Hi Karl,
Thank you for your quick reply— I realize that outbred crosses aren’t your core interest, but may I continue the conversation with a few additional questions?
It's easiest to think of two
crosses involving four inbred lines, AA x BB and CC x DD.
Am I correct that in this scheme AA
and CC have one extreme phenotype (say, large), while BB and CC have the other phenotype
(small)? That would lead to the recombination
between divergent chromosomes in the F1 that you need to map QTL for the trait.
You can use this for a cross between two outbred
individuals, provided that you can reconstruct phase in the two F1 individuals
(the parents of the four-way cross progeny.
Right. So imagine going into an outbred population
of large individuals and picking up an individual that is AC, then going to a
population of small individuals and picking up one that is BD. Then use these as
the parents of the mapping cross.
Parentals: AC x BD
F1: AB, AD, BC, CD. Then cross only AB x CD (since they have all 4 parental alleles).
For any progeny of AB x CD, we know that
A or C came from the large parent, and
B or D came from the small parent
This is essentially the same thing you would get from the AA x CC, BB x DD crosses you described, so I think we are OK so far.
You need to work out phase, which means determining the relationship between alleles at different markers.
This is the same thing as determining which alleles in the F2 came from the large parent(s) of the F1 and which from the small parent(s), correct?
I worked this out for each of my markers from the genotypes of the parentals and the F1, so I’m all set there. But how is the information about phase encoded in the 4way format? It’s easy for a marker with 4 alleles in the F1, because they can immediately be coded as AB and CD. But what about a marker with 3 alleles, one with 2 alleles that segregates like a backcross, or one with two alleles that segregates like an intercross?
Again, forgive my ignorance of inbred lines, but couldn’t these segregation types happen in the 4way cross if some markers in one or both sets of parents are monomorphic. i.e. (AA x BB and AA x DD: F1 cross is AB x AD), (AA x AA and CC x DD: F2 look like backcross) , or (AA x AA and DD x DD: F2 look like intercross)? Are these possibilities and others (plus dominance) why you have genotypes 5-14 in the 4way coding? How would you deal with these possibilities in a 4way cross of inbred lines?
Hopefully, my scheme does the same thing, but maybe coming at it from a different angle. Once we know the phase, it seems like we should be able to use this 4way coding for any segregation type in an outcross if, at each marker, we write the genotypes of our 2 F1 in a stereotyped way that encodes the phase—always put the F1 in the same order in the “cross” (i.e., F1(1) x F1(2), and write their genotypes so that the alleles we put in the A or C position came from the large parental genotype, while alleles in the B or D positions came from the small parental genotype. Thus, in the examples I gave in the original post, by writing a cross (say ef x eg) in a different way for each possible phase, the same F2 genotype (i.e., eg) will get a different code than it will for a marker with 3 alleles where the phase is different and the cross is written as fe x eg. In the first case, eg = AD, while in the second case, eg = BD. If you maintain this convention for all markers, then you know which set of alleles came from the large parent and which set came from the small parent.
By the way, I made a typo in one of my examples in the first post, so here is the corrected version:
Example 2: a backcross segregation type: lm x ll (2 alleles, the first F1 is heterozygous, the second is homozygous)
There are two possible phases for this cross, depending on which parental contributed the m to that first F1:
a. lm x ll (m came from the BD parent of the F1)
F2 are ll = 5 (AC or AD)
lm = 6 (BC or BD)
b. ml x ll (m came from the AC parent)
so F2 are
ml = 5 (AC or AD)
ll = 6 (BC or BD)
Anyway—let me know if you think this scheme will work.
Thanks again,
Sara Via