Just a quick additional question: is the scale linear or what? i.e.
a) S = p1 + p2 + p3
b) S = -10log10(p1) -10log10(p2) -10log10(p3)
c) S = -10log10(p1 + p2 + p3)
d) ??
TY
d
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Davide Cittaro
daweo...@gmail.com
http://sites.google.com/site/davidecittaro/
On Feb 15, 2012, at 6:23 AM, Song, Qiang wrote:Just a quick additional question: is the scale linear or what? i.e.
>
> For each bin, we computed the posterior probability that it is in the
> foreground (ENRICHED) state. The score of a enriched domain is
> therefore the sum of the posterior probabilities of all bins within that
> domain. That is the reason this score has an approximate linear
> relationship with domain length. In order for a domain to have a high score,
> it should be quite big (because we are interested in dispersed domains), and
> each of the underlying bins should have a high posterior probability. By filtering
> those domains with higher score,we are more confident we obtain dispersed
> regions.
a) S = p1 + p2 + p3