[scalanlp] easy way to normalize counts?

[Steven Bethard]

Is there an easy way to go from the IntCounter you get as a result of Counters.count to a normalized counter? The best I could come up with was:

scala> val counts = Counters.count(Seq("a", "b", "a", "c", "b"))
counts: scalala.tensor.counters.Counters.IntCounter[java.lang.String] = Counters((a,2), (b,2), (c,1))

scala> Counters.normalize(Counters.aggregate(for ((k, v) <- counts) yield (k, v.toDouble)))
res9: scalala.tensor.counters.Counters.DoubleCounter[java.lang.String] = Counters((a,0.4), (b,0.4), (c,0.2))

Thanks,

Steve

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[David Hall]

On Sun, May 23, 2010 at 5:01 PM, Steven Bethard <bet...@stanford.edu> wrote:
> Is there an easy way to go from the IntCounter you get as a result of Counters.count to a normalized counter? The best I could come up with was:

I occasionally run into this, and I should probably add a method. I
usually use something exactly like this, or I just use DoubleCounters
the whole way through.

I'm traveling, but I'll add something soon.

-- David

[David Hall]

Done. Counters.normalize(IntCounter) should be in the latest nightly of scalala