Help! - Question - Reactivity of Hydrogen!
Bry
and I have a quick questions:
Suppose you have the following 5 elements listed:
K
Ca
Na
Mg
Al
And you are using the "reactivity series" as a common tool.
What test (or tests) would you use to establish the exact position of
hydrogen in the activity series of the elements listed above?
Is anyone could help me with it - it would be greatly apreciated...
or e-mail me at bsil...@hotmail.com.
Thanks...
Bry
> On Sat, 1 Dec 2007 12:48:15 -0800 (PST), Bry <bsill...@hotmail.com>
> wrote:
>
> >I am working extremely hard to get a special project (long story) -
> >and I have a quick questions:
>
> >Suppose you have the following 5 elements listed:
> > K
> > Ca
> > Na
> > Mg
> > Al
>
> >And you are using the "reactivity series" as a common tool.
>
> >What test (or tests) would you use to establish the exact position of
>
> Why don't you ask someone who is taking a chemistry class.
>
> Seriously... What does "reactivity series" mean? How would you
> determine any part of that table you show above? Does your textbook
> relate reactivity series to single replacement reactions?
>
> If you will explain what you have done so far, and where/why you are
> stuck on this question, we can try to help -- in a way that will help
> you understand it. Just giving an answer serves no purpose --
> especially when the question is rather basic.
>
> bob
Dear Bob,
KISS. Keep It Simple Stupid. I am in an extremely bad time sensitive
situation here. Do not point out the obvious. Do not intimiate me by
saying that the answer is rather basic. I could spew 24,000 lines of
COBOL complete with JCL and RPG extensions in front of you right now
and call it "pretty basic." How would that make you feel? Stunned?
Griping at the walls for survival? I need an answer soon.
If anyone could "post & help" - that would be great.
Sincerly,
Bryan
Richard Schultz
: Suppose you have the following 5 elements listed:
: K
: Ca
: Na
: Mg
: Al
:
: And you are using the "reactivity series" as a common tool.
:
: What test (or tests) would you use to establish the exact position of
: hydrogen in the activity series of the elements listed above?
"Reactivity series" with respect to what? Why is measuring the rate of
reaction of hydrogen with the same reaction partner as the others
not an option?
-----
Richard Schultz sch...@mail.biu.ac.il
Department of Chemistry, Bar-Ilan University, Ramat-Gan, Israel
Opinions expressed are mine alone, and not those of Bar-Ilan University
-----
"Logic is a wreath of pretty flowers which smell bad."
Edward
>
Do you think calling people that answer your questions "stupid" will
encourage faster responses? I saw nothing disrespectful in Bob's
response. He is only trying to help and if you do not like his help
then ignore it or clarify your question for him so he can help. If
you have a short deadline that is not the group's problem. Your OP
smacks of, "Drop what you are doing and do my homework for me, NOW!"
tad...@comcast.net
>
> Thanks...
I am going to go a little out on a limb here and guess that (A) you
are not a chemist [because my instincts tell me you are referring to
what used to be called the "electromotive series" wherein the
electromotive potential (i.e. 'voltage') required to remove an
electron from an atom/ion under certain conditions is listed], and (2)
that you really need a protocol for determining the relative
reactivity of these elements and hydrogen.
The test you need to run is whether hydrogen ions (H+, nominally
available in aqueous electrolytic solutions) can take an electron from
each one of the metal atoms you listed, yielding elemental (neutral)
hydrogen (gas) as a stable product along with the ionized form of the
metal.
The generalized reaction would be something like:
2 M° + 2 H+ => 2 M+ + H2(g) for the monovalent metals (K, Na)
M° + 2 H+ => M(+2) + H2(g) for the divalent metals (Ca, Mg)
and
2 M° + 6 H+ => 2 M(+3) + 3 H2(g) for trivalent metals (Al is the only
one you have listed)
This is beginning electrochemistry, but actually setting up the
measurement in a laboratory requires some finesse because some of the
metals are highly reactive, and the hydrogen gas produced is a fire
hazard. This should only be attempted under rthe supervision of a
qualified chemist.
Tom Davidson
Richmond, VA