odd issue while using scala.sys.process

[Arun Ramakrishnan]

import scala.sys.process._ 

"scalac *.scala" ! 

results in 

error: source file '*.scala' could not be found
one error found

Not sure, why it wont interpret the unix wild cards. Am wondering if this is a mac specific text encoding related issue. 

this is with 

scala 2.9.2

OS X 10.7

thanks

Arun

 

[Daniel Sobral]

It is shell who expands wildcards. You are calling "scalac" directly
instead of going through a shell, so no expansion happens.

--
Daniel C. Sobral

I travel to the future all the time.

[Arun Ramakrishnan]

Thanks for the pointer. But, am not sure how to get around it

On bash or shell, the following works just fine

$bash -c "ls *.scala"

But,

""""bash -c "ls *.scala""""

Still dosent work.

thanks

[Daniel Sobral]

On Mon, May 28, 2012 at 6:23 PM, Arun Ramakrishnan
<sinchron...@gmail.com> wrote:
> Thanks for the pointer. But, am not sure how to get around it
>
> On bash or shell, the following works just fine
>>>
>>> $bash -c "ls *.scala"
>
>
> But,
>
>> """"bash -c "ls *.scala""""
>
> Still dosent work.

Because the quotes are not delimiting the parameter passed to bash --
it is Scala who decides how the arguments break up, and it simply
splits on spaces, without any quotation facility. If you try the
following, instead, it will work:

Seq("bash", "-c", "ls *.scala").!

[Arun Ramakrishnan]

Thanks Daniel.