In article <n2a55v$5lf$
2...@dont-email.me>,
cu...@notformail.com says...
Don't get confused, RMS and AVG is not the same
While RMS is working in the 0.707 of the peak, AVG is
in the 0.637 or there abouts.
Since Watts = 1 J(joule)/ Second we have this to look at;
Inject a 1 Hz tone into an amp from a clean sinewave source with
1 Volt Peak coming out going to a 1 ohm load. How do you
measure Watts if Watts involves a J value over a 1 second period?
We know that the SINE wave isn't always at full level of 1 volt during
that time period so that would indicate that we don't have 1 WATT
of energy there, so what do you do ?
In retrospect that, you need to use voltage in your calculations
to form a WATT value at some point. Wouldn't be logical to
use RMS or AVG as the figure, one being a little different than the
other?
Others will argue the fact that RMS power does not exist, I think they
may have fallen off the cliff, turret, edge, mountain what ever it is
they like to hang out on.
When I was schooled in electronics(Long time ago), starting at lower
levels, through highschool, Post grade in a trade shop, college and
adult lectures, there were never any discussion of RMS/AVG power ever
not existing, because of the roots of how it is derived.
I just flip my eye brown when I hear otherwise and move on.
There are some twisted use of Peak, Peak To Peak power for sales
only and they can get away with it. Only because in retrospect, it is
valid, just the end user is getting fooled by the lack of reallity.
To add to this, doing power calculations in AC does bring in the
phase angle but we get back to the power level of WATTS/second which
then puts a fork into it, if you really think about it. So summing all
the points of a sinewave when doing AC power, still comes out back
to what we were talking about above.
P = I cos(V);do that for all 360 points or even closer if you wish and
see where that leads to.
Just my opinion, really! :)
Jamie