Printing a Val with ${...}, Surrounded by Parentheses?

[Kevin Meredith]

Given the following `val`:

scala> val x = 100

x: Int = 100

The following works:

scala> println(s" ${x} ")

 100

But, the following fails:

scala> println(s"\" ${x} \" ")

<console>:12: error: value $ is not a member of String

       println(s"\" ${x} \" ")

                    ^

<console>:12: error: value \ is not a member of Int

       println(s"\" ${x} \" ")

                         ^

How can I fix this?

[Rex Kerr]

Use triple quotes: s""""$x"""".  Or define a double quote character: val q = '"', and then use it: s"$q$x$q".  Escaping doesn't work "normally" in interpolated strings.

  --Rex

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[Kevin Wright]

That said... there's a proposal to support a $" notation as part of this SIP: https://github.com/scala/scala/pull/4663

Feel free to vote for it in the scala/slip bitter channel!

[Jasper-M]

Then how does escaping work in interpolated strings? Because apparently it does know what escaping is:

scala> s"\"

scala.StringContext$InvalidEscapeException: invalid escape character at index 0 in "\"

    ...

scala> s"\\"

res1: String = \

Can you escape anything other than the escape character?

Best,

Jasper

Op dinsdag 8 september 2015 16:16:39 UTC+2 schreef Rex Kerr:

[Rex Kerr]

The interpolated string parses the escape at runtime (or not, in the case of raw"\\\").  So it's not very helpful for determining compile-time string boundaries.

 --Rex

[Seth Tisue]

This is something of an FAQ. It's https://issues.scala-lang.org/browse/SI-6476