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How to prove the implication P => Q: Do either of the following.
Conditional proof: Assume P is true. Then prove that Q must also be true.
Proof by contrapositive: Assume Q is false (~Q). Then prove that P must also be false (~P).
Assume P is true and Q is false (P & ~Q). Then, for any proposition R, obtain a contradiction of the form R is true and R is false (R & ~R). Or, equivalently, obtain R is true if and only if R is false (R <=> ~R).