compression strength of 1 inch aluminum tubing

[Jack]

How can I calculate the compression load factor for a 1 inch aluminum
tube, 049-065 wall thickness

[dlzc]

Dear Jack:

On Oct 16, 1:29 pm, Jack <advan...@gci.net> wrote:
> How can I  calculate the compression load factor
> for a 1 inch aluminum tube, 049-065 wall thickness

You will need to evaluate the failure mode. Long shapes fail by
"Euler buckling". Short shapes fail in the expected crushing mode.

http://www.efunda.com/formulae/solid_mechanics/columns/columns.cfm
http://en.wikipedia.org/wiki/Buckling

David A. Smith

[brian whatcott]

Jack wrote:
> How can I calculate the compression load factor for a 1 inch aluminum
> tube, 049-065 wall thickness

For metals the load to yield is much the same in compression or in
tension. You find the area of the cross-section and multiply with the
yield strength. But a column in compression doesn't usually fail this
way. It fails in buckling. The criterion here is slenderness ratio.

If its no more than 20 times as long as its diameter, it won't fail in
buckling (usually) and conditionally, columns (or struts, same
difference) can hold up at slenderness ratios up to 80:1.
The key is No Side Loads At All. All Loads Through The Long Axis.

Brian W

[Fred Osim]

the load on the tube has a lot to do with their end conditions, whether it
is simply connected or moment connected, and how it is loaded. for just
compression, stress equals force over area. for buckling,
Pcr=pi^2EI/(KL)^2. if K=1, both ends are pinned, if both ends are rigidly
clamped, K=.5. if one end is clamped and the other end is pinned, K=.7. if
the columned is cantilever and loaded at free end, K=2.

reference: statics and mechanics of materials by nash, schaum's outline.

from fred.

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