.blackberry.net> wrote:
> On Jul 8, 4:00 pm, MoeBlee <jazzm...@hotmail.com> wrote:
> > P.S In general, for any cardinal numbers j and k, we have the theorem:
> > j^k = the cardinality of the set of functions from k into j.
> >[URL was added here not by MoeBlee]> On Jul 8, 6:16 pm, MeAmI.org <Me...@vzw.blackberry.net> wrote:
> On Jul 8, 4:00 pm, MoeBlee <jazzm...@hotmail.com> wrote:
> > P.S In general, for any cardinal numbers j and k, we have the theorem:
> > j^k = the cardinality of the set of functions from k into j.
> > MoeBlee
Please do not falsely add text to quotes of my own posts. The URL you
inserted was not in my post. Please do not quote me and then add to my
quote to make it appear that I posted something when in fact I had not
posted it.
MoeBlee
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