a question about "string interpolation" in ring

[de...@roo.com.br]

Hi all!

ring have some way and/or operator to expand like $$ in php ?

$ cat test.php

<?php

$name = "earth";
$nameOfPlanet = "name";

echo $nameOfPlanet  . PHP_EOL;
echo $$nameOfPlanet . PHP_EOL;

$ php test.php
name
earth

*  The $x (single dollar) is the normal variable with the name x that stores any value like string, integer, float, etc. The $$x (double dollar) is a reference variable that stores the value which can be accessed by using the $ symbol before the $x value. These are called variable variables in PHP. 

* https://www.geeksforgeeks.org/what-does-dollar-dollar-or-double-dollar-means-in-php/

[Ilir Liburn]

Hello Denis,

no to my knowledge. But you can make function acting as $$ operator like this

$name = "earth"
$nameOfPlanet = "name"

? $nameOfPlanet
? $($nameofplanet)

func $ var
return eval("$"+var)

This will work only for global variables obviously.

Greetings,

Ilir

[Mansour Ayouni]

Hello Denis and Ilir,

In Ring, using SoftanzaLib external code support, it's easy to reproduce nearly the same code as PHP, like this:

All the best,

Mansour

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[Mansour Ayouni]

Hello Denis and Ilir,

And this is a better version where the PHP code is reproduced as is with some parentheses added for convenience with Ring:

Best,

Mansour