On Wed, 9 Jun 2021 11:37:00 -0400, Phil Hobbs
<
pcdhSpamM...@electrooptical.net> wrote:
>On 6/9/21 11:24 AM, Chris M. White wrote:
>> On Wed, 9 Jun 2021 04:06:44 -0400, Phil Hobbs
>> <
pcdhSpamM...@electrooptical.net> wrote:
>>
>>> Chris M. White wrote:
>>>> Hi guys,
>>>>
>>>> I have an old vintage HP audio osciallator which I want to use for
>>>> some experimentation to get more practice in electronics. Its output
>>>> is continually variable between 4 and 20 volts. Problem is, for some
>>>> experiments I have in mind, I need it to output only between 1mV and
>>>> 10mV. The oscailator's output impedance is 600 ohms it states.
>>>> Can anyone suggest a simple passive attenuator I could build from
>>>> easily available components which would give me this much lower output
>>>> please?
>>>> thanks!
>>>>
>>>
>>> A bit more detail would be useful.
>>
>> I'm happy to oblige. Anything specific?
>
>What's the load? Any DC involved?
No DC and very high impedance load (> 1M ohm)
>>
>>>
>>> However, something like a resistive voltage divider will probably be a
>>> good place to start.
>>>
>>>
>>> 10k
>>> GEN 0----RRRRR----*----0 OUT
>>> |
>>> R
>>> R 10 ohms
>>> R
>>> |
>>> |
>>> GND
>>>
>>> To get down to 1 mV, you can hang a pot on the output. Figuring out
>>> just how to do that would be a step forward.
>>
>> What's the problem in that? Seems simple enough to my simple mind!
>>
>
>Well, if you understand pots, you understand voltage dividers already.
My main concern was not to draw too much from the already quite high
impedance (600 ohms) of the source generator. Did you allow for that
in the values you came up with?