Lazy initialiazation + Tuple extractors

[missingfaktor]

scala> lazy val (a, b) = (2, { println("hgello"); 4 })

a: Int = <lazy>

b: Int = <lazy>

scala> a

hgello

res9: Int = 2

scala> b

res10: Int = 4

Is the above an expected behavior?

I thought I was declaring two lazy values, but apparently, that's not what it does.

--

Cheers,

missingfaktor.

[Dave]

I think the tuple itself is lazy

So when one of elements are called the whole tuple is evaluated.

scala> lazy val (a, b) = (2, { println("hello"); 4 })

a: Int = <lazy>
b: Int = <lazy>

scala> a

hello
res25: Int = 2

scala> lazy val (a, b) = (2, { println("hello"); 4 })

a: Int = <lazy>
b: Int = <lazy>

scala> b
hello
res26: Int = 4

> missingfaktor <http://twitter.com/#!/missingfaktor>.