A 3 phase 4 wire 400V 250A supply to a building is to be provided from
a substation. A moulded case circuit breaker is to be used in the
substation to protect the circuit. The designer wishes to provide the
circuit with current balance earth fault protection since it is
possible that the earth fault loop impedance of the circuit will be
high (maximum 0.8 ohms).
The open circuit phase voltage at the substation is 240V
I now need to know how to work out the minimum earth fault current at
the load end of the circuit.
It should be something you have down pat, since this appears to be a
homework question
ubuntu2 <pgi...@googlemail.com> wrote:
jk
>ohms law
>
>
>It should be something you have down pat, since this appears to be a
>homework question
You are probably right, but if it is a real question, then there is
not sufficient data provided for calculation, as no mention is made of
the HV bus impedance, nor of the impedance of the transformer
supplying the 400volts. So the minimum fault will certainly be
lower than the simple ohms law value if based only on the figures
supplied.
Peter